What will be the last non-zero digit of the number (2^4 \times 3^2 \times 5)?
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Answer and explanation
Correct answer: 2
Step 1: One pair of (2) and (5) makes (10), giving a trailing zero. Step 2: Remove one (2) with the (5), leaving (2^3 \times 3^2=72), so the last non-zero digit is (2). Step 3: After removing trailing-zero pairs, check the last digit of the remaining product.
Frequently asked questions
What is the correct answer to this question?
2
Why is this the correct answer?
Step 1: One pair of (2) and (5) makes (10), giving a trailing zero. Step 2: Remove one (2) with the (5), leaving (2^3 \times 3^2=72), so the last non-zero digit is (2). Step 3: After removing trailing-zero pairs, check the last digit of the remaining product.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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