Concept-wise Practice

identify MCQ Questions for Class 10

identify se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

All Tags Search Similar

Practice Questions

10 questions tagged with identify.

Question 1/10 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

किस समीकरण का विवेचक (-47) है?

Which equation has discriminant (-47)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+x+12=0\)

Step 1

Concept

For \(x^2+x+12=0\), \(D=1^2-4\cdot1\cdot12=-47\). Subtract the full (4ac) in the discriminant.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+x+12=0\). For \(x^2+x+12=0\), \(D=1^2-4\cdot1\cdot12=-47\). Subtract the full (4ac) in the discriminant.

Step 3

Exam Tip

\(x^2+x+12=0\) के लिए \(D=1^2-4\cdot1\cdot12=-47\) है। विवेचक में (4ac) पूरा घटाएं।

Open Question Page
Ask Friends
Question 2/10 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

किस समीकरण का विवेचक (-35) है?

Which equation has discriminant (-35)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+x+9=0\)

Step 1

Concept

For \(x^2+x+9=0\), \(D=1^2-4\cdot1\cdot9=-35\). Subtract the full (4ac) in the discriminant.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+x+9=0\). For \(x^2+x+9=0\), \(D=1^2-4\cdot1\cdot9=-35\). Subtract the full (4ac) in the discriminant.

Step 3

Exam Tip

\(x^2+x+9=0\) के लिए \(D=1^2-4\cdot1\cdot9=-35\) है। विवेचक में (4ac) पूरा घटाएं।

Open Question Page
Ask Friends
Question 3/10 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

किस समीकरण का विवेचक (-23) है?

Which equation has discriminant (-23)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+x+6=0\)

Step 1

Concept

For \(x^2+x+6=0\), \(D=1^2-4\cdot1\cdot6=-23\). Subtract the full (4ac) in the discriminant.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+x+6=0\). For \(x^2+x+6=0\), \(D=1^2-4\cdot1\cdot6=-23\). Subtract the full (4ac) in the discriminant.

Step 3

Exam Tip

\(x^2+x+6=0\) के लिए \(D=1^2-4\cdot1\cdot6=-23\) है। विवेचक में (4ac) पूरा घटाएं।

Open Question Page
Ask Friends
Question 4/10 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

किस समीकरण का विवेचक (-11) है?

Which equation has discriminant (-11)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+x+3=0\)

Step 1

Concept

For \(x^2+x+3=0\), \(D=1^2-4\cdot1\cdot3=-11\). Subtract the full (4ac) while finding the discriminant.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+x+3=0\). For \(x^2+x+3=0\), \(D=1^2-4\cdot1\cdot3=-11\). Subtract the full (4ac) while finding the discriminant.

Step 3

Exam Tip

\(x^2+x+3=0\) के लिए \(D=1^2-4\cdot1\cdot3=-11\) है। विवेचक निकालते समय (4ac) पूरा घटाएं।

Open Question Page
Ask Friends
Question 5/10 Hard Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

किस समीकरण का विवेचक (-15) है?

Which equation has discriminant (-15)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+x+4=0\)

Step 1

Concept

For \(x^2+x+4=0\), \(D=1^2-4\cdot1\cdot4=-15\). Subtract the full (4ac) while finding the discriminant.

Step 2

Why this answer is correct

The correct answer is A. \(x^2+x+4=0\). For \(x^2+x+4=0\), \(D=1^2-4\cdot1\cdot4=-15\). Subtract the full (4ac) while finding the discriminant.

Step 3

Exam Tip

\(x^2+x+4=0\) के लिए \(D=1^2-4\cdot1\cdot4=-15\) है। विवेचक निकालते समय (4ac) पूरा घटाएं।

Open Question Page
Ask Friends
Question 6/10 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

किस विकल्प में स्थिर पद अनुपस्थित है लेकिन समीकरण द्विघात है?

In which option is the constant term absent but the equation is quadratic?

Explanation opens after your attempt
Correct Answer

A. \(2x^2+7x=0\)

Step 1

Concept

In \(2x^2+7x=0\), the \(x^2\) term is present and the constant term is absent. An equation can be quadratic even without a constant term.

Step 2

Why this answer is correct

The correct answer is A. \(2x^2+7x=0\). In \(2x^2+7x=0\), the \(x^2\) term is present and the constant term is absent. An equation can be quadratic even without a constant term.

Step 3

Exam Tip

\(2x^2+7x=0\) में \(x^2\) पद है और स्थिर पद अनुपस्थित है। स्थिर पद न होने पर भी समीकरण द्विघात हो सकता है।

Open Question Page
Ask Friends
Question 7/10 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

कौन-सा समीकरण द्विघात है लेकिन अभी मानक रूप में नहीं है?

Which equation is quadratic but not yet in standard form?

Explanation opens after your attempt
Correct Answer

B. \(4x^2+1=3x\)

Step 1

Concept

\(4x^2+1=3x\) can be written as \(4x^2-3x+1=0\). In standard form, all terms are on one side and (0) is on the other.

Step 2

Why this answer is correct

The correct answer is B. \(4x^2+1=3x\). \(4x^2+1=3x\) can be written as \(4x^2-3x+1=0\). In standard form, all terms are on one side and (0) is on the other.

Step 3

Exam Tip

\(4x^2+1=3x\) को \(4x^2-3x+1=0\) लिखा जा सकता है। मानक रूप में सभी पद एक ओर और दूसरी ओर (0) होता है।

Open Question Page
Ask Friends
Question 8/10 Medium Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

कौन-सा समीकरण द्विघात है लेकिन मानक रूप में नहीं लिखा गया है?

Which equation is quadratic but not written in standard form?

Explanation opens after your attempt
Correct Answer

B. \(x^2=5x-4\)

Step 1

Concept

\(x^2=5x-4\) can be written as \(x^2-5x+4=0\), so it is quadratic. In standard form, the right side must be (0).

Step 2

Why this answer is correct

The correct answer is B. \(x^2=5x-4\). \(x^2=5x-4\) can be written as \(x^2-5x+4=0\), so it is quadratic. In standard form, the right side must be (0).

Step 3

Exam Tip

\(x^2=5x-4\) को \(x^2-5x+4=0\) बनाया जा सकता है, इसलिए यह द्विघात है। मानक रूप में दायां पक्ष (0) होना चाहिए।

Open Question Page
Ask Friends
Question 9/10 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

क्या \(2x^2=0\) एक द्विघात समीकरण है?

Is \(2x^2=0\) a quadratic equation?

Explanation opens after your attempt
Correct Answer

D. हाँ क्योंकि \(x^2\) का गुणांक (2) हैYes because the coefficient of \(x^2\) is (2)

Step 1

Concept

In \(2x^2=0\), the coefficient of \(x^2\) is \(2\neq 0\). It can be quadratic even without linear and constant terms.

Step 2

Why this answer is correct

The correct answer is D. हाँ क्योंकि \(x^2\) का गुणांक (2) है / Yes because the coefficient of \(x^2\) is (2). In \(2x^2=0\), the coefficient of \(x^2\) is \(2\neq 0\). It can be quadratic even without linear and constant terms.

Step 3

Exam Tip

\(2x^2=0\) में \(x^2\) का गुणांक \(2\neq 0\) है। रैखिक और स्थिर पद न होने पर भी यह द्विघात हो सकता है।

Open Question Page
Ask Friends
Question 10/10 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

निम्न में से (y) में द्विघात समीकरण कौन-सा है?

Which of the following is a quadratic equation in (y)?

Explanation opens after your attempt
Correct Answer

A. \(2y^2-3y+1=0\)

Step 1

Concept

The highest power of (y) is (2), so it is quadratic in (y). The variable may be different, but the degree must be (2).

Step 2

Why this answer is correct

The correct answer is A. \(2y^2-3y+1=0\). The highest power of (y) is (2), so it is quadratic in (y). The variable may be different, but the degree must be (2).

Step 3

Exam Tip

चर (y) की सबसे बड़ी घात (2) है इसलिए यह (y) में द्विघात है। चर कोई भी हो सकता है पर घात (2) होनी चाहिए।

Open Question Page
Ask Friends

identify Revision Links

All MCQ Tags

Browse concept directory

All Subjects

Subject-wise practice

Search identify

More keyword results