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Which number is equal to (\frac{2}{\sqrt{2}+1})?
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Answer and explanation
Correct answer: (2\sqrt{2}-2)
Step 1: The conjugate of the denominator is (\sqrt{2}-1). Step 2: (\frac{2}{\sqrt{2}+1}\times\frac{\sqrt{2}-1}{\sqrt{2}-1}=\frac{2(\sqrt{2}-1)}{2-1}=2\sqrt{2}-2). Step 3: Choosing the correct conjugate sign is very important.
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What is the correct answer to this question?
(2\sqrt{2}-2)
Why is this the correct answer?
Step 1: The conjugate of the denominator is (\sqrt{2}-1). Step 2: (\frac{2}{\sqrt{2}+1}\times\frac{\sqrt{2}-1}{\sqrt{2}-1}=\frac{2(\sqrt{2}-1)}{2-1}=2\sqrt{2}-2). Step 3: Choosing the correct conjugate sign is very important.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Irrational numbers.
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