Question 1/14
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
क्या (x=-3) समीकरण \(2x^2+7x+3=0\) का मूल है?
Is (x=-3) a root of \(2x^2+7x+3=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=-3) gives (18-21+3=0). Watch the signs carefully when substituting a negative root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=-3) gives (18-21+3=0). Watch the signs carefully when substituting a negative root.
Step 3
Exam Tip
(x=-3) रखने पर (18-21+3=0) मिलता है। ऋणात्मक मूल रखते समय चिन्हों को ध्यान से देखें।
Login to save your score, XP, coins and progress.
Question 2/14
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
क्या (x=-2) समीकरण \(3x^2+2x-8=0\) का मूल है?
Is (x=-2) a root of \(3x^2+2x-8=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=-2) gives (12-4-8=0). Handle signs carefully when substituting a negative root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=-2) gives (12-4-8=0). Handle signs carefully when substituting a negative root.
Step 3
Exam Tip
(x=-2) रखने पर (12-4-8=0) मिलता है। ऋणात्मक मूल रखते समय चिन्हों को ध्यान से संभालें।
Login to save your score, XP, coins and progress.
Question 3/14
Medium Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
क्या (x=-1) समीकरण \(2x^2+5x+3=0\) का मूल है?
Is (x=-1) a root of \(2x^2+5x+3=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=-1) gives (2-5+3=0). Check signs carefully for a negative root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=-1) gives (2-5+3=0). Check signs carefully for a negative root.
Step 3
Exam Tip
(x=-1) रखने पर (2-5+3=0) मिलता है। ऋणात्मक मूल में चिन्हों की जांच ध्यान से करें।
Login to save your score, XP, coins and progress.
Question 4/14
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
यदि (x=-4) समीकरण \(2x^2+px-8=0\) का मूल है तो (p) का मान क्या है?
If (x=-4) is a root of \(2x^2+px-8=0\), what is the value of (p)?
Explanation opens after your attempt
Step 1
Concept
Putting (x=-4) gives (32-4p-8=0), so (p=6). Check signs carefully with a negative root.
Step 2
Why this answer is correct
The correct answer is A. (6). Putting (x=-4) gives (32-4p-8=0), so (p=6). Check signs carefully with a negative root.
Step 3
Exam Tip
(x=-4) रखने पर (32-4p-8=0) इसलिए (p=6) मिलता है। ऋणात्मक मूल में चिन्हों की जांच सावधानी से करें।
Login to save your score, XP, coins and progress.
Question 5/14
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
यदि किसी समीकरण के मूल (4) और (-7) हैं तो उनका योग क्या है?
If the roots of an equation are (4) and (-7), what is their sum?
Explanation opens after your attempt
Step 1
Concept
The sum is (4+(-7)=-3). Be careful with the sign while adding a negative number.
Step 2
Why this answer is correct
The correct answer is B. (-3). The sum is (4+(-7)=-3). Be careful with the sign while adding a negative number.
Step 3
Exam Tip
योग (4+(-7)=-3) है। ऋणात्मक संख्या जोड़ते समय चिन्ह का ध्यान रखें।
Login to save your score, XP, coins and progress.
Question 6/14
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
यदि (-3) समीकरण \(x^2+ux-18=0\) का मूल है तो (u) का मान क्या है?
If (-3) is a root of \(x^2+ux-18=0\), what is the value of (u)?
Explanation opens after your attempt
Step 1
Concept
Putting (x=-3) gives (9-3u-18=0), so (u=-3), not (u=3).
Step 2
Why this answer is correct
The correct answer is A. (-9). Putting (x=-3) gives (9-3u-18=0), so (u=-3), not (u=3).
Step 3
Exam Tip
(x=-3) रखने पर (9-3u-18=0) इसलिए (u=-3) नहीं बल्कि (u=-3)?
Login to save your score, XP, coins and progress.
Question 7/14
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33
क्या (x=-1) समीकरण \(2x^2+x-1=0\) का मूल है?
Is (x=-1) a root of \(2x^2+x-1=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=-1) gives (2-1-1=0). Sign checking is important with a negative root.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=-1) gives (2-1-1=0). Sign checking is important with a negative root.
Step 3
Exam Tip
(x=-1) रखने पर (2-1-1=0) मिलता है। ऋणात्मक मूल में चिन्हों की जांच जरूरी है।
Login to save your score, XP, coins and progress.
Question 8/14
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
यदि किसी समीकरण के मूल (2) और (-5) हैं तो उनका योग क्या है?
If the roots of an equation are (2) and (-5), what is their sum?
Explanation opens after your attempt
Step 1
Concept
The sum is (2+(-5)=-3). Do not forget the sign while adding a negative root.
Step 2
Why this answer is correct
The correct answer is B. (-3). The sum is (2+(-5)=-3). Do not forget the sign while adding a negative root.
Step 3
Exam Tip
योग (2+(-5)=-3) है। ऋणात्मक मूल जोड़ते समय चिन्ह न भूलें।
Login to save your score, XP, coins and progress.
Question 9/14
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
यदि (-1) समीकरण \(x^2+rx-12=0\) का मूल है तो (r) का मान क्या है?
If (-1) is a root of \(x^2+rx-12=0\), what is the value of (r)?
Explanation opens after your attempt
Step 1
Concept
Putting (x=-1) gives (1-r-12=0), so (r=-11). Check the sign of each term while using a negative root.
Step 2
Why this answer is correct
The correct answer is A. (-11). Putting (x=-1) gives (1-r-12=0), so (r=-11). Check the sign of each term while using a negative root.
Step 3
Exam Tip
(x=-1) रखने पर (1-r-12=0) इसलिए (r=-11)। ऋणात्मक मूल रखते समय प्रत्येक पद का चिन्ह देखें।
Login to save your score, XP, coins and progress.
Question 10/14
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32
क्या (x=-2) समीकरण \(x^2+3x+2=0\) का मूल है?
Is (x=-2) a root of \(x^2+3x+2=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=-2) gives (4-6+2=0). Be careful with signs when substituting a negative value.
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=-2) gives (4-6+2=0). Be careful with signs when substituting a negative value.
Step 3
Exam Tip
(x=-2) रखने पर (4-6+2=0) मिलता है। ऋणात्मक मान रखते समय चिन्हों पर ध्यान दें।
Login to save your score, XP, coins and progress.
Question 11/14
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
यदि किसी समीकरण के मूल (1) और (-4) हैं तो उनका योग क्या है?
If the roots of an equation are (1) and (-4) then what is their sum?
Explanation opens after your attempt
Step 1
Concept
The sum is (1+(-4)=-3). Be careful with the sign while adding a negative number.
Step 2
Why this answer is correct
The correct answer is B. (-3). The sum is (1+(-4)=-3). Be careful with the sign while adding a negative number.
Step 3
Exam Tip
योग (1+(-4)=-3) है। ऋणात्मक संख्या जोड़ते समय चिन्ह का ध्यान रखें।
Login to save your score, XP, coins and progress.
Question 12/14
Easy Mathematics
Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31
यदि (-2) समीकरण \(x^2+kx+4=0\) का मूल है तो (k) का मान क्या है?
If (-2) is a root of \(x^2+kx+4=0\) then what is the value of (k)?
Explanation opens after your attempt
Step 1
Concept
Putting (x=-2) gives (4-2k+4=0) so (k=4). Be careful with signs while substituting a negative root.
Step 2
Why this answer is correct
The correct answer is B. (4). Putting (x=-2) gives (4-2k+4=0) so (k=4). Be careful with signs while substituting a negative root.
Step 3
Exam Tip
(x=-2) रखने पर (4-2k+4=0) इसलिए (k=4)। ऋणात्मक मूल रखते समय चिन्ह सावधानी से लगाएं।
Login to save your score, XP, coins and progress.
Question 13/14
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29
\(x^2+6x+9=0\) में (x=-3) रखने पर क्या होगा?
What happens when (x=-3) is put in \(x^2+6x+9=0\)?
Explanation opens after your attempt
Correct Answer
A. समीकरण संतुष्ट होता है/The equation is satisfied
Step 1
Concept
((-3)2+6(-3)+9=0). Hence (x=-3) is a solution.
Step 2
Why this answer is correct
The correct answer is A. समीकरण संतुष्ट होता है / The equation is satisfied. ((-3)2+6(-3)+9=0). Hence (x=-3) is a solution.
Step 3
Exam Tip
((-3)2+6(-3)+9=0) है। अतः (x=-3) हल है।
Login to save your score, XP, coins and progress.
Question 14/14
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28
\(x^2+4x+4=0\) में (x=-2) रखने पर क्या होगा?
What happens when (x=-2) is put in \(x^2+4x+4=0\)?
Explanation opens after your attempt
Correct Answer
A. समीकरण संतुष्ट होता है/The equation is satisfied
Step 1
Concept
((-2)2+4(-2)+4=0). Hence (x=-2) is a solution.
Step 2
Why this answer is correct
The correct answer is A. समीकरण संतुष्ट होता है / The equation is satisfied. ((-2)2+4(-2)+4=0). Hence (x=-2) is a solution.
Step 3
Exam Tip
((-2)2+4(-2)+4=0) है। अतः (x=-2) हल है।
Login to save your score, XP, coins and progress.
