If the correct (k) is needed for equal roots of (x^2-2(k+3)x+k^2-16=0), which value is correct?

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Correct answer: (k=-\frac{25}{6})

(D=4(k+3)^2-4(k^2-16)=0) gives ((k+3)^2=k^2-16), so (6k+25=0) and (k=-\frac{25}{6}). In exams, handle the constant term carefully after expansion.

What is the correct answer to this question?

(k=-\frac{25}{6})

Why is this the correct answer?

(D=4(k+3)^2-4(k^2-16)=0) gives ((k+3)^2=k^2-16), so (6k+25=0) and (k=-\frac{25}{6}). In exams, handle the constant term carefully after expansion.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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