If both zeroes of (p(x)=x^2+rx+9) are equal and negative, what is the value of (r)?

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Answer and explanation

Correct answer: (6)

For equal zeroes, (r^2-36=0), so (r=\pm6). For negative zeroes the sum must be positive (6), hence (r=6).

What is the correct answer to this question?

(6)

Why is this the correct answer?

For equal zeroes, (r^2-36=0), so (r=\pm6). For negative zeroes the sum must be positive (6), hence (r=6).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.

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