रेखा (x-3y=12) के लिए (x=0) और (y=0) पर कौन-से अवरोध मिलते हैं?

For the line (x-3y=12), what intercepts are obtained at (x=0) and (y=0)?

Explanation opens after your attempt
Correct Answer

A. (\left\(0,-4\right\)) और (\left\(12,0\right\))(\left\(0,-4\right\)) and (\left\(12,0\right\))

Step 1

Concept

At (x=0), (y=-4), and at (y=0), (x=12). While finding intercepts, note which variable is kept zero.

Step 2

Why this answer is correct

The correct answer is A. (\left\(0,-4\right\)) और (\left\(12,0\right\)) / (\left\(0,-4\right\)) and (\left\(12,0\right\)). At (x=0), (y=-4), and at (y=0), (x=12). While finding intercepts, note which variable is kept zero.

Step 3

Exam Tip

(x=0) पर (y=-4) और (y=0) पर (x=12)। अवरोध निकालते समय कौन-सा चर शून्य रखा है, यह ध्यान रखें।

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Mathematics Answer, Explanation and Revision Hints

रेखा (x-3y=12) के लिए (x=0) और (y=0) पर कौन-से अवरोध मिलते हैं? / For the line (x-3y=12), what intercepts are obtained at (x=0) and (y=0)?

Correct Answer: A. (\left\(0,-4\right\)) और (\left\(12,0\right\)) / (\left\(0,-4\right\)) and (\left\(12,0\right\)). Explanation: (x=0) पर (y=-4) और (y=0) पर (x=12)। अवरोध निकालते समय कौन-सा चर शून्य रखा है, यह ध्यान रखें। / At (x=0), (y=-4), and at (y=0), (x=12). While finding intercepts, note which variable is kept zero.

Which concept should I revise for this Mathematics MCQ?

At (x=0), (y=-4), and at (y=0), (x=12). While finding intercepts, note which variable is kept zero.

What exam hint can help solve this Mathematics question?

(x=0) पर (y=-4) और (y=0) पर (x=12)। अवरोध निकालते समय कौन-सा चर शून्य रखा है, यह ध्यान रखें।