0 reads0 ratings0 helpful
If (x^2-2(k-5)x+k^2-36=0) has equal roots, what is the value of (k)?यदि (x^2-2(k-5)x+k^2-36=0) के मूल समान हों, तो (k) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (k=\frac{61}{10})(k=\frac{61}{10})
For equal roots, (D=0), so ((k-5)^2=k^2-36) and (k=\frac{61}{10}). In exams, handle constant terms carefully while expanding squares.समान मूलों के लिए (D=0), इसलिए ((k-5)^2=k^2-36) और (k=\frac{61}{10}) है। परीक्षा में वर्ग फैलाते समय स्थिर पद ध्यान से लें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
