Substituting (x=0) in \(4x^3-7x\) gives (0), and it is not the zero polynomial. For (x=0), the constant term must be (0).
Step 2
Why this answer is correct
The correct answer is B. \(4x^3-7x\). Substituting (x=0) in \(4x^3-7x\) gives (0), and it is not the zero polynomial. For (x=0), the constant term must be (0).
Step 3
Exam Tip
\(4x^3-7x\) में (x=0) रखने पर (0) मिलता है और यह शून्य बहुपद नहीं है। (x=0) के लिए अचर पद (0) होना चाहिए।
The sum of zeroes is (2), so the other zero is (2-\(1+\sqrt{3}\)=1-\sqrt{3}). With rational coefficients, the conjugate also appears.
Step 2
Why this answer is correct
The correct answer is A. \(1-\sqrt{3}\). The sum of zeroes is (2), so the other zero is (2-\(1+\sqrt{3}\)=1-\sqrt{3}). With rational coefficients, the conjugate also appears.
Step 3
Exam Tip
शून्यकों का योग (2) है, इसलिए दूसरा शून्यक (2-\(1+\sqrt{3}\)=1-\sqrt{3}) है। परिमेय गुणांकों में संयुग्मी भी मिलता है।
A. दूसरा (7), कटान ((6,0)), ((7,0))/Other (7), intersections ((6,0)), ((7,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (13), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (7), कटान ((6,0)), ((7,0)) / Other (7), intersections ((6,0)), ((7,0)). In the quadratic, the sum of zeroes is (13), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (13) है, इसलिए दूसरा शून्यक (7) है। टिप: शून्यक को ((x,0)) में बदलें।
The average of the two zeroes is (5), so the other zero is (11). Tip: the axis of symmetry passes through the midpoint of zeroes.
Step 2
Why this answer is correct
The correct answer is A. (11). The average of the two zeroes is (5), so the other zero is (11). Tip: the axis of symmetry passes through the midpoint of zeroes.
Step 3
Exam Tip
दो शून्यकों का औसत (5) है इसलिए दूसरा शून्यक (11) होगा। टिप: सममिति अक्ष शून्यकों के मध्य से गुजरता है।
A. दूसरा (7), कटान ((4,0)), ((7,0))/Other (7), intersections ((4,0)), ((7,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (11), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (7), कटान ((4,0)), ((7,0)) / Other (7), intersections ((4,0)), ((7,0)). In the quadratic, the sum of zeroes is (11), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (11) है, इसलिए दूसरा शून्यक (7) है। टिप: शून्यक को ((x,0)) में बदलें।
The average of the two zeroes is (-2), so the other zero is (-9). Tip: connect the axis of symmetry with the midpoint of zeroes.
Step 2
Why this answer is correct
The correct answer is A. (-9). The average of the two zeroes is (-2), so the other zero is (-9). Tip: connect the axis of symmetry with the midpoint of zeroes.
Step 3
Exam Tip
दो शून्यकों का औसत (-2) है, इसलिए दूसरा शून्यक (-9) होगा। टिप: सममिति अक्ष को शून्यकों के मध्य से जोड़ें।
A. दूसरा (5), कटान ((4,0)), ((5,0))/Other (5), intersections ((4,0)), ((5,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (9), so the other zero is (5). Tip: quickly convert a zero to ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (5), कटान ((4,0)), ((5,0)) / Other (5), intersections ((4,0)), ((5,0)). In the quadratic, the sum of zeroes is (9), so the other zero is (5). Tip: quickly convert a zero to ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (9) है इसलिए दूसरा शून्यक (5) है। टिप: शून्यक को तुरंत ((x,0)) में बदलें।
The average of the two zeroes is (3), so the other zero is (-5). Tip: set \(\frac{a+b}{2}\) equal to the axis of symmetry.
Step 2
Why this answer is correct
The correct answer is A. (-5). The average of the two zeroes is (3), so the other zero is (-5). Tip: set \(\frac{a+b}{2}\) equal to the axis of symmetry.
Step 3
Exam Tip
दो शून्यकों का औसत (3) है इसलिए दूसरा शून्यक (-5) होगा। टिप: \(\frac{a+b}{2}\) को सममिति अक्ष के बराबर रखें।
The average of the two zeroes is (4), so the other zero is (10). Tip: connect the axis of symmetry with the midpoint of zeroes.
Step 2
Why this answer is correct
The correct answer is A. (10). The average of the two zeroes is (4), so the other zero is (10). Tip: connect the axis of symmetry with the midpoint of zeroes.
Step 3
Exam Tip
दोनों शून्यकों का औसत (4) है इसलिए दूसरा शून्यक (10) होगा। टिप: सममिति अक्ष को शून्यकों के मध्य मान से जोड़ें।
A. दूसरा (4), कटान ((3,0)), ((4,0))/Other (4), intersections ((3,0)), ((4,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (7), so the other zero is (4). Tip: quickly convert a zero to ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (4), कटान ((3,0)), ((4,0)) / Other (4), intersections ((3,0)), ((4,0)). In the quadratic, the sum of zeroes is (7), so the other zero is (4). Tip: quickly convert a zero to ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (7) है, इसलिए दूसरा शून्यक (4) है। टिप: शून्यक को तुरंत ((x,0)) में बदलें।
The average of the two zeroes is (2), so the other zero is (-5). Tip: set \( \frac{a+b}{2} \) equal to the axis of symmetry.
Step 2
Why this answer is correct
The correct answer is A. (-5). The average of the two zeroes is (2), so the other zero is (-5). Tip: set \( \frac{a+b}{2} \) equal to the axis of symmetry.
Step 3
Exam Tip
दो शून्यकों का औसत (2) है, इसलिए दूसरा शून्यक (-5) होगा। टिप: \( \frac{a+b}{2} \) को सममिति अक्ष के बराबर रखें।
The average of the two zeroes is (1), so the other zero is (7). Tip: the axis of symmetry passes through the midpoint of zeroes.
Step 2
Why this answer is correct
The correct answer is C. (7). The average of the two zeroes is (1), so the other zero is (7). Tip: the axis of symmetry passes through the midpoint of zeroes.
Step 3
Exam Tip
दो शून्यकों का औसत (1) होगा इसलिए दूसरा शून्यक (7) है। टिप: सममिति अक्ष शून्यकों के मध्य से गुजरता है।
A. दूसरा (3), कटान ((2,0)), ((3,0))/Other (3), intersections ((2,0)), ((3,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (5), so the other zero is (3). Tip: immediately convert a zero to ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (3), कटान ((2,0)), ((3,0)) / Other (3), intersections ((2,0)), ((3,0)). In the quadratic, the sum of zeroes is (5), so the other zero is (3). Tip: immediately convert a zero to ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (5) है, इसलिए दूसरा शून्यक (3) है। टिप: शून्यक को तुरंत ((x,0)) में बदलें।
For a quadratic with rational coefficients, if \(a+\sqrt{b}\) is a zero then \(a-\sqrt{b}\) is also a zero. The conjugate-root rule is useful in exams.
Step 2
Why this answer is correct
The correct answer is A. \(2-\sqrt{3}\). For a quadratic with rational coefficients, if \(a+\sqrt{b}\) is a zero then \(a-\sqrt{b}\) is also a zero. The conjugate-root rule is useful in exams.
Step 3
Exam Tip
परिमेय गुणांकों वाले द्विघात में \(a+\sqrt{b}\) के साथ \(a-\sqrt{b}\) भी शून्यक होता है। परीक्षा में संयुग्मी मूल का नियम उपयोगी है।
A. दूसरा \(\sqrt{5}\), \(k=\sqrt{5}\)/Other \(\sqrt{5}\), \(k=\sqrt{5}\)
Step 1
Concept
The product is (5), so the other zero is \(\frac{5}{\sqrt{5}}=\sqrt{5}\). The sum is \(2\sqrt{5}=2k\), hence \(k=\sqrt{5}\).
Step 2
Why this answer is correct
The correct answer is A. दूसरा \(\sqrt{5}\), \(k=\sqrt{5}\) / Other \(\sqrt{5}\), \(k=\sqrt{5}\). The product is (5), so the other zero is \(\frac{5}{\sqrt{5}}=\sqrt{5}\). The sum is \(2\sqrt{5}=2k\), hence \(k=\sqrt{5}\).
Step 3
Exam Tip
गुणनफल (5) है, इसलिए दूसरा शून्यक \(\frac{5}{\sqrt{5}}=\sqrt{5}\) होगा। योग \(2\sqrt{5}=2k\), अतः \(k=\sqrt{5}\) है।
(p(x)=\(x+\sqrt{5}\)2), so the zero is \(-\sqrt{5}\) twice. A perfect-square form gives a repeated zero.
Step 2
Why this answer is correct
The correct answer is A. \(-\sqrt{5}\) दो बार / \(-\sqrt{5}\) twice. (p(x)=\(x+\sqrt{5}\)2), so the zero is \(-\sqrt{5}\) twice. A perfect-square form gives a repeated zero.
Step 3
Exam Tip
(p(x)=\(x+\sqrt{5}\)2), इसलिए शून्यक \(-\sqrt{5}\) दो बार है। पूर्ण वर्ग रूप से दोहराया शून्यक मिलता है।
A. न तो काटेगा न छुएगा/It will neither cut nor touch it
Step 1
Concept
A real zero appears when the graph meets the (x)-axis. With no real zero, the graph will not meet the (x)-axis.
Step 2
Why this answer is correct
The correct answer is A. न तो काटेगा न छुएगा / It will neither cut nor touch it. A real zero appears when the graph meets the (x)-axis. With no real zero, the graph will not meet the (x)-axis.
Step 3
Exam Tip
वास्तविक शून्यक (x)-अक्ष से मिलने पर दिखता है। कोई वास्तविक शून्यक न होने पर ग्राफ (x)-अक्ष से नहीं मिलेगा।
One real zero means the graph meets the (x)-axis at only one point. For a parabola, this is usually the touching case.
Step 2
Why this answer is correct
The correct answer is A. एक बिंदु पर छुएगा / It will touch at one point. One real zero means the graph meets the (x)-axis at only one point. For a parabola, this is usually the touching case.
Step 3
Exam Tip
एक वास्तविक शून्यक का अर्थ है ग्राफ (x)-अक्ष से केवल एक बिंदु पर मिलता है। परवलय में यह सामान्यतः छूने की स्थिति होती है।
A. जब उसका ग्राफ (x)-अक्ष को न छुए और न काटे/When its graph neither touches nor cuts the (x)-axis
Step 1
Concept
For real zeroes, the graph must meet the (x)-axis. If it does not meet the (x)-axis, there is no real zero.
Step 2
Why this answer is correct
The correct answer is A. जब उसका ग्राफ (x)-अक्ष को न छुए और न काटे / When its graph neither touches nor cuts the (x)-axis. For real zeroes, the graph must meet the (x)-axis. If it does not meet the (x)-axis, there is no real zero.
Step 3
Exam Tip
वास्तविक शून्यक के लिए ग्राफ का (x)-अक्ष से मिलना जरूरी है। यदि ग्राफ (x)-अक्ष से नहीं मिलता, तो कोई वास्तविक शून्यक नहीं होगा।
The other zero is (8), and the average is \(\frac{-10+8}{2}=-1\). Tip: the axis of symmetry is the average of two zeroes.
Step 2
Why this answer is correct
The correct answer is A. (x=-1). The other zero is (8), and the average is \(\frac{-10+8}{2}=-1\). Tip: the axis of symmetry is the average of two zeroes.
Step 3
Exam Tip
दूसरा शून्यक (8) है और औसत \(\frac{-10+8}{2}=-1\) है। टिप: सममिति अक्ष दो शून्यकों का औसत है।
The other zero is (4), and the average is \(\frac{-8+4}{2}=-2\). Tip: the axis of symmetry is the average of two zeroes.
Step 2
Why this answer is correct
The correct answer is A. (x=-2). The other zero is (4), and the average is \(\frac{-8+4}{2}=-2\). Tip: the axis of symmetry is the average of two zeroes.
Step 3
Exam Tip
दूसरा शून्यक (4) है और औसत \(\frac{-8+4}{2}=-2\) है। टिप: सममिति अक्ष दो शून्यकों का औसत है।
The average of the two zeroes is (2), so the other zero is (7). Tip: in a parabola the axis of symmetry passes through the midpoint of the zeroes.
Step 2
Why this answer is correct
The correct answer is A. (7). The average of the two zeroes is (2), so the other zero is (7). Tip: in a parabola the axis of symmetry passes through the midpoint of the zeroes.
Step 3
Exam Tip
दो शून्यकों का औसत (2) होगा, इसलिए दूसरा शून्यक (7) है। टिप: परवलय में सममिति अक्ष शून्यकों के मध्य से गुजरता है।
At a zero, the polynomial value is (0). While reading a graph, look for points where (y=0).
Step 2
Why this answer is correct
The correct answer is A. बहुपद का मान / Value of the polynomial. At a zero, the polynomial value is (0). While reading a graph, look for points where (y=0).
Step 3
Exam Tip
शून्यक पर बहुपद का मान (0) होता है। ग्राफ पढ़ते समय (y=0) वाले बिंदु देखें।
From (4x+6=0), \(x=-\frac{3}{2}\), which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.
Step 2
Why this answer is correct
The correct answer is A. (-2) और (-1) / (-2) and (-1). From (4x+6=0), \(x=-\frac{3}{2}\), which lies between (-2) and (-1). In exams, identify the interval of a negative fraction carefully.
Step 3
Exam Tip
(4x+6=0) से \(x=-\frac{3}{2}\), जो (-2) और (-1) के बीच है। परीक्षा में ऋणात्मक भिन्न का अंतराल सावधानी से पहचानें।
From (3x-7=0), \(x=\frac{7}{3}\), which lies between (2) and (3). In exams, first find the zero and then locate it.
Step 2
Why this answer is correct
The correct answer is B. (2) और (3) / (2) and (3). From (3x-7=0), \(x=\frac{7}{3}\), which lies between (2) and (3). In exams, first find the zero and then locate it.
Step 3
Exam Tip
(3x-7=0) से \(x=\frac{7}{3}\), जो (2) और (3) के बीच है। परीक्षा में पहले शून्यक निकालें फिर स्थान तय करें।
The zero (-5) is negative, so it lies to the left of (0). In exams, the sign of the zero tells its direction.
Step 2
Why this answer is correct
The correct answer is B. (0) के बाईं ओर / To the left of (0). The zero (-5) is negative, so it lies to the left of (0). In exams, the sign of the zero tells its direction.
Step 3
Exam Tip
शून्यक (-5) ऋणात्मक है इसलिए वह (0) के बाईं ओर होगा। परीक्षा में शून्यक का चिह्न उसकी दिशा बताता है।
With rational coefficients \(a+\sqrt{b}\) is accompanied by \(a-\sqrt{b}\). In exams identify conjugate zeroes quickly.
Step 2
Why this answer is correct
The correct answer is A. \(4-\sqrt{11}\). With rational coefficients \(a+\sqrt{b}\) is accompanied by \(a-\sqrt{b}\). In exams identify conjugate zeroes quickly.
Step 3
Exam Tip
परिमेय गुणांकों में \(a+\sqrt{b}\) के साथ \(a-\sqrt{b}\) भी शून्यक होता है। परीक्षा में संयुग्मी शून्यक तुरंत पहचानें।
The companion zero is \(5-2\sqrt{6}\), with sum (10) and product (25-24=1). In exams form the polynomial using the conjugate.
Step 2
Why this answer is correct
The correct answer is A. \(x^2-10x+1\). The companion zero is \(5-2\sqrt{6}\), with sum (10) and product (25-24=1). In exams form the polynomial using the conjugate.
Step 3
Exam Tip
साथी शून्यक \(5-2\sqrt{6}\) होगा, योग (10) और गुणनफल (25-24=1) है। परीक्षा में संयुग्मी लेकर बहुपद बनाएं।
With rational coefficients, \(a+\sqrt{b}\) is accompanied by \(a-\sqrt{b}\). In exams identify conjugate zeroes quickly.
Step 2
Why this answer is correct
The correct answer is A. \(2-\sqrt{7}\). With rational coefficients, \(a+\sqrt{b}\) is accompanied by \(a-\sqrt{b}\). In exams identify conjugate zeroes quickly.
Step 3
Exam Tip
परिमेय गुणांकों में \(a+\sqrt{b}\) के साथ \(a-\sqrt{b}\) भी शून्यक आता है। परीक्षा में संयुग्मी शून्यकों को तुरंत पहचानें।
For rational coefficients, irrational zeroes usually occur in conjugate pairs. Hence the companion zero of \(3-\sqrt{5}\) is \(3+\sqrt{5}\).
Step 2
Why this answer is correct
The correct answer is A. \(3+\sqrt{5}\). For rational coefficients, irrational zeroes usually occur in conjugate pairs. Hence the companion zero of \(3-\sqrt{5}\) is \(3+\sqrt{5}\).
Step 3
Exam Tip
परिमेय गुणांकों में अपरिमेय शून्यक सामान्यतः संयुग्मी रूप में आते हैं। इसलिए \(3-\sqrt{5}\) का साथी शून्यक \(3+\sqrt{5}\) होगा।
With rational coefficients, the conjugate of the irrational part is also a zero. Hence \(\frac{3-\sqrt{5}}{2}\) is the other zero.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{3-\sqrt{5}}{2}\). With rational coefficients, the conjugate of the irrational part is also a zero. Hence \(\frac{3-\sqrt{5}}{2}\) is the other zero.
Step 3
Exam Tip
परिमेय गुणांकों में अपरिमेय भाग का संयुग्मी भी शून्यक होता है। इसलिए \(\frac{3-\sqrt{5}}{2}\) दूसरा शून्यक है।
With rational coefficients, the conjugate of an irrational zero is also a zero. So \(2-\sqrt{3}\) will be the other zero.
Step 2
Why this answer is correct
The correct answer is A. \(2-\sqrt{3}\). With rational coefficients, the conjugate of an irrational zero is also a zero. So \(2-\sqrt{3}\) will be the other zero.
Step 3
Exam Tip
परिमेय गुणांकों में अपरिमेय शून्यक का संयुग्मी भी शून्यक होता है। इसलिए \(2-\sqrt{3}\) दूसरा शून्यक होगा।
Both zeroes are \(\sqrt{3}\), so the sum is \(2\sqrt{3}\). In \(x^2+kx+3\), the sum is (-k), hence \(k=-2\sqrt{3}\).
Step 2
Why this answer is correct
The correct answer is A. \(-2\sqrt{3}\). Both zeroes are \(\sqrt{3}\), so the sum is \(2\sqrt{3}\). In \(x^2+kx+3\), the sum is (-k), hence \(k=-2\sqrt{3}\).
Step 3
Exam Tip
दोनों शून्यक \(\sqrt{3}\) हैं, इसलिए योग \(2\sqrt{3}\) है। \(x^2+kx+3\) में योग (-k) है, अतः \(k=-2\sqrt{3}\)।
For a quadratic with rational coefficients, \(a-\sqrt{b}\) accompanies \(a+\sqrt{b}\). Remember this as the conjugate-zero rule.
Step 2
Why this answer is correct
The correct answer is A. \(3-\sqrt{5}\). For a quadratic with rational coefficients, \(a-\sqrt{b}\) accompanies \(a+\sqrt{b}\). Remember this as the conjugate-zero rule.
Step 3
Exam Tip
परिमेय गुणांकों वाले द्विघात में \(a+\sqrt{b}\) के साथ \(a-\sqrt{b}\) भी शून्यक होता है। परीक्षा में इसे संयुग्मी शून्यक नियम की तरह याद रखें।
B. ग्राफ ((0,0)) से गुजरता है/The graph passes through ((0,0))
Step 1
Concept
(0) is a zero when (p(0)=0). Tip: passing through the origin shows zero as a zero.
Step 2
Why this answer is correct
The correct answer is B. ग्राफ ((0,0)) से गुजरता है / The graph passes through ((0,0)). (0) is a zero when (p(0)=0). Tip: passing through the origin shows zero as a zero.
Step 3
Exam Tip
(0) शून्यक तब है जब (p(0)=0) हो। टिप: मूल बिंदु से गुजरना (0) शून्यक बताता है।
B. जब उसका ग्राफ (x)-अक्ष के समांतर और ऊपर हो/When its graph is parallel to and above the (x)-axis
Step 1
Concept
A line parallel to and above the (x)-axis does not meet the (x)-axis. Tip: such a graph behaves like a non-zero constant polynomial.
Step 2
Why this answer is correct
The correct answer is B. जब उसका ग्राफ (x)-अक्ष के समांतर और ऊपर हो / When its graph is parallel to and above the (x)-axis. A line parallel to and above the (x)-axis does not meet the (x)-axis. Tip: such a graph behaves like a non-zero constant polynomial.
Step 3
Exam Tip
(x)-अक्ष के समांतर ऊपर रेखा (x)-अक्ष से नहीं मिलती। टिप: ऐसा ग्राफ अशून्य स्थिर बहुपद जैसा होता है।
B. जो (x)-अक्ष को एक ही बिंदु पर स्पर्श करे/One that touches the (x)-axis at only one point
Step 1
Concept
One touching point gives one real zero. Tip: zeroes depend on meeting the (x)-axis.
Step 2
Why this answer is correct
The correct answer is B. जो (x)-अक्ष को एक ही बिंदु पर स्पर्श करे / One that touches the (x)-axis at only one point. One touching point gives one real zero. Tip: zeroes depend on meeting the (x)-axis.
Step 3
Exam Tip
एक ही स्पर्श बिंदु एक वास्तविक शून्यक देता है। टिप: शून्यक (x)-अक्ष से मिलने पर निर्भर है।
A. \(\sqrt{3}=-\frac{p}{q}\) होगा जो असंभव है/\(\sqrt{3}=-\frac{p}{q}\) would be true which is impossible
Step 1
Concept
\(-\frac{p}{q}\) is rational so it would make \(\sqrt{3}\) rational which is false. In exams recognize the contradiction method.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{3}=-\frac{p}{q}\) होगा जो असंभव है / \(\sqrt{3}=-\frac{p}{q}\) would be true which is impossible. \(-\frac{p}{q}\) is rational so it would make \(\sqrt{3}\) rational which is false. In exams recognize the contradiction method.
Step 3
Exam Tip
\(-\frac{p}{q}\) परिमेय है इसलिए इससे \(\sqrt{3}\) परिमेय हो जाएगा जो गलत है। परीक्षा में विरोधाभास विधि पहचानें।
A. \(\sqrt{2}=-\frac{p}{q}\), इसलिए \(\sqrt{2}\) परिमेय होगा जो असंभव है/\(\sqrt{2}=-\frac{p}{q}\), so \(\sqrt{2}\) would be rational which is impossible
Step 1
Concept
Since \(-\frac{p}{q}\) is rational, this would make \(\sqrt{2}\) rational which is false. In exams recognize the contradiction method.
Step 2
Why this answer is correct
The correct answer is A. \(\sqrt{2}=-\frac{p}{q}\), इसलिए \(\sqrt{2}\) परिमेय होगा जो असंभव है / \(\sqrt{2}=-\frac{p}{q}\), so \(\sqrt{2}\) would be rational which is impossible. Since \(-\frac{p}{q}\) is rational, this would make \(\sqrt{2}\) rational which is false. In exams recognize the contradiction method.
Step 3
Exam Tip
क्योंकि \(-\frac{p}{q}\) परिमेय है, इससे \(\sqrt{2}\) परिमेय मानना पड़ेगा जो गलत है। परीक्षा में विरोधाभास विधि को पहचानें।
Multiplying an irrational number by a non-zero rational number keeps it irrational.
Step 2
Why this answer is correct
If (pq) were rational, then \(q=\frac{pq}{p}\) would be rational, which contradicts the given condition.
Step 3
Exam Tip
Always check that the rational multiplier is not zero. चरण 1: अशून्य परिमेय संख्या से गुणा करने पर अपरिमेयता बनी रहती है। चरण 2: यदि (pq) परिमेय मान लें, तो \(q=\frac{pq}{p}\) परिमेय हो जाएगा, जो गलत है। चरण 3: परीक्षा में ध्यान रखें कि (p) शून्य नहीं होना चाहिए।
Dividing by a non-zero rational number does not remove irrationality.
Step 2
Why this answer is correct
For example, \(\frac{\sqrt{3}}{4}\) remains irrational.
Step 3
Exam Tip
The condition \(k\neq0\) is necessary because division by zero is not possible. चरण 1: अशून्य परिमेय संख्या से भाग करने पर अपरिमेयता समाप्त नहीं होती। चरण 2: जैसे \(\frac{\sqrt{3}}{4}\) अपरिमेय रहता है। चरण 3: यहां \(k\neq0\) जरूरी है क्योंकि शून्य से भाग संभव नहीं है।
Dividing by a non-zero rational number does not remove irrationality.
Step 2
Why this answer is correct
For example, \(\frac{\sqrt{3}}{4}\) remains irrational.
Step 3
Exam Tip
The condition \(k\neq0\) is necessary because division by zero is not possible. चरण 1: अशून्य परिमेय संख्या से भाग करने पर अपरिमेयता समाप्त नहीं होती। चरण 2: जैसे \(\frac{\sqrt{3}}{4}\) अपरिमेय रहता है। चरण 3: यहां \(k\neq0\) जरूरी है क्योंकि शून्य से भाग संभव नहीं है।
A non-zero rational multiplier does not remove irrationality.
Step 2
Why this answer is correct
For example, \(4\sqrt{3}\) remains irrational.
Step 3
Exam Tip
The non-zero condition is important because multiplying by (0) gives (0). चरण 1: अशून्य परिमेय गुणक अपरिमेयता को समाप्त नहीं करता। चरण 2: जैसे \(4\sqrt{3}\) अपरिमेय रहता है। चरण 3: यहां अशून्य शर्त जरूरी है क्योंकि (0) से गुणा करने पर परिणाम (0) होगा।
Dividing by a non-zero rational number does not remove irrationality.
Step 2
Why this answer is correct
For example, \(\frac{\sqrt{2}}{5}\) is irrational.
Step 3
Exam Tip
The condition \(r\neq0\) is necessary because division by zero is not possible. चरण 1: अशून्य परिमेय संख्या से भाग करने पर अपरिमेयता समाप्त नहीं होती। चरण 2: जैसे \(\frac{\sqrt{2}}{5}\) अपरिमेय है। चरण 3: यहां \(r\neq0\) शर्त जरूरी है क्योंकि शून्य से भाग संभव नहीं होता।
A non-zero rational multiplier does not remove irrationality.
Step 2
Why this answer is correct
For example, \(3\sqrt{2}\) is irrational.
Step 3
Exam Tip
The non-zero condition is important because multiplying by zero gives zero. चरण 1: अशून्य परिमेय गुणक अपरिमेयता को समाप्त नहीं करता। चरण 2: जैसे \(3\sqrt{2}\) अपरिमेय है। चरण 3: यहां अशून्य शर्त जरूरी है क्योंकि शून्य से गुणा करने पर परिणाम शून्य होगा।
Multiplying an irrational number by a non-zero rational number keeps it irrational.
Step 2
Why this answer is correct
For example, \(2 \times \sqrt{3}=2\sqrt{3}\), which is irrational.
Step 3
Exam Tip
The non-zero condition is important because multiplication by (0) gives (0). चरण 1: अशून्य परिमेय संख्या से अपरिमेय संख्या को गुणा करने पर परिणाम अपरिमेय रहता है। चरण 2: जैसे \(2 \times \sqrt{3}=2\sqrt{3}\), जो अपरिमेय है। चरण 3: यहां अशून्य शर्त जरूरी है, क्योंकि शून्य से गुणा करने पर परिणाम (0) होगा।
One pair of (2) and (5) makes (10), giving a trailing zero.
Step 2
Why this answer is correct
Remove one (2) with the (5), leaving \(2^3 \times 3^2=72\), so the last non-zero digit is (2).
Step 3
Exam Tip
After removing trailing-zero pairs, check the last digit of the remaining product. चरण 1: (2) और (5) का एक जोड़ा (10) बनाता है, जो अंतिम शून्य देता है। चरण 2: एक (5) के साथ एक (2) हटाएं, बचता है \(2^3 \times 3^2=8 \times 9=72\), इसलिए शून्य से अलग अंतिम अंक (2) है। चरण 3: अंतिम शून्य हटाने के बाद बची संख्या का अंतिम अंक देखें।
C. कोई वास्तविक मूल नहीं है/There are no real roots
Step 1
Concept
The discriminant is (4-20=-16), which is negative, so there are no real roots. In exams do not treat a negative discriminant as real zeroes.
Step 2
Why this answer is correct
The correct answer is C. कोई वास्तविक मूल नहीं है / There are no real roots. The discriminant is (4-20=-16), which is negative, so there are no real roots. In exams do not treat a negative discriminant as real zeroes.
Step 3
Exam Tip
विविक्तकर (4-20=-16) ऋणात्मक है, इसलिए वास्तविक मूल नहीं हैं। परीक्षा में ऋणात्मक विविक्तकर को वास्तविक शून्यक नहीं मानें।
The Maya used zero in calculation and timekeeping. For exams connect the Maya with mathematical achievement.
Step 2
Why this answer is correct
The correct answer is A. गणना और कैलेंडर / Calculation and calendar. The Maya used zero in calculation and timekeeping. For exams connect the Maya with mathematical achievement.
Step 3
Exam Tip
माया गणना और समय मापन में शून्य का उपयोग करते थे। परीक्षा में माया को गणितीय उपलब्धि से जोड़ें।
Brahmagupta gave important mathematical rules on zero and numbers. For exams, connect zero with a major achievement of Indian mathematics.
Step 2
Why this answer is correct
The correct answer is A. गणित / Mathematics. Brahmagupta gave important mathematical rules on zero and numbers. For exams, connect zero with a major achievement of Indian mathematics.
Step 3
Exam Tip
ब्रह्मगुप्त ने शून्य और संख्याओं पर महत्वपूर्ण गणितीय नियम दिए। परीक्षा में शून्य को भारतीय गणित की प्रमुख उपलब्धि से जोड़ें।
A. हर पद में (x) गुणनखंड है/Every term has factor (x)
Step 1
Concept
(p(x)=x\(7x^2-2\)), so at (x=0) the value is (0). If every term has (x), then (0) is a zero.
Step 2
Why this answer is correct
The correct answer is A. हर पद में (x) गुणनखंड है / Every term has factor (x). (p(x)=x\(7x^2-2\)), so at (x=0) the value is (0). If every term has (x), then (0) is a zero.
Step 3
Exam Tip
(p(x)=x\(7x^2-2\)), इसलिए (x=0) पर मान (0) होता है। यदि हर पद में (x) हो, तो (0) शून्यक होता है।
A. इसकी घात परिभाषित नहीं होती/Its degree is not defined
Step 1
Concept
The zero polynomial has no non-zero term, so its degree is not defined. A non-zero constant polynomial has degree (0).
Step 2
Why this answer is correct
The correct answer is A. इसकी घात परिभाषित नहीं होती / Its degree is not defined. The zero polynomial has no non-zero term, so its degree is not defined. A non-zero constant polynomial has degree (0).
Step 3
Exam Tip
शून्य बहुपद में कोई अशून्य पद नहीं होता, इसलिए उसकी घात परिभाषित नहीं होती। स्थिर अशून्य बहुपद की घात (0) होती है।
C. इसकी घात परिभाषित नहीं होती/Its degree is not defined
Step 1
Concept
The degree of the zero polynomial is not defined. A non-zero constant polynomial has degree (0).
Step 2
Why this answer is correct
The correct answer is C. इसकी घात परिभाषित नहीं होती / Its degree is not defined. The degree of the zero polynomial is not defined. A non-zero constant polynomial has degree (0).
Step 3
Exam Tip
शून्य बहुपद की घात परिभाषित नहीं होती। गैर-शून्य नियत बहुपद की घात (0) होती है।
