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If D = 64, what will be the nature of the roots of the quadratic equation?

Answer and explanation

Correct answer: Two distinct real roots

The governing concept is the discriminant of a quadratic equation. For ax² + bx + c = 0, the discriminant is D = b² − 4ac, and its sign determines the nature of the roots. If D > 0, the equation has two distinct real roots; if D = 0, it has two equal real roots; and if D < 0, it has no real roots. Here D = 64, which is positive, so the equation has two distinct real roots. Therefore option A is correct. Option B would be correct only for D = 0, not for 64. Option C applies when the discriminant is negative. Option D is also incorrect because the positive value of the discriminant gives a definite conclusion without requiring the actual coefficients or solving the equation.

Related tags

Quadratic-EquationsDiscriminantNature-Of-RootsNature Of RootsQuadratic EquationsMathematicsClass 10 Mcq

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