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square MCQ Questions for Class 10

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80 questions tagged with square.

Question 1/80 Medium Art Education Fundamentals of Visual Arts Elements of Art Class 10 Level 1

किस कारण से वर्ग को ज्यामितीय आकार कहा जाता है?

Why is a square called a geometric shape?

Explanation opens after your attempt
Correct Answer

C. क्योंकि उसकी भुजाएं और कोण नियमित होते हैंBecause its sides and angles are regular

Step 1

Concept

A square is a regular rule-based shape. Exam tip: treat measured and regular shapes as geometric.

Step 2

Why this answer is correct

The correct answer is C. क्योंकि उसकी भुजाएं और कोण नियमित होते हैं / Because its sides and angles are regular. A square is a regular rule-based shape. Exam tip: treat measured and regular shapes as geometric.

Step 3

Exam Tip

वर्ग नियमित नियमों वाला आकार है। परीक्षा में measured and regular shapes को geometric मानें।

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Question 2/80 Easy Art Education Fundamentals of Visual Arts Elements of Art Class 10 Level 5

चार बराबर भुजाओं वाला नियमित आकार कौन सा है?

Which regular shape has four equal sides?

Explanation opens after your attempt
Correct Answer

B. वर्गSquare

Step 1

Concept

A square has four equal sides. Exam tip: remember square for equal sides.

Step 2

Why this answer is correct

The correct answer is B. वर्ग / Square. A square has four equal sides. Exam tip: remember square for equal sides.

Step 3

Exam Tip

वर्ग में चार बराबर भुजाएं होती हैं। परीक्षा में equal sides के लिए square याद रखें।

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Question 3/80 Easy Art Education Fundamentals of Visual Arts Elements of Art Class 10 Level 5

किस आकार में स्पष्ट कोने और सीधी भुजाएं होती हैं?

Which shape has clear corners and straight sides?

Explanation opens after your attempt
Correct Answer

C. वर्गSquare

Step 1

Concept

A square has clear corners and straight sides. Exam tip: treat square as a geometric shape.

Step 2

Why this answer is correct

The correct answer is C. वर्ग / Square. A square has clear corners and straight sides. Exam tip: treat square as a geometric shape.

Step 3

Exam Tip

वर्ग में स्पष्ट कोने और सीधी भुजाएं होती हैं। परीक्षा में square को geometric shape मानें।

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Question 4/80 Easy Art Education Fundamentals of Visual Arts Elements of Art Class 10 Level 4

किस आकार को नियमित और गणितीय माना जाता है?

Which shape is considered regular and mathematical?

Explanation opens after your attempt
Correct Answer

B. वर्गSquare

Step 1

Concept

A square is a regular geometric shape with equal sides. Exam tip: understand rule-based shapes as geometric.

Step 2

Why this answer is correct

The correct answer is B. वर्ग / Square. A square is a regular geometric shape with equal sides. Exam tip: understand rule-based shapes as geometric.

Step 3

Exam Tip

वर्ग समान भुजाओं वाला नियमित ज्यामितीय आकार है। परीक्षा में नियम वाले आकार को ज्यामितीय समझें।

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Question 5/80 Easy Art Education Fundamentals of Visual Arts Elements of Art Class 10 Level 3

यदि किसी चित्र में केवल वृत्त और वर्ग हैं तो कौन सा तत्व प्रमुख है?

If a picture has only circles and squares which element is prominent?

Explanation opens after your attempt
Correct Answer

B. आकारShape

Step 1

Concept

Circles and squares are examples of shapes. Exam tip: write flat closed figures as shapes.

Step 2

Why this answer is correct

The correct answer is B. आकार / Shape. Circles and squares are examples of shapes. Exam tip: write flat closed figures as shapes.

Step 3

Exam Tip

वृत्त और वर्ग आकार के उदाहरण हैं। परीक्षा में flat closed figures को shapes लिखें।

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Question 6/80 Easy Art Education Fundamentals of Visual Arts Elements of Art Class 10 Level 1

वर्ग और आयत किस प्रकार के आकार हैं?

Square and rectangle are which type of shapes?

Explanation opens after your attempt
Correct Answer

C. ज्यामितीय आकारGeometric shapes

Step 1

Concept

Square and rectangle are geometric shapes with clear rules. Exam tip: understand regular shapes as geometric.

Step 2

Why this answer is correct

The correct answer is C. ज्यामितीय आकार / Geometric shapes. Square and rectangle are geometric shapes with clear rules. Exam tip: understand regular shapes as geometric.

Step 3

Exam Tip

वर्ग और आयत स्पष्ट नियमों वाले ज्यामितीय आकार हैं। परीक्षा में नियमित आकार को ज्यामितीय समझें।

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Question 7/80 Hard Mathematics Polynomials Polynomials in one variable Class 10 Level 46

यदि \(3x^2+2x-1\) के शून्यक \(\alpha\) और \(\beta\) हैं, तो (\(\alpha+\beta\)2) का मान क्या है?

If \(\alpha\) and \(\beta\) are zeroes of \(3x^2+2x-1\), what is (\(\alpha+\beta\)2)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{4}{9}\)

Step 1

Concept

\(\alpha+\beta=-\frac{2}{3}\). Therefore, (\(\alpha+\beta\)2=\frac{4}{9}).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{4}{9}\). \(\alpha+\beta=-\frac{2}{3}\). Therefore, (\(\alpha+\beta\)2=\frac{4}{9}).

Step 3

Exam Tip

\(\alpha+\beta=-\frac{2}{3}\) है। इसलिए (\(\alpha+\beta\)2=\frac{4}{9}) होगा।

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Question 8/80 Medium Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

\(104^2\) का मान क्या है?

What is the value of \(104^2\)?

Explanation opens after your attempt
Correct Answer

A. (10816)

Step 1

Concept

(1042=(100+4)2=10000+800+16=10816). Do not forget the middle term in ((a+b)2).

Step 2

Why this answer is correct

The correct answer is A. (10816). (1042=(100+4)2=10000+800+16=10816). Do not forget the middle term in ((a+b)2).

Step 3

Exam Tip

(1042=(100+4)2=10000+800+16=10816)। ((a+b)2) में मध्य पद न भूलें।

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Question 9/80 Medium Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 44

\(103^2\) का मान क्या है?

What is the value of \(103^2\)?

Explanation opens after your attempt
Correct Answer

A. (10609)

Step 1

Concept

(1032=(100+3)2=10000+600+9=10609). Do not forget the middle term in ((a+b)2).

Step 2

Why this answer is correct

The correct answer is A. (10609). (1032=(100+3)2=10000+600+9=10609). Do not forget the middle term in ((a+b)2).

Step 3

Exam Tip

(1032=(100+3)2=10000+600+9=10609)। ((a+b)2) में मध्य पद न भूलें।

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Question 10/80 Medium Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 43

\(102^2\) का मान क्या है?

What is the value of \(102^2\)?

Explanation opens after your attempt
Correct Answer

A. (10404)

Step 1

Concept

(1022=(100+2)2=10000+400+4=10404). Do not forget the middle term in ((a+b)2).

Step 2

Why this answer is correct

The correct answer is A. (10404). (1022=(100+2)2=10000+400+4=10404). Do not forget the middle term in ((a+b)2).

Step 3

Exam Tip

(1022=(100+2)2=10000+400+4=10404)। ((a+b)2) में मध्य पद न भूलें।

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Question 11/80 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक धनात्मक संख्या का वर्ग उसके (11) गुने से (60) अधिक है। संख्या क्या है?

The square of a positive number is (60) more than (11) times the number. What is the number?

Explanation opens after your attempt
Correct Answer

B. (15)

Step 1

Concept

The equation is \(x^2=11x+60\). From \(x^2-11x-60=0\), the positive root is (x=15).

Step 2

Why this answer is correct

The correct answer is B. (15). The equation is \(x^2=11x+60\). From \(x^2-11x-60=0\), the positive root is (x=15).

Step 3

Exam Tip

समीकरण \(x^2=11x+60\) है। \(x^2-11x-60=0\) से धनात्मक हल (x=15) है।

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Question 12/80 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक संख्या के वर्ग में उस संख्या का (9) गुना जोड़ने पर (400) मिलता है। धनात्मक संख्या क्या है?

When (9) times a number is added to its square, the result is (400). What is the positive number?

Explanation opens after your attempt
Correct Answer

A. (16)

Step 1

Concept

The equation is \(x^2+9x=400\). From \(x^2+9x-400=0\), the positive root is (x=16).

Step 2

Why this answer is correct

The correct answer is A. (16). The equation is \(x^2+9x=400\). From \(x^2+9x-400=0\), the positive root is (x=16).

Step 3

Exam Tip

समीकरण \(x^2+9x=400\) है। \(x^2+9x-400=0\) से धनात्मक हल (x=16) है।

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Question 13/80 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक वर्गाकार मैदान की भुजा (4) मीटर बढ़ाने पर क्षेत्रफल (96) वर्ग मीटर बढ़ जाता है। मूल भुजा कितनी थी?

When the side of a square field is increased by (4) m, its area increases by (96) square m. What was the original side?

Explanation opens after your attempt
Correct Answer

B. (10) मीटर(10) m

Step 1

Concept

If the original side is (x), then ((x+4)2-x-2=96). Thus (8x+16=96), giving (x=10).

Step 2

Why this answer is correct

The correct answer is B. (10) मीटर / (10) m. If the original side is (x), then ((x+4)2-x-2=96). Thus (8x+16=96), giving (x=10).

Step 3

Exam Tip

मूल भुजा (x) हो तो ((x+4)2-x-2=96)। इससे (8x+16=96) और (x=10) मिलता है।

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Question 14/80 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक तार को वर्ग के रूप में मोड़ने पर क्षेत्रफल (3025) वर्ग सेमी है। तार की लंबाई क्या है?

A wire is bent into a square and the area is (3025) square cm. What is the length of the wire?

Explanation opens after your attempt
Correct Answer

C. (220) सेमी(220) cm

Step 1

Concept

If the side of the square is (x), then \(x^2=3025\), so (x=55). The wire length is the perimeter (4x=220) cm.

Step 2

Why this answer is correct

The correct answer is C. (220) सेमी / (220) cm. If the side of the square is (x), then \(x^2=3025\), so (x=55). The wire length is the perimeter (4x=220) cm.

Step 3

Exam Tip

वर्ग की भुजा (x) हो तो \(x^2=3025\), इसलिए (x=55) है। तार की लंबाई परिमाप (4x=220) सेमी होगी।

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Question 15/80 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक वर्ग की भुजा (x) सेमी है। भुजा (9) सेमी घटाने पर क्षेत्रफल (1681) वर्ग सेमी हो जाता है। मूल भुजा क्या है?

The side of a square is (x) cm. When the side is reduced by (9) cm, the area becomes (1681) square cm. What is the original side?

Explanation opens after your attempt
Correct Answer

C. (50) सेमी(50) cm

Step 1

Concept

((x-9)2=1681) gives (x-9=41), so (x=50). Write the reduced side as (x-9).

Step 2

Why this answer is correct

The correct answer is C. (50) सेमी / (50) cm. ((x-9)2=1681) gives (x-9=41), so (x=50). Write the reduced side as (x-9).

Step 3

Exam Tip

((x-9)2=1681) से (x-9=41), इसलिए (x=50) है। घटाई गई भुजा को (x-9) लिखें।

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Question 16/80 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक वर्गाकार मैदान की भुजा (x) मीटर है। यदि भुजा (12) मीटर बढ़ाने पर क्षेत्रफल (2448) वर्ग मीटर बढ़ता है, तो (x) क्या है?

A square field has side (x) m. If increasing the side by (12) m increases the area by (2448) square m, what is (x)?

Explanation opens after your attempt
Correct Answer

C. (96)

Step 1

Concept

The area increase is ((x+12)2-x-2=2448). This gives (24x+144=2448), so (x=96).

Step 2

Why this answer is correct

The correct answer is C. (96). The area increase is ((x+12)2-x-2=2448). This gives (24x+144=2448), so (x=96).

Step 3

Exam Tip

क्षेत्रफल वृद्धि ((x+12)2-x-2=2448) है। इससे (24x+144=2448), इसलिए (x=96) है।

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Question 17/80 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक संख्या के वर्ग में (975) घटाने पर (2625) मिलता है। धनात्मक संख्या क्या है?

When (975) is subtracted from the square of a number, the result is (2625). What is the positive number?

Explanation opens after your attempt
Correct Answer

C. (60)

Step 1

Concept

\(x^2-975=2625\) gives \(x^2=3600\), so (x=60). Write the subtraction sign carefully.

Step 2

Why this answer is correct

The correct answer is C. (60). \(x^2-975=2625\) gives \(x^2=3600\), so (x=60). Write the subtraction sign carefully.

Step 3

Exam Tip

\(x^2-975=2625\) से \(x^2=3600\), इसलिए (x=60) है। घटाव के चिन्ह को ध्यान से लिखें।

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Question 18/80 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक संख्या के वर्ग में (399) जोड़ने पर (3208) मिलता है। धनात्मक संख्या क्या है?

When (399) is added to the square of a number, the result is (3208). What is the positive number?

Explanation opens after your attempt
Correct Answer

C. (53)

Step 1

Concept

\(x^2+399=3208\) gives \(x^2=2809\), so (x=53). First move the constant to the other side.

Step 2

Why this answer is correct

The correct answer is C. (53). \(x^2+399=3208\) gives \(x^2=2809\), so (x=53). First move the constant to the other side.

Step 3

Exam Tip

\(x^2+399=3208\) से \(x^2=2809\), इसलिए (x=53) है। पहले स्थिर संख्या को दूसरी तरफ ले जाएँ।

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Question 19/80 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक वर्गाकार टाइल की भुजा (x-12) सेमी है और क्षेत्रफल (1849) वर्ग सेमी है। (x) क्या है?

The side of a square tile is (x-12) cm and its area is (1849) square cm. What is (x)?

Explanation opens after your attempt
Correct Answer

C. (55)

Step 1

Concept

((x-12)2=1849) and (x-12=43), so (x=55). Remember that the side must be positive.

Step 2

Why this answer is correct

The correct answer is C. (55). ((x-12)2=1849) and (x-12=43), so (x=55). Remember that the side must be positive.

Step 3

Exam Tip

((x-12)2=1849) और (x-12=43), इसलिए (x=55) है। भुजा धनात्मक होने की शर्त याद रखें।

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Question 20/80 Expert Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 40

एक वर्ग की भुजा (x+17) सेमी है। उसका क्षेत्रफल (3249) वर्ग सेमी है। (x) का मान क्या है?

The side of a square is (x+17) cm. Its area is (3249) square cm. What is the value of (x)?

Explanation opens after your attempt
Correct Answer

C. (40)

Step 1

Concept

((x+17)2=3249) gives (x+17=57), so (x=40). Take the positive square root for length.

Step 2

Why this answer is correct

The correct answer is C. (40). ((x+17)2=3249) gives (x+17=57), so (x=40). Take the positive square root for length.

Step 3

Exam Tip

((x+17)2=3249) से (x+17=57), इसलिए (x=40) है। लंबाई के लिए धनात्मक वर्गमूल लें।

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Question 21/80 Hard Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक तार को वर्ग के रूप में मोड़ने पर क्षेत्रफल (2025) वर्ग सेमी है। तार की लंबाई क्या है?

A wire is bent into a square and the area is (2025) square cm. What is the length of the wire?

Explanation opens after your attempt
Correct Answer

B. (180) सेमी(180) cm

Step 1

Concept

If the side of the square is (x), then \(x^2=2025\), so (x=45). The wire length is the perimeter (4x=180) cm.

Step 2

Why this answer is correct

The correct answer is B. (180) सेमी / (180) cm. If the side of the square is (x), then \(x^2=2025\), so (x=45). The wire length is the perimeter (4x=180) cm.

Step 3

Exam Tip

वर्ग की भुजा (x) हो तो \(x^2=2025\), इसलिए (x=45) है। तार की लंबाई परिमाप (4x=180) सेमी होगी।

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Question 22/80 Hard Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक वर्ग की भुजा (x) सेमी है। भुजा (7) सेमी घटाने पर क्षेत्रफल (1296) वर्ग सेमी हो जाता है। मूल भुजा क्या है?

The side of a square is (x) cm. When the side is reduced by (7) cm, the area becomes (1296) square cm. What is the original side?

Explanation opens after your attempt
Correct Answer

C. (43) सेमी(43) cm

Step 1

Concept

((x-7)2=1296) gives (x-7=36), so (x=43). Write the reduced side as (x-7).

Step 2

Why this answer is correct

The correct answer is C. (43) सेमी / (43) cm. ((x-7)2=1296) gives (x-7=36), so (x=43). Write the reduced side as (x-7).

Step 3

Exam Tip

((x-7)2=1296) से (x-7=36), इसलिए (x=43) है। घटाई गई भुजा को (x-7) लिखें।

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Question 23/80 Hard Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक वर्गाकार मैदान की भुजा (x) मीटर है। यदि भुजा (10) मीटर बढ़ाने पर क्षेत्रफल (1700) वर्ग मीटर बढ़ता है, तो (x) क्या है?

A square field has side (x) m. If increasing the side by (10) m increases the area by (1700) square m, what is (x)?

Explanation opens after your attempt
Correct Answer

B. (80)

Step 1

Concept

The area increase is ((x+10)2-x-2=1700). This gives (20x+100=1700), so (x=80).

Step 2

Why this answer is correct

The correct answer is B. (80). The area increase is ((x+10)2-x-2=1700). This gives (20x+100=1700), so (x=80).

Step 3

Exam Tip

क्षेत्रफल वृद्धि ((x+10)2-x-2=1700) है। इससे (20x+100=1700), इसलिए (x=80) है।

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Question 24/80 Hard Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक वर्गाकार टाइल की भुजा (x-13) सेमी है और क्षेत्रफल (1600) वर्ग सेमी है। (x) क्या है?

The side of a square tile is (x-13) cm and its area is (1600) square cm. What is (x)?

Explanation opens after your attempt
Correct Answer

C. (53)

Step 1

Concept

((x-13)2=1600) and (x-13=40), so (x=53). Remember that the side must be positive.

Step 2

Why this answer is correct

The correct answer is C. (53). ((x-13)2=1600) and (x-13=40), so (x=53). Remember that the side must be positive.

Step 3

Exam Tip

((x-13)2=1600) और (x-13=40), इसलिए (x=53) है। भुजा धनात्मक होने की शर्त याद रखें।

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Question 25/80 Hard Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 42

एक वर्ग की भुजा (x+12) सेमी है। उसका क्षेत्रफल (1764) वर्ग सेमी है। (x) का मान क्या है?

The side of a square is (x+12) cm. Its area is (1764) square cm. What is the value of (x)?

Explanation opens after your attempt
Correct Answer

C. (30)

Step 1

Concept

((x+12)2=1764) gives (x+12=42), so (x=30). Take the positive square root for length.

Step 2

Why this answer is correct

The correct answer is C. (30). ((x+12)2=1764) gives (x+12=42), so (x=30). Take the positive square root for length.

Step 3

Exam Tip

((x+12)2=1764) से (x+12=42), इसलिए (x=30) है। लंबाई के लिए धनात्मक वर्गमूल लें।

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Question 26/80 Hard Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक तार को वर्ग के रूप में मोड़ने पर क्षेत्रफल (1296) वर्ग सेमी है। तार की लंबाई क्या है?

A wire is bent into a square and the area is (1296) square cm. What is the length of the wire?

Explanation opens after your attempt
Correct Answer

C. (144) सेमी(144) cm

Step 1

Concept

If the side of the square is (x), then \(x^2=1296\), so (x=36). The wire length is the perimeter (4x=144) cm.

Step 2

Why this answer is correct

The correct answer is C. (144) सेमी / (144) cm. If the side of the square is (x), then \(x^2=1296\), so (x=36). The wire length is the perimeter (4x=144) cm.

Step 3

Exam Tip

वर्ग की भुजा (x) हो तो \(x^2=1296\), इसलिए (x=36) है। तार की लंबाई परिमाप (4x=144) सेमी होगी।

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Question 27/80 Hard Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक वर्ग की भुजा (x) सेमी है। भुजा (5) सेमी घटाने पर क्षेत्रफल (784) वर्ग सेमी हो जाता है। मूल भुजा क्या है?

The side of a square is (x) cm. When the side is reduced by (5) cm, the area becomes (784) square cm. What is the original side?

Explanation opens after your attempt
Correct Answer

C. (33) सेमी(33) cm

Step 1

Concept

((x-5)2=784) gives (x-5=28), so (x=33). Write the reduced side as (x-5).

Step 2

Why this answer is correct

The correct answer is C. (33) सेमी / (33) cm. ((x-5)2=784) gives (x-5=28), so (x=33). Write the reduced side as (x-5).

Step 3

Exam Tip

((x-5)2=784) से (x-5=28), इसलिए (x=33) है। घटाई गई भुजा को (x-5) लिखें।

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Question 28/80 Hard Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक वर्गाकार मैदान की भुजा (x) मीटर है। यदि भुजा (8) मीटर बढ़ाने पर क्षेत्रफल (1216) वर्ग मीटर बढ़ता है, तो (x) क्या है?

A square field has side (x) m. If increasing the side by (8) m increases the area by (1216) square m, what is (x)?

Explanation opens after your attempt
Correct Answer

B. (72)

Step 1

Concept

The area increase is ((x+8)2-x-2=1216). This gives (16x+64=1216), so (x=72).

Step 2

Why this answer is correct

The correct answer is B. (72). The area increase is ((x+8)2-x-2=1216). This gives (16x+64=1216), so (x=72).

Step 3

Exam Tip

क्षेत्रफल वृद्धि ((x+8)2-x-2=1216) है। इससे (16x+64=1216), इसलिए (x=72) है।

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Question 29/80 Hard Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक संख्या के वर्ग में (256) घटाने पर (1040) मिलता है। धनात्मक संख्या क्या है?

When (256) is subtracted from the square of a number, the result is (1040). What is the positive number?

Explanation opens after your attempt
Correct Answer

C. (36)

Step 1

Concept

\(x^2-256=1040\) gives \(x^2=1296\), so (x=36). Write the subtraction sign carefully.

Step 2

Why this answer is correct

The correct answer is C. (36). \(x^2-256=1040\) gives \(x^2=1296\), so (x=36). Write the subtraction sign carefully.

Step 3

Exam Tip

\(x^2-256=1040\) से \(x^2=1296\), इसलिए (x=36) है। घटाव के चिन्ह को ध्यान से लिखें।

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Question 30/80 Hard Mathematics Quadratic Equations Word Problems and Applications Class 10 Level 41

एक वर्गाकार टाइल की भुजा (x-8) सेमी है और क्षेत्रफल (900) वर्ग सेमी है। (x) क्या है?

The side of a square tile is (x-8) cm and its area is (900) square cm. What is (x)?

Explanation opens after your attempt
Correct Answer

C. (38)

Step 1

Concept

((x-8)2=900) and (x-8=30), so (x=38). Remember that the side must be positive.

Step 2

Why this answer is correct

The correct answer is C. (38). ((x-8)2=900) and (x-8=30), so (x=38). Remember that the side must be positive.

Step 3

Exam Tip

((x-8)2=900) और (x-8=30), इसलिए (x=38) है। भुजा धनात्मक होने की शर्त याद रखें।

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