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What will be the nature of the equation (x^2+7x+10=0)?

Answer and explanation

Correct answer: Two real and distinct roots

For a quadratic equation ax^2+bx+c=0, the discriminant D=b^2−4ac determines the nature of its roots. Here a=1, b=7 and c=10, so D=7^2−4(1)(10)=49−40=9. Since D is positive, the equation has two real and distinct roots. In fact, factorisation gives x^2+7x+10=(x+5)(x+2), so the roots are −5 and −2, which confirms that they are real and unequal. Option B would require D=0, while option C applies when D<0. A quadratic with real coefficients cannot have only one isolated imaginary root; non-real roots occur as a conjugate pair.

Related tags

Quadratic EquationsDiscriminantNature Of RootsReal Distinct RootsMathematicsClass 10 Mcq

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