A. दूसरा (7), कटान ((6,0)), ((7,0))/Other (7), intersections ((6,0)), ((7,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (13), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (7), कटान ((6,0)), ((7,0)) / Other (7), intersections ((6,0)), ((7,0)). In the quadratic, the sum of zeroes is (13), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (13) है, इसलिए दूसरा शून्यक (7) है। टिप: शून्यक को ((x,0)) में बदलें।
(x-2-13x-68=(x-17)(x+4)), so the zeroes are (17) and (-4). Tip: write intersection points from factors.
Step 2
Why this answer is correct
The correct answer is A. ((17,0)) और ((-4,0)) / ((17,0)) and ((-4,0)). (x-2-13x-68=(x-17)(x+4)), so the zeroes are (17) and (-4). Tip: write intersection points from factors.
Step 3
Exam Tip
(x-2-13x-68=(x-17)(x+4)) है, इसलिए शून्यक (17) और (-4) हैं। टिप: गुणनखंडों से कटान बिंदु लिखें।
The polynomial is ((x-n)(x-(n+3))), so the zeroes are (n) and (n+3). Tip: write zeroes as ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((n,0)) और ((n+3,0)) / ((n,0)) and ((n+3,0)). The polynomial is ((x-n)(x-(n+3))), so the zeroes are (n) and (n+3). Tip: write zeroes as ((x,0)).
Step 3
Exam Tip
बहुपद ((x-n)(x-(n+3))) है इसलिए शून्यक (n) और (n+3) हैं। टिप: शून्यकों को ((x,0)) में लिखें।
A. दूसरा (7), कटान ((4,0)), ((7,0))/Other (7), intersections ((4,0)), ((7,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (11), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (7), कटान ((4,0)), ((7,0)) / Other (7), intersections ((4,0)), ((7,0)). In the quadratic, the sum of zeroes is (11), so the other zero is (7). Tip: convert a zero into ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (11) है, इसलिए दूसरा शून्यक (7) है। टिप: शून्यक को ((x,0)) में बदलें।
(x-2-9x-52=(x-13)(x+4)), so the zeroes are (13) and (-4). Tip: write intersection points from factors.
Step 2
Why this answer is correct
The correct answer is A. ((13,0)) और ((-4,0)) / ((13,0)) and ((-4,0)). (x-2-9x-52=(x-13)(x+4)), so the zeroes are (13) and (-4). Tip: write intersection points from factors.
Step 3
Exam Tip
(x-2-9x-52=(x-13)(x+4)) है, इसलिए शून्यक (13) और (-4) हैं। टिप: गुणनखंडों से कटान बिंदु लिखें।
The polynomial is ((x-m)(x-(m-1))), so the zeroes are (m) and (m-1). Tip: write zeroes as ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((m,0)) और ((m-1,0)) / ((m,0)) and ((m-1,0)). The polynomial is ((x-m)(x-(m-1))), so the zeroes are (m) and (m-1). Tip: write zeroes as ((x,0)).
Step 3
Exam Tip
बहुपद ((x-m)(x-(m-1))) है, इसलिए शून्यक (m) और (m-1) हैं। टिप: शून्यकों को ((x,0)) में लिखें।
A. दूसरा (5), कटान ((4,0)), ((5,0))/Other (5), intersections ((4,0)), ((5,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (9), so the other zero is (5). Tip: quickly convert a zero to ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (5), कटान ((4,0)), ((5,0)) / Other (5), intersections ((4,0)), ((5,0)). In the quadratic, the sum of zeroes is (9), so the other zero is (5). Tip: quickly convert a zero to ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (9) है इसलिए दूसरा शून्यक (5) है। टिप: शून्यक को तुरंत ((x,0)) में बदलें।
(x-2-8x-33=(x-11)(x+3)), so the zeroes are (11) and (-3). Tip: form ((x,0)) points from factors.
Step 2
Why this answer is correct
The correct answer is A. ((11,0)) और ((-3,0)) / ((11,0)) and ((-3,0)). (x-2-8x-33=(x-11)(x+3)), so the zeroes are (11) and (-3). Tip: form ((x,0)) points from factors.
Step 3
Exam Tip
(x-2-8x-33=(x-11)(x+3)) है इसलिए शून्यक (11) और (-3) हैं। टिप: गुणनखंडों से बिंदु ((x,0)) बनाएं।
It is ((x-u)(x-v)), so the zeroes are (u) and (v). Tip: write each zero as the point ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((u,0)) और ((v,0)) / ((u,0)) and ((v,0)). It is ((x-u)(x-v)), so the zeroes are (u) and (v). Tip: write each zero as the point ((x,0)).
Step 3
Exam Tip
यह ((x-u)(x-v)) है इसलिए शून्यक (u) और (v) हैं। टिप: शून्यक को ((x,0)) बिंदु के रूप में लिखें।
A. दूसरा (4), कटान ((3,0)), ((4,0))/Other (4), intersections ((3,0)), ((4,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (7), so the other zero is (4). Tip: quickly convert a zero to ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (4), कटान ((3,0)), ((4,0)) / Other (4), intersections ((3,0)), ((4,0)). In the quadratic, the sum of zeroes is (7), so the other zero is (4). Tip: quickly convert a zero to ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (7) है, इसलिए दूसरा शून्यक (4) है। टिप: शून्यक को तुरंत ((x,0)) में बदलें।
(x-2-4x-21=(x-7)(x+3)), so the zeroes are (7) and (-3). Tip: form ((x,0)) points from factors.
Step 2
Why this answer is correct
The correct answer is A. ((7,0)) और ((-3,0)) / ((7,0)) and ((-3,0)). (x-2-4x-21=(x-7)(x+3)), so the zeroes are (7) and (-3). Tip: form ((x,0)) points from factors.
Step 3
Exam Tip
(x-2-4x-21=(x-7)(x+3)) है, इसलिए शून्यक (7) और (-3) हैं। टिप: गुणनखंडों से बिंदु ((x,0)) बनाएं।
A. दूसरा (3), कटान ((2,0)), ((3,0))/Other (3), intersections ((2,0)), ((3,0))
Step 1
Concept
In the quadratic, the sum of zeroes is (5), so the other zero is (3). Tip: immediately convert a zero to ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. दूसरा (3), कटान ((2,0)), ((3,0)) / Other (3), intersections ((2,0)), ((3,0)). In the quadratic, the sum of zeroes is (5), so the other zero is (3). Tip: immediately convert a zero to ((x,0)).
Step 3
Exam Tip
द्विघात में शून्यकों का योग (5) है, इसलिए दूसरा शून्यक (3) है। टिप: शून्यक को तुरंत ((x,0)) में बदलें।
(x-2+2x-15=(x+5)(x-3)), so the zeroes are (-5) and (3). Tip: form points ((x,0)) from factors.
Step 2
Why this answer is correct
The correct answer is A. ((3,0)) और ((-5,0)) / ((3,0)) and ((-5,0)). (x-2+2x-15=(x+5)(x-3)), so the zeroes are (-5) and (3). Tip: form points ((x,0)) from factors.
Step 3
Exam Tip
(x-2+2x-15=(x+5)(x-3)), इसलिए शून्यक (-5) और (3) हैं। टिप: गुणनखंडों से बिंदु ((x,0)) बनाएं।
The polynomial equals ((x-a)(x-b)), so the zeroes are (a) and (b). Tip: connect factor form with graph intersections.
Step 2
Why this answer is correct
The correct answer is A. ((a,0)) और ((b,0)) / ((a,0)) and ((b,0)). The polynomial equals ((x-a)(x-b)), so the zeroes are (a) and (b). Tip: connect factor form with graph intersections.
Step 3
Exam Tip
बहुपद ((x-a)(x-b)) के बराबर है, इसलिए शून्यक (a) और (b) हैं। टिप: गुणनखंड रूप को ग्राफ कटान से जोड़ें।
The first coordinate of each intersection point is a zero. Tip: read the zero (a) from ((a,0)).
Step 2
Why this answer is correct
The correct answer is B. शून्यक (a,b,c) हैं / The zeroes are (a,b,c). The first coordinate of each intersection point is a zero. Tip: read the zero (a) from ((a,0)).
Step 3
Exam Tip
हर कटान बिंदु का पहला निर्देशांक शून्यक है। टिप: ((a,0)) से शून्यक (a) पढ़ें।
B. (0), (2) और (5) शून्यक हैं/(0), (2) and (5) are zeroes
Step 1
Concept
The origin is also on the (x)-axis, so (0) is also a zero. Tip: do not ignore ((0,0)).
Step 2
Why this answer is correct
The correct answer is B. (0), (2) और (5) शून्यक हैं / (0), (2) and (5) are zeroes. The origin is also on the (x)-axis, so (0) is also a zero. Tip: do not ignore ((0,0)).
Step 3
Exam Tip
मूल बिंदु भी (x)-अक्ष पर है, इसलिए (0) भी शून्यक है। टिप: ((0,0)) को नजरअंदाज न करें।
At an (x)-axis intersection, (y=p(x)=0). Tip: read the function value directly from the intersection point.
Step 2
Why this answer is correct
The correct answer is A. दोनों (0) / Both (0). At an (x)-axis intersection, (y=p(x)=0). Tip: read the function value directly from the intersection point.
Step 3
Exam Tip
(x)-अक्ष कटान पर (y=p(x)=0) होता है। टिप: कटान बिंदु से फलन मान सीधे पढ़ें।
Where (p(x)=0), there is an (x)-axis intersection. Tip: (p(0)=5) does not give a zero.
Step 2
Why this answer is correct
The correct answer is B. ((-3,0)) और ((4,0)) / ((-3,0)) and ((4,0)). Where (p(x)=0), there is an (x)-axis intersection. Tip: (p(0)=5) does not give a zero.
Step 3
Exam Tip
जहाँ (p(x)=0) है वहीं (x)-अक्ष कटान है। टिप: (p(0)=5) शून्यक नहीं देता।
