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Which of the following is a zero of the polynomial \(p(x)=16x^2-24x+9\)?बहुपद \(p(x)=16x^2-24x+9\) का शून्यक कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(\frac{3}{4}\)\(\frac{3}{4}\)
The polynomial can be written as \(16x^2-24x+9=(4x-3)^2\). For a zero, \(4x-3=0\), giving \(x=\frac{3}{4}\). Substituting option B, \(x=-\frac{3}{4}\), does not make the polynomial zero. In an exam, identifying the perfect-square form is the quickest method.दिया गया बहुपद \(16x^2-24x+9=(4x-3)^2\) है। शून्यक के लिए \(4x-3=0\), अतः \(x=\frac{3}{4}\)। विकल्प B में \(x=-\frac{3}{4}\) रखने पर बहुपद का मान शून्य नहीं आता। परीक्षा में ऐसे प्रश्नों में पूर्ण वर्ग पहचानना सबसे तेज़ तरीका है।
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