किस (k) के लिए \(x=\sqrt{2}\) बहुपद \(x^2+kx-2\) का शून्यक होगा?

For which (k) will \(x=\sqrt{2}\) be a zero of the polynomial \(x^2+kx-2\)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

Substitution gives \(2+k\sqrt{2}-2=k\sqrt{2}=0\), so (k=0). In exams write (p\(\alpha\)=0) for a zero.

Step 2

Why this answer is correct

The correct answer is A. (0). Substitution gives \(2+k\sqrt{2}-2=k\sqrt{2}=0\), so (k=0). In exams write (p\(\alpha\)=0) for a zero.

Step 3

Exam Tip

रखने पर \(2+k\sqrt{2}-2=k\sqrt{2}=0\), इसलिए (k=0) है। परीक्षा में शून्यक होने पर (p\(\alpha\)=0) लिखें।

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Mathematics Answer, Explanation and Revision Hints

किस (k) के लिए \(x=\sqrt{2}\) बहुपद \(x^2+kx-2\) का शून्यक होगा? / For which (k) will \(x=\sqrt{2}\) be a zero of the polynomial \(x^2+kx-2\)?

Correct Answer: A. (0). Explanation: रखने पर \(2+k\sqrt{2}-2=k\sqrt{2}=0\), इसलिए (k=0) है। परीक्षा में शून्यक होने पर (p\(\alpha\)=0) लिखें। / Substitution gives \(2+k\sqrt{2}-2=k\sqrt{2}=0\), so (k=0). In exams write (p\(\alpha\)=0) for a zero.

Which concept should I revise for this Mathematics MCQ?

Substitution gives \(2+k\sqrt{2}-2=k\sqrt{2}=0\), so (k=0). In exams write (p\(\alpha\)=0) for a zero.

What exam hint can help solve this Mathematics question?

रखने पर \(2+k\sqrt{2}-2=k\sqrt{2}=0\), इसलिए (k=0) है। परीक्षा में शून्यक होने पर (p\(\alpha\)=0) लिखें।