यदि (p(x)=x-2 -hx) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2 -hx), what will be the (x)-axis intersections of the graph?
#symbolic factorization
#intercepts
#zeroes
A ((0,0)) और ((h,0)) / ((0,0)) and ((h,0))
B ((0,0)) और ((-h,0)) / ((0,0)) and ((-h,0))
C ((h,0)) और ((-h,0)) / ((h,0)) and ((-h,0))
D ((0,h)) और ((h,0)) / ((0,h)) and ((h,0))
Explanation opens after your attempt
Correct Answer
A. ((0,0)) और ((h,0)) / ((0,0)) and ((h,0))
Step 1
Concept
(x-2 -hx=x(x-h)), so the zeroes are (0) and (h). Tip: factor out the common (x).
Step 2
Why this answer is correct
The correct answer is A. ((0,0)) और ((h,0)) / ((0,0)) and ((h,0)). (x-2 -hx=x(x-h)), so the zeroes are (0) and (h). Tip: factor out the common (x).
Step 3
Exam Tip
(x-2 -hx=x(x-h)) है, इसलिए शून्यक (0) और (h) हैं। टिप: सामान्य (x) गुणनखंड निकालें।
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यदि (p(x)=x-2 -(2n+3)x+n(n+3)) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2 -(2n+3)x+n(n+3)), what will be the (x)-axis intersections of the graph?
#symbolic factorization
#intercepts
#zeroes
A ((n,0)) और ((n+3,0)) / ((n,0)) and ((n+3,0))
B ((0,n)) और ((0,n+3)) / ((0,n)) and ((0,n+3))
C ((-n,0)) और ((-n-3,0)) / ((-n,0)) and ((-n-3,0))
D ((n,n+3)) और ((n+3,n)) / ((n,n+3)) and ((n+3,n))
Explanation opens after your attempt
Correct Answer
A. ((n,0)) और ((n+3,0)) / ((n,0)) and ((n+3,0))
Step 1
Concept
The polynomial is ((x-n)(x-(n+3))), so the zeroes are (n) and (n+3). Tip: write zeroes as ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((n,0)) और ((n+3,0)) / ((n,0)) and ((n+3,0)). The polynomial is ((x-n)(x-(n+3))), so the zeroes are (n) and (n+3). Tip: write zeroes as ((x,0)).
Step 3
Exam Tip
बहुपद ((x-n)(x-(n+3))) है इसलिए शून्यक (n) और (n+3) हैं। टिप: शून्यकों को ((x,0)) में लिखें।
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यदि (p(x)=x-2 -ex) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2 -ex), what will be the (x)-axis intersections of the graph?
#symbolic factorization
#intercepts
#zeroes
A ((0,0)) और ((e,0)) / ((0,0)) and ((e,0))
B ((0,0)) और ((-e,0)) / ((0,0)) and ((-e,0))
C ((e,0)) और ((-e,0)) / ((e,0)) and ((-e,0))
D ((0,e)) और ((e,0)) / ((0,e)) and ((e,0))
Explanation opens after your attempt
Correct Answer
A. ((0,0)) और ((e,0)) / ((0,0)) and ((e,0))
Step 1
Concept
(x-2 -ex=x(x-e)), so the zeroes are (0) and (e). Tip: factor out the common (x).
Step 2
Why this answer is correct
The correct answer is A. ((0,0)) और ((e,0)) / ((0,0)) and ((e,0)). (x-2 -ex=x(x-e)), so the zeroes are (0) and (e). Tip: factor out the common (x).
Step 3
Exam Tip
(x-2 -ex=x(x-e)) है, इसलिए शून्यक (0) और (e) हैं। टिप: सामान्य (x) गुणनखंड निकालें।
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यदि (p(x)=x-2 -(2m-1)x+m(m-1 )) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2 -(2m-1)x+m(m-1 )), what will be the (x)-axis intersections of the graph?
#symbolic factorization
#intercepts
#zeroes
A ((m,0)) और ((m-1 ,0)) / ((m,0)) and ((m-1 ,0))
B ((0,m)) और ((0,m-1 )) / ((0,m)) and ((0,m-1 ))
C ((-m,0)) और ((1-m,0)) / ((-m,0)) and ((1-m,0))
D ((m,m-1 )) और ((m-1 ,m)) / ((m,m-1 )) and ((m-1 ,m))
Explanation opens after your attempt
Correct Answer
A. ((m,0)) और ((m-1 ,0)) / ((m,0)) and ((m-1 ,0))
Step 1
Concept
The polynomial is ((x-m)(x-(m-1 ))), so the zeroes are (m) and (m-1 ). Tip: write zeroes as ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((m,0)) और ((m-1 ,0)) / ((m,0)) and ((m-1 ,0)). The polynomial is ((x-m)(x-(m-1 ))), so the zeroes are (m) and (m-1 ). Tip: write zeroes as ((x,0)).
Step 3
Exam Tip
बहुपद ((x-m)(x-(m-1 ))) है, इसलिए शून्यक (m) और (m-1 ) हैं। टिप: शून्यकों को ((x,0)) में लिखें।
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यदि (p(x)=x-2 -cx) है तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2 -cx), what will be the (x)-axis intersections of the graph?
#symbolic factorization
#intercepts
#zeroes
A ((0,0)) और ((c,0)) / ((0,0)) and ((c,0))
B ((0,0)) और ((-c,0)) / ((0,0)) and ((-c,0))
C ((c,0)) और ((-c,0)) / ((c,0)) and ((-c,0))
D ((0,c)) और ((c,0)) / ((0,c)) and ((c,0))
Explanation opens after your attempt
Correct Answer
A. ((0,0)) और ((c,0)) / ((0,0)) and ((c,0))
Step 1
Concept
(x-2 -cx=x(x-c)), so the zeroes are (0) and (c). Tip: factor out the common (x).
Step 2
Why this answer is correct
The correct answer is A. ((0,0)) और ((c,0)) / ((0,0)) and ((c,0)). (x-2 -cx=x(x-c)), so the zeroes are (0) and (c). Tip: factor out the common (x).
Step 3
Exam Tip
(x-2 -cx=x(x-c)) है इसलिए शून्यक (0) और (c) हैं। टिप: सामान्य (x) गुणनखंड निकालें।
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यदि (p(x)=x-2 -(u+v)x+uv) है तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2 -(u+v)x+uv), what will be the (x)-axis intersections of the graph?
#symbolic factorization
#intercepts
#zeroes
A ((u,0)) और ((v,0)) / ((u,0)) and ((v,0))
B ((0,u)) और ((0,v)) / ((0,u)) and ((0,v))
C ((-u,0)) और ((-v,0)) / ((-u,0)) and ((-v,0))
D ((u,v)) और ((v,u)) / ((u,v)) and ((v,u))
Explanation opens after your attempt
Correct Answer
A. ((u,0)) और ((v,0)) / ((u,0)) and ((v,0))
Step 1
Concept
It is ((x-u)(x-v)), so the zeroes are (u) and (v). Tip: write each zero as the point ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((u,0)) और ((v,0)) / ((u,0)) and ((v,0)). It is ((x-u)(x-v)), so the zeroes are (u) and (v). Tip: write each zero as the point ((x,0)).
Step 3
Exam Tip
यह ((x-u)(x-v)) है इसलिए शून्यक (u) और (v) हैं। टिप: शून्यक को ((x,0)) बिंदु के रूप में लिखें।
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यदि (p(x)=x-2 -bx) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2 -bx), what will be the (x)-axis intersections of the graph?
#symbolic factorization
#intercepts
#zeroes
A ((0,0)) और ((b,0)) / ((0,0)) and ((b,0))
B ((0,0)) और ((-b,0)) / ((0,0)) and ((-b,0))
C ((b,0)) और ((-b,0)) / ((b,0)) and ((-b,0))
D ((0,b)) और ((b,0)) / ((0,b)) and ((b,0))
Explanation opens after your attempt
Correct Answer
A. ((0,0)) और ((b,0)) / ((0,0)) and ((b,0))
Step 1
Concept
(x-2 -bx=x(x-b)), so the zeroes are (0) and (b). Tip: factor out the common (x).
Step 2
Why this answer is correct
The correct answer is A. ((0,0)) और ((b,0)) / ((0,0)) and ((b,0)). (x-2 -bx=x(x-b)), so the zeroes are (0) and (b). Tip: factor out the common (x).
Step 3
Exam Tip
(x-2 -bx=x(x-b)) है, इसलिए शून्यक (0) और (b) हैं। टिप: सामान्य (x) गुणनखंड निकालें।
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यदि (p(x)=x-2 -(m+n)x+mn) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2 -(m+n)x+mn), what will be the (x)-axis intersections of the graph?
#symbolic factorization
#intercepts
#zeroes
A ((m,0)) और ((n,0)) / ((m,0)) and ((n,0))
B ((0,m)) और ((0,n)) / ((0,m)) and ((0,n))
C ((-m,0)) और ((-n,0)) / ((-m,0)) and ((-n,0))
D ((m,n)) और ((n,m)) / ((m,n)) and ((n,m))
Explanation opens after your attempt
Correct Answer
A. ((m,0)) और ((n,0)) / ((m,0)) and ((n,0))
Step 1
Concept
It is ((x-m)(x-n)), so the zeroes are (m) and (n). Tip: write each zero as ((x,0)).
Step 2
Why this answer is correct
The correct answer is A. ((m,0)) और ((n,0)) / ((m,0)) and ((n,0)). It is ((x-m)(x-n)), so the zeroes are (m) and (n). Tip: write each zero as ((x,0)).
Step 3
Exam Tip
यह ((x-m)(x-n)) है इसलिए शून्यक (m) और (n) हैं। टिप: शून्यक को ((x,0)) में लिखें।
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यदि (p(x)=x-2 -ax) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2 -ax), what will be the (x)-axis intersections of the graph?
#symbolic factorization
#intercepts
#zeroes
A ((0,0)) और ((a,0)) / ((0,0)) and ((a,0))
B ((0,0)) और ((-a,0)) / ((0,0)) and ((-a,0))
C ((a,0)) और ((-a,0)) / ((a,0)) and ((-a,0))
D ((0,a)) और ((a,0)) / ((0,a)) and ((a,0))
Explanation opens after your attempt
Correct Answer
A. ((0,0)) और ((a,0)) / ((0,0)) and ((a,0))
Step 1
Concept
(x-2 -ax=x(x-a)), so the zeroes are (0) and (a). Tip: factor out the common (x).
Step 2
Why this answer is correct
The correct answer is A. ((0,0)) और ((a,0)) / ((0,0)) and ((a,0)). (x-2 -ax=x(x-a)), so the zeroes are (0) and (a). Tip: factor out the common (x).
Step 3
Exam Tip
(x-2 -ax=x(x-a)), इसलिए शून्यक (0) और (a) हैं। टिप: सामान्य (x) गुणनखंड निकालें।
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यदि (p(x)=x-2 -(a+b)x+ab) है, तो ग्राफ के (x)-अक्ष कटान कौन से होंगे?
If (p(x)=x-2 -(a+b)x+ab), what will be the (x)-axis intersections of the graph?
#symbolic factorization
#intercepts
#zeroes
A ((a,0)) और ((b,0)) / ((a,0)) and ((b,0))
B ((0,a)) और ((0,b)) / ((0,a)) and ((0,b))
C ((-a,0)) और ((-b,0)) / ((-a,0)) and ((-b,0))
D ((a,b)) और ((b,a)) / ((a,b)) and ((b,a))
Explanation opens after your attempt
Correct Answer
A. ((a,0)) और ((b,0)) / ((a,0)) and ((b,0))
Step 1
Concept
The polynomial equals ((x-a)(x-b)), so the zeroes are (a) and (b). Tip: connect factor form with graph intersections.
Step 2
Why this answer is correct
The correct answer is A. ((a,0)) और ((b,0)) / ((a,0)) and ((b,0)). The polynomial equals ((x-a)(x-b)), so the zeroes are (a) and (b). Tip: connect factor form with graph intersections.
Step 3
Exam Tip
बहुपद ((x-a)(x-b)) के बराबर है, इसलिए शून्यक (a) और (b) हैं। टिप: गुणनखंड रूप को ग्राफ कटान से जोड़ें।
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