What is the discriminant \(D\) of the equation \(x^2-2x-1=0\)?समीकरण \(x^2-2x-1=0\) का विविक्तकर \(D\) कितना है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 88
For \(ax^2+bx+c=0\), the discriminant is \(D=b^2-4ac\). Here, \(a=1\), \(b=-2\), and \(c=-1\), so \(D=(-2)^2-4(1)(-1)=4+4=8\).\(ax^2+bx+c=0\) का विविक्तकर \(D=b^2-4ac\) होता है। यहाँ \(a=1\), \(b=-2\) और \(c=-1\) हैं, इसलिए \(D=(-2)^2-4(1)(-1)=4+4=8\)।
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.