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If (\sqrt{3}) is a repeated zero of (x^2+kx+3), what is (k)?
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Answer and explanation
Correct answer: (-2\sqrt{3})
Both zeroes are (\sqrt{3}), so the sum is (2\sqrt{3}). In (x^2+kx+3), the sum is (-k), hence (k=-2\sqrt{3}).
Frequently asked questions
What is the correct answer to this question?
(-2\sqrt{3})
Why is this the correct answer?
Both zeroes are (\sqrt{3}), so the sum is (2\sqrt{3}). In (x^2+kx+3), the sum is (-k), hence (k=-2\sqrt{3}).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
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