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Which form is obtained by rationalising the denominator of (\dfrac{3}{2-\sqrt{3}})?
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Answer and explanation
Correct answer: (,6+3\sqrt{3},)
Multiplying by (2+\sqrt{3}) makes the denominator (4-3=1). In exams, multiply both numerator and denominator by the conjugate.
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What is the correct answer to this question?
(,6+3\sqrt{3},)
Why is this the correct answer?
Multiplying by (2+\sqrt{3}) makes the denominator (4-3=1). In exams, multiply both numerator and denominator by the conjugate.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.
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