Class 10 negative root MCQ Questions

Question 1/27 Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

यदि संख्या रेखा पर \( -\sqrt{122}<x<-11 \), तो कौन सा मान संभव है?

If \( -\sqrt{122}<x<-11 \) on the number line, which value is possible?

Explanation opens after your attempt

Correct Answer

A. ( -11.03 )

Step 1

Concept

\( -\sqrt{122}\approx-11.045 \), so (x) must lie between (-11.045) and (-11). (-11.03) is correct.

Step 2

Why this answer is correct

The correct answer is A. ( -11.03 ). \( -\sqrt{122}\approx-11.045 \), so (x) must lie between (-11.045) and (-11). (-11.03) is correct.

Step 3

Exam Tip

\( -\sqrt{122}\approx-11.045 \), इसलिए (x) को (-11.045) और (-11) के बीच होना चाहिए। (-11.03) सही है।

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Question 2/27 Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

किस संख्या की (0) से दूरी \( \sqrt{41} \) है और वह (0) के बाईं ओर है?

Which number has distance \( \sqrt{41} \) from (0) and lies to the left of (0) on the number line?

Explanation opens after your attempt

Correct Answer

B. \( -\sqrt{41} \)

Step 1

Concept

The point on the left is negative and its distance is \( \sqrt{41} \). Therefore the number is \( -\sqrt{41} \).

Step 2

Why this answer is correct

The correct answer is B. \( -\sqrt{41} \). The point on the left is negative and its distance is \( \sqrt{41} \). Therefore the number is \( -\sqrt{41} \).

Step 3

Exam Tip

बाईं ओर का बिंदु ऋणात्मक होगा और दूरी \( \sqrt{41} \) है। इसलिए संख्या \( -\sqrt{41} \) है।

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Question 3/27 Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर \( -\sqrt{2.56} \) किस बिंदु के बराबर है?

On the number line, \( -\sqrt{2.56} \) is equal to which point?

Explanation opens after your attempt

Correct Answer

A. ( -1.6 )

Step 1

Concept

\( \sqrt{2.56}=1.6 \), so \( -\sqrt{2.56}=-1.6 \). Handle the outside negative sign separately.

Step 2

Why this answer is correct

The correct answer is A. ( -1.6 ). \( \sqrt{2.56}=1.6 \), so \( -\sqrt{2.56}=-1.6 \). Handle the outside negative sign separately.

Step 3

Exam Tip

\( \sqrt{2.56}=1.6 \), इसलिए \( -\sqrt{2.56}=-1.6 \)। बाहर के ऋण चिह्न को अलग से संभालें।

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Question 4/27 Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

यदि \(P=-\sqrt{93}\) और (Q=-9.62) हैं, तो संख्या रेखा पर कौन सा बिंदु अधिक दाईं ओर है?

If \(P=-\sqrt{93}\) and (Q=-9.62), which point is farther right on the number line?

Explanation opens after your attempt

Correct Answer

B. (Q)

Step 1

Concept

\( -\sqrt{93}\approx-9.644 \) and (-9.62) is greater. The greater number lies farther right on the number line.

Step 2

Why this answer is correct

The correct answer is B. (Q). \( -\sqrt{93}\approx-9.644 \) and (-9.62) is greater. The greater number lies farther right on the number line.

Step 3

Exam Tip

\( -\sqrt{93}\approx-9.644 \) और (-9.62) इससे बड़ा है। बड़ी संख्या संख्या रेखा पर दाईं ओर होती है।

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Question 5/27 Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

यदि संख्या रेखा पर \( -\sqrt{82}<x<-9 \), तो कौन सा मान संभव है?

If \( -\sqrt{82}<x<-9 \) on the number line, which value is possible?

Explanation opens after your attempt

Correct Answer

A. ( -9.03 )

Step 1

Concept

\( -\sqrt{82}\approx-9.055 \), so (x) must lie between (-9.055) and (-9). (-9.03) is correct.

Step 2

Why this answer is correct

The correct answer is A. ( -9.03 ). \( -\sqrt{82}\approx-9.055 \), so (x) must lie between (-9.055) and (-9). (-9.03) is correct.

Step 3

Exam Tip

\( -\sqrt{82}\approx-9.055 \), इसलिए (x) को (-9.055) और (-9) के बीच होना चाहिए। (-9.03) सही है।

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Question 6/27 Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

संख्या रेखा पर \( -\sqrt{1.69} \) किस बिंदु के बराबर है?

On the number line, \( -\sqrt{1.69} \) is equal to which point?

Explanation opens after your attempt

Correct Answer

A. ( -1.3 )

Step 1

Concept

\( \sqrt{1.69}=1.3 \), so \( -\sqrt{1.69}=-1.3 \). Handle the outside negative sign separately.

Step 2

Why this answer is correct

The correct answer is A. ( -1.3 ). \( \sqrt{1.69}=1.3 \), so \( -\sqrt{1.69}=-1.3 \). Handle the outside negative sign separately.

Step 3

Exam Tip

\( \sqrt{1.69}=1.3 \), इसलिए \( -\sqrt{1.69}=-1.3 \)। बाहर के ऋण चिह्न को अलग से संभालें।

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Question 7/27 Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 50

यदि \(P=-\sqrt{74}\) और (Q=-8.55) हैं, तो संख्या रेखा पर कौन सा बिंदु अधिक दाईं ओर है?

If \(P=-\sqrt{74}\) and (Q=-8.55), which point is farther right on the number line?

Explanation opens after your attempt

Correct Answer

B. (Q)

Step 1

Concept

\( -\sqrt{74}\approx-8.602 \) and (-8.55) is greater. The greater number lies to the right on a number line.

Step 2

Why this answer is correct

The correct answer is B. (Q). \( -\sqrt{74}\approx-8.602 \) and (-8.55) is greater. The greater number lies to the right on a number line.

Step 3

Exam Tip

\( -\sqrt{74}\approx-8.602 \) और (-8.55) इससे बड़ा है। बड़ी संख्या संख्या रेखा पर दाईं ओर होती है।

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Question 8/27 Hard Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

यदि \( -\sqrt{m} \) संख्या रेखा पर ( -3 ) और ( -2 ) के बीच है, तो (m) के लिए कौन सा मान सही हो सकता है?

If \( -\sqrt{m} \) lies between (-3) and (-2) on the number line, which value of (m) can be correct?

Explanation opens after your attempt

Correct Answer

C. (5)

Step 1

Concept

From \(-3<-\sqrt{m}<-2\), \(2<\sqrt{m}<3\), so (4<m<9). (5) is in the correct range.

Step 2

Why this answer is correct

The correct answer is C. (5). From \(-3<-\sqrt{m}<-2\), \(2<\sqrt{m}<3\), so (4<m<9). (5) is in the correct range.

Step 3

Exam Tip

\(-3<-\sqrt{m}<-2\) से \(2<\sqrt{m}<3\), इसलिए (4<m<9)। (5) सही सीमा में है।

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Question 9/27 Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

यदि संख्या रेखा पर (x) ऐसा है कि \( -\sqrt{50}<x<-7 \), तो कौन सा मान संभव है?

If (x) on the number line satisfies \( -\sqrt{50}<x<-7 \), which value is possible?

Explanation opens after your attempt

Correct Answer

A. ( -7.05 )

Step 1

Concept

\( -\sqrt{50}\approx-7.071 \), so (x) must lie between (-7.071) and (-7). (-7.05) is correct.

Step 2

Why this answer is correct

The correct answer is A. ( -7.05 ). \( -\sqrt{50}\approx-7.071 \), so (x) must lie between (-7.071) and (-7). (-7.05) is correct.

Step 3

Exam Tip

\( -\sqrt{50}\approx-7.071 \), इसलिए (x) को (-7.071) और (-7) के बीच होना चाहिए। (-7.05) सही है।

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Question 10/27 Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

किस संख्या की (0) से दूरी संख्या रेखा पर \( \sqrt{17} \) है और वह (0) के बाईं ओर है?

Which number has distance \( \sqrt{17} \) from (0) and lies to the left of (0) on the number line?

Explanation opens after your attempt

Correct Answer

A. \( -\sqrt{17} \)

Step 1

Concept

The point on the left is negative and its distance is \( \sqrt{17} \). Therefore the number is \( -\sqrt{17} \).

Step 2

Why this answer is correct

The correct answer is A. \( -\sqrt{17} \). The point on the left is negative and its distance is \( \sqrt{17} \). Therefore the number is \( -\sqrt{17} \).

Step 3

Exam Tip

बाईं ओर का बिंदु ऋणात्मक होगा और दूरी \( \sqrt{17} \) है। इसलिए संख्या \( -\sqrt{17} \) है।

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Question 11/27 Expert Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

संख्या रेखा पर \( -\sqrt{0.36} \) किस बिंदु के बराबर है?

On the number line, \( -\sqrt{0.36} \) is equal to which point?

Explanation opens after your attempt

Correct Answer

A. ( -0.6 )

Step 1

Concept

\( \sqrt{0.36}=0.6 \), so \( -\sqrt{0.36}=-0.6 \). Treat the outside negative sign separately.

Step 2

Why this answer is correct

The correct answer is A. ( -0.6 ). \( \sqrt{0.36}=0.6 \), so \( -\sqrt{0.36}=-0.6 \). Treat the outside negative sign separately.

Step 3

Exam Tip

\( \sqrt{0.36}=0.6 \) है इसलिए \( -\sqrt{0.36}=-0.6 \)। बाहर के ऋण चिह्न को अलग से देखें।

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Question 12/27 Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 51

संख्या रेखा पर \(-\sqrt{11}\) किस दो पूर्णांकों के बीच होगा?

Between which two integers will \(-\sqrt{11}\) lie on the number line?

Explanation opens after your attempt

Correct Answer

C. (-4) और (-3)(-4) and (-3)

Step 1

Concept

\(\sqrt{11}\) lies between (3) and (4), so \(-\sqrt{11}\) lies between (-4) and (-3). The negative sign changes the side.

Step 2

Why this answer is correct

The correct answer is C. (-4) और (-3) / (-4) and (-3). \(\sqrt{11}\) lies between (3) and (4), so \(-\sqrt{11}\) lies between (-4) and (-3). The negative sign changes the side.

Step 3

Exam Tip

\(\sqrt{11}\) (3) और (4) के बीच है इसलिए \(-\sqrt{11}\) (-4) और (-3) के बीच होगा। ऋणात्मक चिन्ह दिशा बदल देता है।

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Question 13/27 Medium Mathematics Polynomials Representing real numbers on the number line Class 10 Level 49

कौन सा कथन संख्या रेखा पर \(-\sqrt{4}\) की सही स्थिति बताता है?

Which statement gives the correct position of \(-\sqrt{4}\) on the number line?

Explanation opens after your attempt

Correct Answer

B. यह (-2) पर होगाIt will be at (-2)

Step 1

Concept

\(\sqrt{4}=2\), so \(-\sqrt{4}=-2\). Remember the negative sign after finding the square root.

Step 2

Why this answer is correct

The correct answer is B. यह (-2) पर होगा / It will be at (-2). \(\sqrt{4}=2\), so \(-\sqrt{4}=-2\). Remember the negative sign after finding the square root.

Step 3

Exam Tip

\(\sqrt{4}=2\), इसलिए \(-\sqrt{4}=-2\) होगा। ऋण चिह्न को वर्गमूल लेने के बाद भी याद रखें।

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Question 14/27 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

क्या (x=-3) समीकरण \(2x^2+7x+3=0\) का मूल है?

Is (x=-3) a root of \(2x^2+7x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. हाँYes

Step 1

Concept

Putting (x=-3) gives (18-21+3=0). Watch the signs carefully when substituting a negative root.

Step 2

Why this answer is correct

The correct answer is A. हाँ / Yes. Putting (x=-3) gives (18-21+3=0). Watch the signs carefully when substituting a negative root.

Step 3

Exam Tip

(x=-3) रखने पर (18-21+3=0) मिलता है। ऋणात्मक मूल रखते समय चिन्हों को ध्यान से देखें।

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Question 15/27 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

क्या (x=-2) समीकरण \(3x^2+2x-8=0\) का मूल है?

Is (x=-2) a root of \(3x^2+2x-8=0\)?

Explanation opens after your attempt

Correct Answer

A. हाँYes

Step 1

Concept

Putting (x=-2) gives (12-4-8=0). Handle signs carefully when substituting a negative root.

Step 2

Why this answer is correct

The correct answer is A. हाँ / Yes. Putting (x=-2) gives (12-4-8=0). Handle signs carefully when substituting a negative root.

Step 3

Exam Tip

(x=-2) रखने पर (12-4-8=0) मिलता है। ऋणात्मक मूल रखते समय चिन्हों को ध्यान से संभालें।

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Question 16/27 Medium Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

क्या (x=-1) समीकरण \(2x^2+5x+3=0\) का मूल है?

Is (x=-1) a root of \(2x^2+5x+3=0\)?

Explanation opens after your attempt

Correct Answer

A. हाँYes

Step 1

Concept

Putting (x=-1) gives (2-5+3=0). Check signs carefully for a negative root.

Step 2

Why this answer is correct

The correct answer is A. हाँ / Yes. Putting (x=-1) gives (2-5+3=0). Check signs carefully for a negative root.

Step 3

Exam Tip

(x=-1) रखने पर (2-5+3=0) मिलता है। ऋणात्मक मूल में चिन्हों की जांच ध्यान से करें।

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Question 17/27 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि (x=-4) समीकरण \(2x^2+px-8=0\) का मूल है तो (p) का मान क्या है?

If (x=-4) is a root of \(2x^2+px-8=0\), what is the value of (p)?

Explanation opens after your attempt

Correct Answer

A. (6)

Step 1

Concept

Putting (x=-4) gives (32-4p-8=0), so (p=6). Check signs carefully with a negative root.

Step 2

Why this answer is correct

The correct answer is A. (6). Putting (x=-4) gives (32-4p-8=0), so (p=6). Check signs carefully with a negative root.

Step 3

Exam Tip

(x=-4) रखने पर (32-4p-8=0) इसलिए (p=6) मिलता है। ऋणात्मक मूल में चिन्हों की जांच सावधानी से करें।

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Question 18/27 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि किसी समीकरण के मूल (4) और (-7) हैं तो उनका योग क्या है?

If the roots of an equation are (4) and (-7), what is their sum?

Explanation opens after your attempt

Correct Answer

B. (-3)

Step 1

Concept

The sum is (4+(-7)=-3). Be careful with the sign while adding a negative number.

Step 2

Why this answer is correct

The correct answer is B. (-3). The sum is (4+(-7)=-3). Be careful with the sign while adding a negative number.

Step 3

Exam Tip

योग (4+(-7)=-3) है। ऋणात्मक संख्या जोड़ते समय चिन्ह का ध्यान रखें।

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Question 19/27 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि (-3) समीकरण \(x^2+ux-18=0\) का मूल है तो (u) का मान क्या है?

If (-3) is a root of \(x^2+ux-18=0\), what is the value of (u)?

Explanation opens after your attempt

Correct Answer

A. (-9)

Step 1

Concept

Putting (x=-3) gives (9-3u-18=0), so (u=-3), not (u=3).

Step 2

Why this answer is correct

The correct answer is A. (-9). Putting (x=-3) gives (9-3u-18=0), so (u=-3), not (u=3).

Step 3

Exam Tip

(x=-3) रखने पर (9-3u-18=0) इसलिए (u=-3) नहीं बल्कि (u=-3)?

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Question 20/27 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

क्या (x=-1) समीकरण \(2x^2+x-1=0\) का मूल है?

Is (x=-1) a root of \(2x^2+x-1=0\)?

Explanation opens after your attempt

Correct Answer

A. हाँYes

Step 1

Concept

Putting (x=-1) gives (2-1-1=0). Sign checking is important with a negative root.

Step 2

Why this answer is correct

The correct answer is A. हाँ / Yes. Putting (x=-1) gives (2-1-1=0). Sign checking is important with a negative root.

Step 3

Exam Tip

(x=-1) रखने पर (2-1-1=0) मिलता है। ऋणात्मक मूल में चिन्हों की जांच जरूरी है।

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Question 21/27 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि किसी समीकरण के मूल (2) और (-5) हैं तो उनका योग क्या है?

If the roots of an equation are (2) and (-5), what is their sum?

Explanation opens after your attempt

Correct Answer

B. (-3)

Step 1

Concept

The sum is (2+(-5)=-3). Do not forget the sign while adding a negative root.

Step 2

Why this answer is correct

The correct answer is B. (-3). The sum is (2+(-5)=-3). Do not forget the sign while adding a negative root.

Step 3

Exam Tip

योग (2+(-5)=-3) है। ऋणात्मक मूल जोड़ते समय चिन्ह न भूलें।

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Question 22/27 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि (-1) समीकरण \(x^2+rx-12=0\) का मूल है तो (r) का मान क्या है?

If (-1) is a root of \(x^2+rx-12=0\), what is the value of (r)?

Explanation opens after your attempt

Correct Answer

A. (-11)

Step 1

Concept

Putting (x=-1) gives (1-r-12=0), so (r=-11). Check the sign of each term while using a negative root.

Step 2

Why this answer is correct

The correct answer is A. (-11). Putting (x=-1) gives (1-r-12=0), so (r=-11). Check the sign of each term while using a negative root.

Step 3

Exam Tip

(x=-1) रखने पर (1-r-12=0) इसलिए (r=-11)। ऋणात्मक मूल रखते समय प्रत्येक पद का चिन्ह देखें।

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Question 23/27 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

क्या (x=-2) समीकरण \(x^2+3x+2=0\) का मूल है?

Is (x=-2) a root of \(x^2+3x+2=0\)?

Explanation opens after your attempt

Correct Answer

A. हाँYes

Step 1

Concept

Putting (x=-2) gives (4-6+2=0). Be careful with signs when substituting a negative value.

Step 2

Why this answer is correct

The correct answer is A. हाँ / Yes. Putting (x=-2) gives (4-6+2=0). Be careful with signs when substituting a negative value.

Step 3

Exam Tip

(x=-2) रखने पर (4-6+2=0) मिलता है। ऋणात्मक मान रखते समय चिन्हों पर ध्यान दें।

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Question 24/27 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि किसी समीकरण के मूल (1) और (-4) हैं तो उनका योग क्या है?

If the roots of an equation are (1) and (-4) then what is their sum?

Explanation opens after your attempt

Correct Answer

B. (-3)

Step 1

Concept

The sum is (1+(-4)=-3). Be careful with the sign while adding a negative number.

Step 2

Why this answer is correct

The correct answer is B. (-3). The sum is (1+(-4)=-3). Be careful with the sign while adding a negative number.

Step 3

Exam Tip

योग (1+(-4)=-3) है। ऋणात्मक संख्या जोड़ते समय चिन्ह का ध्यान रखें।

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Question 25/27 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि (-2) समीकरण \(x^2+kx+4=0\) का मूल है तो (k) का मान क्या है?

If (-2) is a root of \(x^2+kx+4=0\) then what is the value of (k)?

Explanation opens after your attempt

Correct Answer

B. (4)

Step 1

Concept

Putting (x=-2) gives (4-2k+4=0) so (k=4). Be careful with signs while substituting a negative root.

Step 2

Why this answer is correct

The correct answer is B. (4). Putting (x=-2) gives (4-2k+4=0) so (k=4). Be careful with signs while substituting a negative root.

Step 3

Exam Tip

(x=-2) रखने पर (4-2k+4=0) इसलिए (k=4)। ऋणात्मक मूल रखते समय चिन्ह सावधानी से लगाएं।

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Question 26/27 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

\(x^2+6x+9=0\) में (x=-3) रखने पर क्या होगा?

What happens when (x=-3) is put in \(x^2+6x+9=0\)?

Explanation opens after your attempt

Correct Answer

A. समीकरण संतुष्ट होता हैThe equation is satisfied

Step 1

Concept

((-3)²+6(-3)+9=0). Hence (x=-3) is a solution.

Step 2

Why this answer is correct

The correct answer is A. समीकरण संतुष्ट होता है / The equation is satisfied. ((-3)²+6(-3)+9=0). Hence (x=-3) is a solution.

Step 3

Exam Tip

((-3)²+6(-3)+9=0) है। अतः (x=-3) हल है।

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Question 27/27 Easy Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28

\(x^2+4x+4=0\) में (x=-2) रखने पर क्या होगा?

What happens when (x=-2) is put in \(x^2+4x+4=0\)?

Explanation opens after your attempt

Correct Answer

A. समीकरण संतुष्ट होता हैThe equation is satisfied

Step 1

Concept

((-2)²+4(-2)+4=0). Hence (x=-2) is a solution.

Step 2

Why this answer is correct

The correct answer is A. समीकरण संतुष्ट होता है / The equation is satisfied. ((-2)²+4(-2)+4=0). Hence (x=-2) is a solution.

Step 3

Exam Tip

((-2)²+4(-2)+4=0) है। अतः (x=-2) हल है।

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