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If ( -\sqrt{122}<x<-11 ) on the number line, which value is possible?

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Answer and explanation

Correct answer: ( -11.03 )

( -\sqrt{122}\approx-11.045 ), so (x) must lie between (-11.045) and (-11). (-11.03) is correct.

Related tags

Number-LineInequalityNegative-Root

Frequently asked questions

What is the correct answer to this question?

( -11.03 )

Why is this the correct answer?

( -\sqrt{122}\approx-11.045 ), so (x) must lie between (-11.045) and (-11). (-11.03) is correct.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Representing real numbers on the number line.

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