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Class 10MathematicsQuadratic EquationsNature of RootsEasy
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Find the value of the discriminant \(\Delta\) for the equation \(2x^2-3x+1=0\).

Answer and explanation

Correct answer: \(\Delta=1\)

For \(ax^2+bx+c=0\), \(\Delta=b^2-4ac\). Here \(a=2,\;b=-3,\;c=1\). So \(\Delta=(-3)^2-4(2)(1)=9-8=1\).

Related tags

Quadratic EquationsDiscriminantNature Of RootsFormula
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