Question 1/16
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
क्या (x=-3) समीकरण \(2x^2+7x+3=0\) का मूल है?
Is (x=-3) a root of \(2x^2+7x+3=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=-3) gives (18-21+3=0). Watch the signs carefully when substituting a negative root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=-3) gives (18-21+3=0). Watch the signs carefully when substituting a negative root.
Step 3
Exam Tip
(x=-3) रखने पर (18-21+3=0) मिलता है। ऋणात्मक मूल रखते समय चिन्हों को ध्यान से देखें।
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Question 2/16
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
क्या (x=5) समीकरण \(x^2-10x+25=0\) का मूल है?
Is (x=5) a root of \(x^2-10x+25=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=5) gives (25-50+25=0). Therefore (5) is its root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=5) gives (25-50+25=0). Therefore (5) is its root.
Step 3
Exam Tip
(x=5) रखने पर (25-50+25=0) मिलता है। इसलिए (5) इसका मूल है।
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Question 3/16
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
क्या (x=-2) समीकरण \(3x^2+2x-8=0\) का मूल है?
Is (x=-2) a root of \(3x^2+2x-8=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=-2) gives (12-4-8=0). Handle signs carefully when substituting a negative root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=-2) gives (12-4-8=0). Handle signs carefully when substituting a negative root.
Step 3
Exam Tip
(x=-2) रखने पर (12-4-8=0) मिलता है। ऋणात्मक मूल रखते समय चिन्हों को ध्यान से संभालें।
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Question 4/16
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
क्या (x=4) समीकरण \(x^2-9x+20=0\) का मूल है?
Is (x=4) a root of \(x^2-9x+20=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=4) gives (16-36+20=0). Therefore (4) is a root of this equation.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=4) gives (16-36+20=0). Therefore (4) is a root of this equation.
Step 3
Exam Tip
(x=4) रखने पर (16-36+20=0) मिलता है। इसलिए (4) इस समीकरण का मूल है।
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Question 5/16
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
क्या (x=-1) समीकरण \(2x^2+5x+3=0\) का मूल है?
Is (x=-1) a root of \(2x^2+5x+3=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=-1) gives (2-5+3=0). Check signs carefully for a negative root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=-1) gives (2-5+3=0). Check signs carefully for a negative root.
Step 3
Exam Tip
(x=-1) रखने पर (2-5+3=0) मिलता है। ऋणात्मक मूल में चिन्हों की जांच ध्यान से करें।
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Question 6/16
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
क्या (x=3) समीकरण \(x^2-7x+12=0\) का मूल है?
Is (x=3) a root of \(x^2-7x+12=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=3) gives (9-21+12=0). Therefore (3) is a root of this equation.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=3) gives (9-21+12=0). Therefore (3) is a root of this equation.
Step 3
Exam Tip
(x=3) रखने पर (9-21+12=0) मिलता है। इसलिए (3) इस समीकरण का मूल है।
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Question 7/16
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
निम्न में से कौन सा मान \(x^2-100=0\) का मूल नहीं है?
Which of the following values is not a root of \(x^2-100=0\)?
Explanation opens after your attempt
Step 1
Concept
The roots of \(x^2-100=0\) are (10) and (-10). Substituting (0) does not make the equation true.
Step 2
Why this answer is correct
The correct answer is C. (0). The roots of \(x^2-100=0\) are (10) and (-10). Substituting (0) does not make the equation true.
Step 3
Exam Tip
\(x^2-100=0\) के मूल (10) और (-10) हैं। (0) रखने पर समीकरण सत्य नहीं होता।
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Question 8/16
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
क्या (x=-1) समीकरण \(2x^2+x-1=0\) का मूल है?
Is (x=-1) a root of \(2x^2+x-1=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=-1) gives (2-1-1=0). Sign checking is important with a negative root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=-1) gives (2-1-1=0). Sign checking is important with a negative root.
Step 3
Exam Tip
(x=-1) रखने पर (2-1-1=0) मिलता है। ऋणात्मक मूल में चिन्हों की जांच जरूरी है।
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Question 9/16
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
क्या (x=2) समीकरण \(x^2-4x+4=0\) का मूल है?
Is (x=2) a root of \(x^2-4x+4=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=2) gives (4-8+4=0). Therefore (2) is a root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=2) gives (4-8+4=0). Therefore (2) is a root.
Step 3
Exam Tip
(x=2) रखने पर (4-8+4=0) मिलता है। इसलिए (2) इसका मूल है।
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Question 10/16
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
निम्न में से कौन सा मान \(x^2-64=0\) का मूल नहीं है?
Which of the following values is not a root of \(x^2-64=0\)?
Explanation opens after your attempt
Step 1
Concept
The roots of \(x^2-64=0\) are (8) and (-8). Substituting (0) does not make the equation true.
Step 2
Why this answer is correct
The correct answer is C. (0). The roots of \(x^2-64=0\) are (8) and (-8). Substituting (0) does not make the equation true.
Step 3
Exam Tip
\(x^2-64=0\) के मूल (8) और (-8) हैं। (0) रखने पर समीकरण सत्य नहीं होता।
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Question 11/16
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
क्या (x=-2) समीकरण \(x^2+3x+2=0\) का मूल है?
Is (x=-2) a root of \(x^2+3x+2=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=-2) gives (4-6+2=0). Be careful with signs when substituting a negative value.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=-2) gives (4-6+2=0). Be careful with signs when substituting a negative value.
Step 3
Exam Tip
(x=-2) रखने पर (4-6+2=0) मिलता है। ऋणात्मक मान रखते समय चिन्हों पर ध्यान दें।
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Question 12/16
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
क्या (x=1) समीकरण \(x^2-3x+2=0\) का मूल है?
Is (x=1) a root of \(x^2-3x+2=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=1) gives (1-3+2=0). Therefore (1) is a root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=1) gives (1-3+2=0). Therefore (1) is a root.
Step 3
Exam Tip
(x=1) रखने पर (1-3+2=0) मिलता है। इसलिए (1) इसका मूल है।
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Question 13/16
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
निम्न में से कौन सा मान \(x^2-16=0\) का मूल नहीं है?
Which of the following values is not a root of \(x^2-16=0\)?
Explanation opens after your attempt
Step 1
Concept
The roots of \(x^2-16=0\) are (4) and (-4). Substituting (0) does not satisfy the equation.
Step 2
Why this answer is correct
The correct answer is C. (0). The roots of \(x^2-16=0\) are (4) and (-4). Substituting (0) does not satisfy the equation.
Step 3
Exam Tip
\(x^2-16=0\) के मूल (4) और (-4) हैं। (0) रखने पर समीकरण संतुष्ट नहीं होता।
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Question 14/16
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
यदि (3) समीकरण \(x^2+px-6=0\) का मूल है तो (p) का मान क्या है?
If (3) is a root of \(x^2+px-6=0\) then what is the value of (p)?
Explanation opens after your attempt
Step 1
Concept
Putting (x=3) gives (9+3p-6=0) so (p=-1). For a parameter question substitute the root directly.
Step 2
Why this answer is correct
The correct answer is B. (-1). Putting (x=3) gives (9+3p-6=0) so (p=-1). For a parameter question substitute the root directly.
Step 3
Exam Tip
(x=3) रखने पर (9+3p-6=0) इसलिए (p=-1)। पैरामीटर के लिए मूल को सीधे रखें।
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Question 15/16
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
क्या (x=0) समीकरण \(3x^2+2x=0\) का मूल है?
Is (x=0) a root of \(3x^2+2x=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=0) gives (3(0)2+2(0)=0). Therefore (0) is a root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=0) gives (3(0)2+2(0)=0). Therefore (0) is a root.
Step 3
Exam Tip
(x=0) रखने पर (3(0)2+2(0)=0) मिलता है। इसलिए (0) मूल है।
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Question 16/16
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
क्या (x=2) समीकरण \(x^2-5x+6=0\) का मूल है?
Is (x=2) a root of \(x^2-5x+6=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=2) gives (4-10+6=0) so it is a root. In exams always check the final sum after substitution.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=2) gives (4-10+6=0) so it is a root. In exams always check the final sum after substitution.
Step 3
Exam Tip
(x=2) रखने पर (4-10+6=0) मिलता है इसलिए यह मूल है। परीक्षा में मान रखने के बाद अंतिम योग जरूर देखें।
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