Concept-wise Practice

denominator MCQ Questions for Class 10

denominator se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

6 questions tagged with denominator.

Question 1/6 Medium Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 16

कौन सा कथन \(\sqrt{2}\) की सिद्धि में \(q\neq 0\) की जरूरत को सही बताता है?

Which statement correctly explains why \(q\neq 0\) is needed in the proof of \(\sqrt{2}\)?

Explanation opens after your attempt
Correct Answer

A. भिन्न \(\frac{p}{q}\) में हर शून्य नहीं हो सकताThe denominator in \(\frac{p}{q}\) cannot be zero

Step 1

Concept

A rational number is written as \(\frac{p}{q}\).

Step 2

Why this answer is correct

The denominator of a fraction cannot be zero.

Step 3

Exam Tip

Therefore \(q\neq 0\) must be written. चरण 1: परिमेय संख्या को \(\frac{p}{q}\) के रूप में लिखा जाता है। चरण 2: भिन्न का हर शून्य नहीं हो सकता। चरण 3: इसलिए \(q\neq 0\) लिखना आवश्यक है।

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Question 2/6 Easy Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 18

\(\sqrt{3}=\frac{p}{q}\) लिखते समय कौन सी शर्त जरूरी है?

Which condition is necessary while writing \(\sqrt{3}=\frac{p}{q}\)?

Explanation opens after your attempt
Correct Answer

C. \(q\neq 0\)

Step 1

Concept

The denominator of any fraction cannot be zero.

Step 2

Why this answer is correct

So in \(\frac{p}{q}\), we must write \(q\neq 0\).

Step 3

Exam Tip

Do not forget this small condition while writing the rational form. चरण 1: किसी भी भिन्न का हर शून्य नहीं हो सकता। चरण 2: इसलिए \(\frac{p}{q}\) में \(q\neq 0\) लिखना जरूरी है। चरण 3: परिमेय संख्या का रूप लिखते समय यह छोटी शर्त न भूलें।

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Question 3/6 Easy Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 17

यदि \(\sqrt{3}=\frac{a}{b}\) है, जहां (a) और (b) सहअभाज्य हैं, तो (b) के बारे में कौन सी शर्त जरूरी है?

If \(\sqrt{3}=\frac{a}{b}\), where (a) and (b) are coprime, which condition about (b) is necessary?

Explanation opens after your attempt
Correct Answer

A. \(b\neq 0\)

Step 1

Concept

The denominator of a fraction cannot be zero.

Step 2

Why this answer is correct

So while writing \(\frac{a}{b}\), the condition \(b\neq 0\) is necessary.

Step 3

Exam Tip

Write this condition when expressing a rational number. चरण 1: किसी भिन्न में हर शून्य नहीं हो सकता। चरण 2: इसलिए \(\frac{a}{b}\) लिखते समय \(b\neq 0\) जरूरी है। चरण 3: परिमेय संख्या का रूप लिखते समय यह शर्त साथ लिखें।

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Question 4/6 Easy Mathematics Chapter 1: Real Numbers 6: Proof of irrationality of √2, √3, √5 Class 10 Level 16

\(\sqrt{2}\) के प्रमाण में \(q\neq 0\) क्यों जरूरी है?

Why is \(q\neq 0\) necessary in the proof of \(\sqrt{2}\)?

Explanation opens after your attempt
Correct Answer

A. क्योंकि \(\frac{p}{q}\) में हर शून्य नहीं हो सकताBecause the denominator in \(\frac{p}{q}\) cannot be zero

Step 1

Concept

A rational number is written in the form \(\frac{p}{q}\).

Step 2

Why this answer is correct

The denominator of a fraction cannot be zero.

Step 3

Exam Tip

Therefore \(q\neq 0\) must be written in the proof. चरण 1: परिमेय संख्या \(\frac{p}{q}\) के रूप में लिखी जाती है। चरण 2: किसी भिन्न का हर शून्य नहीं हो सकता। चरण 3: इसलिए प्रमाण में \(q\neq 0\) लिखना आवश्यक है।

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Question 5/6 Expert Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 14

कौन-सा विकल्प \(\frac{1}{\sqrt{5}+\sqrt{2}}\) का परिमेय हर वाला रूप है?

Which option is the rationalized form of \(\frac{1}{\sqrt{5}+\sqrt{2}}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{\sqrt{5}-\sqrt{2}}{3}\)

Step 1

Concept

The conjugate of the denominator is \(\sqrt{5}-\sqrt{2}\).

Step 2

Why this answer is correct

The denominator becomes (5-2=3), so the form is \(\frac{\sqrt{5}-\sqrt{2}}{3}\).

Step 3

Exam Tip

For a sum of two surds, the conjugate changes the sign between them. चरण 1: हर का संयुग्मी \(\sqrt{5}-\sqrt{2}\) है। चरण 2: हर (5-2=3) बनता है, इसलिए रूप \(\frac{\sqrt{5}-\sqrt{2}}{3}\) है। चरण 3: दो मूलों के योग में संयुग्मी का चिह्न बदलता है।

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Question 6/6 Hard Mathematics Chapter 1: Real Numbers 5: Irrational numbers Class 10 Level 15

कौन-सी संख्या \(\frac{2}{\sqrt{2}+1}\) के बराबर है?

Which number is equal to \(\frac{2}{\sqrt{2}+1}\)?

Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{2}-2\)

Step 1

Concept

The conjugate of the denominator is \(\sqrt{2}-1\).

Step 2

Why this answer is correct

(\frac{2}{\sqrt{2}+1}\times\frac{\sqrt{2}-1}{\sqrt{2}-1}=\frac{2\(\sqrt{2}-1\)}{2-1}=2\sqrt{2}-2).

Step 3

Exam Tip

Choosing the correct conjugate sign is very important. चरण 1: हर का संयुग्मी \(\sqrt{2}-1\) है। चरण 2: (\frac{2}{\sqrt{2}+1}\times\frac{\sqrt{2}-1}{\sqrt{2}-1}=\frac{2\(\sqrt{2}-1\)}{2-1}=2\sqrt{2}-2)। चरण 3: संयुग्मी का सही चिह्न चुनना बहुत जरूरी है।

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