If the discriminant of a quadratic equation is \(D=(r-2)^2-9\), which interval of \(r\) results in no real roots?

Correct answer: \(-1<r<5\)

A quadratic equation has no real roots when its discriminant satisfies \(D<0\). Thus, \((r-2)^2-9<0\), or \((r-2)^2<9\). This gives \(-3<r-2<3\), and hence \(-1<r<5\). At the endpoints \(r=-1\) and \(r=5\), \(D=0\), so the equation has one repeated real root; therefore option C is not correct. Exam tip: use \(D<0\) for no real roots, \(D=0\) for equal real roots, and \(D>0\) for two distinct real roots.