If (x^2-2(k-4)x+k^2-25=0) has equal roots, what is the value of (k)?

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Answer and explanation

Correct answer: (k=\frac{41}{8})

For equal roots, (D=0), so ((k-4)^2=k^2-25) and (k=\frac{41}{8}). In exams, handle constant terms carefully while expanding squares.

What is the correct answer to this question?

(k=\frac{41}{8})

Why is this the correct answer?

For equal roots, (D=0), so ((k-4)^2=k^2-25) and (k=\frac{41}{8}). In exams, handle constant terms carefully while expanding squares.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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