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For which value of \(m\) will \(2\) be a zero of the polynomial \(x^2-6x+m\)?किस मान के लिए बहुपद \(x^2-6x+m\) का शून्यक \(2\) होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 88
If \(2\) is a zero of the polynomial, substituting \(x=2\) must make its value zero: \(2^2-6(2)+m=0\), so \(4-12+m=0\) and \(m=8\). Exam tip: Substitute the given zero into the polynomial and equate the result to zero.यदि \(2\) बहुपद का शून्यक है, तो बहुपद में \(x=2\) रखने पर उसका मान शून्य होगा: \(2^2-6(2)+m=0\), अर्थात \(4-12+m=0\)। इसलिए \(m=8\)। परीक्षा-युक्ति: दिए गए शून्यक को बहुपद में रखकर सीधे \(p(x)=0\) लगाएँ।
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