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2 results found for "discriminant value" in Class 10.
What is the discriminant of \(6x^2-5x+1=0\)?
A. (1)
(D=(-5)2-4(6)(1)=1). This gives two real and distinct roots.
The correct answer is A. (1). (D=(-5)2-4(6)(1)=1). This gives two real and distinct roots.
(D=(-5)2-4(6)(1)=1) है। इससे दो वास्तविक और असमान मूल होंगे।
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What is the value of the discriminant for \(2x^2-3x+1=0\)?
A. (1)
The value is (D=(-3)2-4(2)(1)=1). A positive discriminant gives distinct real roots.
The correct answer is A. (1). The value is (D=(-3)2-4(2)(1)=1). A positive discriminant gives distinct real roots.
(D=(-3)2-4(2)(1)=1) है। धनात्मक विविक्तकर असमान वास्तविक मूल देता है।
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