In \(x^2-36=0\), (b=0), so the sum of roots is \(-\frac{b}{a}=0\). If the (x) term is absent, the sum can be (0).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-36=0\). In \(x^2-36=0\), (b=0), so the sum of roots is \(-\frac{b}{a}=0\). If the (x) term is absent, the sum can be (0).
Step 3
Exam Tip
\(x^2-36=0\) में (b=0), इसलिए मूलों का योग \(-\frac{b}{a}=0\) है। (x) पद अनुपस्थित हो तो योग (0) हो सकता है।
In \(3x^2-27=0\), the \(x^2\) term is present and the (x) term is absent. An equation can be quadratic even without the (x) term.
Step 2
Why this answer is correct
The correct answer is A. \(3x^2-27=0\). In \(3x^2-27=0\), the \(x^2\) term is present and the (x) term is absent. An equation can be quadratic even without the (x) term.
Step 3
Exam Tip
\(3x^2-27=0\) में \(x^2\) पद है और (x) पद अनुपस्थित है। (x) पद न होने पर भी समीकरण द्विघात हो सकता है।
In \(x^2-49=0\), the \(x^2\) term is present and the (x) term is absent. An equation can be quadratic even without an (x) term.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-49=0\). In \(x^2-49=0\), the \(x^2\) term is present and the (x) term is absent. An equation can be quadratic even without an (x) term.
Step 3
Exam Tip
\(x^2-49=0\) में \(x^2\) पद है और (x) पद अनुपस्थित है। (x) पद न होने पर भी समीकरण द्विघात हो सकता है।
D. हाँ क्योंकि \(x^2\) का गुणांक (2) है/Yes because the coefficient of \(x^2\) is (2)
Step 1
Concept
In \(2x^2=0\), the coefficient of \(x^2\) is \(2\neq 0\). It can be quadratic even without linear and constant terms.
Step 2
Why this answer is correct
The correct answer is D. हाँ क्योंकि \(x^2\) का गुणांक (2) है / Yes because the coefficient of \(x^2\) is (2). In \(2x^2=0\), the coefficient of \(x^2\) is \(2\neq 0\). It can be quadratic even without linear and constant terms.
Step 3
Exam Tip
\(2x^2=0\) में \(x^2\) का गुणांक \(2\neq 0\) है। रैखिक और स्थिर पद न होने पर भी यह द्विघात हो सकता है।
