समीकरण \(6x^2-5x+1=0\) का विविक्तकर क्या है?
What is the discriminant of \(6x^2-5x+1=0\)?
Explanation opens after your attempt
A. (1)
Concept
(D=(-5)2-4(6)(1)=1). This gives two real and distinct roots.
Why this answer is correct
The correct answer is A. (1). (D=(-5)2-4(6)(1)=1). This gives two real and distinct roots.
Exam Tip
(D=(-5)2-4(6)(1)=1) है। इससे दो वास्तविक और असमान मूल होंगे।
Login to save your score, XP, coins and progress.