यदि (x=3) समीकरण \(ax^2-8x+6=0\) का मूल है तो (a) का मान क्या है?
If (x=3) is a root of \(ax^2-8x+6=0\), what is the value of (a)?
Explanation opens after your attempt
A. (2)
Concept
Putting (x=3) gives (9a-24+6=0), so (9a=18) and (a=2). Substitute in questions with an unknown coefficient.
Why this answer is correct
The correct answer is A. (2). Putting (x=3) gives (9a-24+6=0), so (9a=18) and (a=2). Substitute in questions with an unknown coefficient.
Exam Tip
(x=3) रखने पर (9a-24+6=0) इसलिए (9a=18) और (a=2)। अज्ञात गुणांक वाले प्रश्न में प्रतिस्थापन करें।
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