0 reads0 ratings0 helpful
If the zeroes of (p(x)=x^2-6x+k) are (3+\sqrt{2}) and (3-\sqrt{2}), what is the value of (k)?
Advertisement
Answer and explanation
Correct answer: (7)
The product ((3+\sqrt{2})(3-\sqrt{2})=9-2=7), so (k=7). In exams connect the constant term with the product of zeroes.
Frequently asked questions
What is the correct answer to this question?
(7)
Why is this the correct answer?
The product ((3+\sqrt{2})(3-\sqrt{2})=9-2=7), so (k=7). In exams connect the constant term with the product of zeroes.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement