Concept-wise Practice

numerical MCQ Questions for Class 10

numerical se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

3 questions tagged with numerical.

Question 1/3 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि (p(x)=2x-2-8) है तो ग्राफ (x)-अक्ष को किन (x)-मानों पर काटेगा?

If (p(x)=2x-2-8), at which (x)-values will the graph cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. (-2) और (2)(-2) and (2)

Step 1

Concept

From \(2x^2-8=0\), \(x^2=4\). Hence the zeroes are (-2) and (2).

Step 2

Why this answer is correct

The correct answer is A. (-2) और (2) / (-2) and (2). From \(2x^2-8=0\), \(x^2=4\). Hence the zeroes are (-2) and (2).

Step 3

Exam Tip

\(2x^2-8=0\) से \(x^2=4\) मिलता है। इसलिए शून्यक (-2) और (2) हैं।

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Question 2/3 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि (p(x)=x-2-2x-8) है तो ग्राफ (x)-अक्ष को किन बिंदुओं पर मिलेगा?

If (p(x)=x-2-2x-8), at which points will the graph meet the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. ((-2,0)) और ((4,0))((-2,0)) and ((4,0))

Step 1

Concept

(x-2-2x-8=(x-4)(x+2)). So the graph meets the (x)-axis at (x=4) and (x=-2).

Step 2

Why this answer is correct

The correct answer is A. ((-2,0)) और ((4,0)) / ((-2,0)) and ((4,0)). (x-2-2x-8=(x-4)(x+2)). So the graph meets the (x)-axis at (x=4) and (x=-2).

Step 3

Exam Tip

(x-2-2x-8=(x-4)(x+2)) है। अतः (x=4) और (x=-2) पर ग्राफ (x)-अक्ष से मिलेगा।

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Question 3/3 Expert Mathematics Chapter 2: Polynomials Geometrical meaning of the zeroes of a polynomial. Class 10 Level 24

यदि (p(x)=x-2-9) है तो इसका ग्राफ (x)-अक्ष को किन बिंदुओं पर काटेगा?

If (p(x)=x-2-9), at which points will its graph cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. ((-3,0)) और ((3,0))((-3,0)) and ((3,0))

Step 1

Concept

Solving \(x^2-9=0\) gives \(x=\pm3\). Zeroes appear on the (x)-axis as ((x,0)).

Step 2

Why this answer is correct

The correct answer is A. ((-3,0)) और ((3,0)) / ((-3,0)) and ((3,0)). Solving \(x^2-9=0\) gives \(x=\pm3\). Zeroes appear on the (x)-axis as ((x,0)).

Step 3

Exam Tip

\(x^2-9=0\) से \(x=\pm3\) मिलता है। शून्यक हमेशा (x)-अक्ष पर ((x,0)) रूप में दिखते हैं।

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