यदि (x=4) समीकरण \(ax^2-10x+8=0\) का मूल है तो (a) का मान क्या है?
If (x=4) is a root of \(ax^2-10x+8=0\), what is the value of (a)?
Explanation opens after your attempt
A. (2)
Concept
Putting (x=4) gives (16a-40+8=0), so (16a=32) and (a=2). Substitute when a coefficient is unknown.
Why this answer is correct
The correct answer is A. (2). Putting (x=4) gives (16a-40+8=0), so (16a=32) and (a=2). Substitute when a coefficient is unknown.
Exam Tip
(x=4) रखने पर (16a-40+8=0) इसलिए (16a=32) और (a=2)। अज्ञात गुणांक में प्रतिस्थापन करें।
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