sum_zeroes se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.
9 questions tagged with sum_zeroes.
If (p(x)=5x-2-20x+20), what is the sum of its zeroes?
A. (4)
योग \(-\frac{b}{a}=-\frac{-20}{5}=4\) है। पहले सामान्य गुणनखंड निकालना चाहें तो भी योग वही रहेगा। / The sum is \(-\frac{b}{a}=-\frac{-20}{5}=4\). Even if a common factor is removed first, the sum remains the same.
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If one zero of (p(x)=x-2-10x+r) is (4), what is the other zero?
A. (6)
शून्यकों का योग (10) है। एक शून्यक (4) है, इसलिए दूसरा (10-4=6) है। / The sum of zeroes is (10). Since one zero is (4), the other is (10-4=6).
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If the sum of zeroes of (p(x)=3x-2+(m-1)x-2) is (0), what is (m)?
A. (1)
योग \(-\frac{m-1}{3}\) है, इसे (0) रखने पर (m-1=0) मिलता है। शून्य योग में (x) का गुणांक (0) हो जाता है। / The sum is \(-\frac{m-1}{3}\); setting it to (0) gives (m-1=0). When the sum is zero, the coefficient of (x) becomes zero.
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If the sum of zeroes of (p(x)=x-2-2(k+1)x+k-2) is (10), what is (k)?
A. (4)
शून्यकों का योग (2(k+1)) है, इसलिए (2(k+1)=10) और (k=4)। सूत्र लगाते समय ऋण चिह्न संभालें। / The sum of zeroes is (2(k+1)), so (2(k+1)=10) and (k=4). Handle the negative sign carefully in the formula.
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If (p(x)=2x-2-7x+3), what is the sum of its zeroes?
A. \(\frac{7}{2}\)
द्विघात \(ax^2+bx+c\) में शून्यकों का योग \(-\frac{b}{a}\) होता है। यहाँ \(-\frac{-7}{2}=\frac{7}{2}\) है। / For \(ax^2+bx+c\), the sum of zeroes is \(-\frac{b}{a}\). Here \(-\frac{-7}{2}=\frac{7}{2}\).
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A. \(-\frac{5}{2}\)
द्विघात \(ax^2+bx+c\) के लिए शून्यकों का योग \(-\frac{b}{a}\) होता है। इसलिए \(\alpha+\beta=-\frac{5}{2}\)। / For \(ax^2+bx+c\), the sum of zeroes is \(-\frac{b}{a}\). Hence \(\alpha+\beta=-\frac{5}{2}\).
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The sum of zeroes of the quadratic polynomial \(kx^2+6x+4\) is (-3). What is (k)?
A. (2)
योग \(-\frac{6}{k}\) है और यह (-3) है। इसलिए (k=2) होगा। / The sum is \(-\frac{6}{k}\), and it equals (-3). Therefore, (k=2).
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If \(\alpha\) and \(\beta\) are zeroes of \(3x^2+2x-1\), what is (\(\alpha+\beta\)2)?
A. \(\frac{4}{9}\)
\(\alpha+\beta=-\frac{2}{3}\) है। इसलिए (\(\alpha+\beta\)2=\frac{4}{9}) होगा। / \(\alpha+\beta=-\frac{2}{3}\). Therefore, (\(\alpha+\beta\)2=\frac{4}{9}).
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If the sum of zeroes of (p(x)=2x-2+kx+8) is (3), what is (k)?
B. (-6)
योग \(-\frac{k}{2}\) होता है और यह (3) है। इसलिए (k=-6) है। / The sum is \(-\frac{k}{2}\), and it equals (3). Hence (k=-6).
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