If (x^2-2(k+1)x+k^2=0) has equal roots, what is the value of (k)?

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Answer and explanation

Correct answer: (k=-\frac{1}{2})

For equal roots, (D=0), so (4(k+1)^2-4k^2=0) gives (2k+1=0). In exams, write (D) first in parameter questions.

What is the correct answer to this question?

(k=-\frac{1}{2})

Why is this the correct answer?

For equal roots, (D=0), so (4(k+1)^2-4k^2=0) gives (2k+1=0). In exams, write (D) first in parameter questions.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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