If one zero of the polynomial \(p(x)=x^2+3x-18\) is \(3\), what is its other zero?
Answer and explanation
Correct answer: -6
For a quadratic polynomial \(ax^2+bx+c\), the product of its zeroes is \(\frac{c}{a}\). Here, the product is \(\frac{-18}{1}=-18\). Since one zero is \(3\), the other zero is \(\frac{-18}{3}=-6\). Hence, option A is correct. Exam tip: when one zero is given, use the product of zeroes directly rather than the sum unless needed.
Frequently asked questions
What is the correct answer to this question?
-6
Why is this the correct answer?
For a quadratic polynomial \(ax^2+bx+c\), the product of its zeroes is \(\frac{c}{a}\). Here, the product is \(\frac{-18}{1}=-18\). Since one zero is \(3\), the other zero is \(\frac{-18}{3}=-6\). Hence, option A is correct. Exam tip: when one zero is given, use the product of zeroes directly rather than the sum unless needed.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Polynomials in one variable.
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