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If \(p(x)=x^2-cx\), what are the x-axis intersections (x-intercepts) of its graph?

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Answer and explanation

Correct answer: (0,0) and (c,0)

We have \(p(x)=x^2-cx\). Factor the expression: \(p(x)=x(x-c)\). Setting \(p(x)=0\) gives \(x=0\) or \(x=c\). Therefore the x-intercepts are \((0,0)\) and \((c,0)\). Why others are wrong: option B uses \(-c\) which is the wrong sign; option C omits the zero at \(x=0\); option D includes \((0,c)\), a point on the y-axis, not an x-intercept. Exam tip: set \(p(x)=0\) and factor out the common \(x\) to find zeros quickly.

Related tags

PolynomialsZerosX-InterceptsFactorizationQuadratic-Functions

Frequently asked questions

What is the correct answer to this question?

(0,0) and (c,0)

Why is this the correct answer?

We have \(p(x)=x^2-cx\). Factor the expression: \(p(x)=x(x-c)\). Setting \(p(x)=0\) gives \(x=0\) or \(x=c\). Therefore the x-intercepts are \((0,0)\) and \((c,0)\). Why others are wrong: option B uses \(-c\) which is the wrong sign; option C omits the zero at \(x=0\); option D includes \((0,c)\), a point on the y-axis, not an x-intercept. Exam tip: set \(p(x)=0\) and factor out the common \(x\) to find zeros quickly.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Geometrical meaning of the zeroes of a polynomial..

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