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2 results found for "conjugate fraction" in Class 10.

Question Expert Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

यदि \(x=\frac{\sqrt{10}+\sqrt{6}}{\sqrt{10}-\sqrt{6}}\), तो (x) का सरल रूप क्या है?

If \(x=\frac{\sqrt{10}+\sqrt{6}}{\sqrt{10}-\sqrt{6}}\), what is the simplified form of (x)?

Explanation opens after your attempt
Correct Answer

A. \(4+\sqrt{15}\)

Step 1

Concept

Multiply by \(\sqrt{10}+\sqrt{6}\) to rationalize the denominator.

Step 2

Why this answer is correct

The numerator becomes (\(\sqrt{10}+\sqrt{6}\)2=16+2\sqrt{60}) and the denominator is (10-6=4), so the value is \(4+\sqrt{15}\).

Step 3

Exam Tip

In conjugate fractions, clear the denominator first. चरण 1: हर को परिमेय बनाने के लिए \(\sqrt{10}+\sqrt{6}\) से गुणा करें। चरण 2: ऊपर (\(\sqrt{10}+\sqrt{6}\)2=16+2\sqrt{60}) और नीचे (10-6=4) मिलता है, इसलिए मान \(4+\sqrt{15}\) है। चरण 3: संयुग्मी वाले भिन्नों में हर को पहले साफ करें।

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Question Expert Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 13

कौन-सा विकल्प \(\frac{2+\sqrt{3}}{2-\sqrt{3}}\) के सही सरल रूप के बराबर है?

Which option is equal to the simplified form of \(\frac{2+\sqrt{3}}{2-\sqrt{3}}\)?

Explanation opens after your attempt
Correct Answer

A. \(7+4\sqrt{3}\)

Step 1

Concept

Multiply by \(2+\sqrt{3}\) to rationalize the denominator.

Step 2

Why this answer is correct

(\frac{\(2+\sqrt{3}\)2}{4-3}=4+4\sqrt{3}+3=7+4\sqrt{3}).

Step 3

Exam Tip

When multiplying by the conjugate, the numerator may become a full square. चरण 1: हर को परिमेय बनाने के लिए \(2+\sqrt{3}\) से गुणा करें। चरण 2: (\frac{\(2+\sqrt{3}\)2}{4-3}=4+4\sqrt{3}+3=7+4\sqrt{3})। चरण 3: संयुग्मी से गुणा करते समय ऊपर भी पूरा वर्ग बनता है।

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