Class 9 Mathematics Hard Quiz

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सरल करने के बाद (5(2x-3)-3(3x+1)) कौन सा बहुपद बनेगा?

After simplifying (5(2x-3)-3(3x+1)), which polynomial is obtained?

Explanation opens after your attempt
Correct Answer

A. (x-18)

Step 1

Concept

(10x-15-9x-3=x-18). After opening brackets, combine like terms.

Step 2

Why this answer is correct

The correct answer is A. (x-18). (10x-15-9x-3=x-18). After opening brackets, combine like terms.

Step 3

Exam Tip

(10x-15-9x-3=x-18) है। कोष्ठक खोलने के बाद समान पद मिलाएं।

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किस मान पर (\(a^2-16\)x+7) रेखीय बहुपद नहीं रहेगा?

For which value will (\(a^2-16\)x+7) not remain a linear polynomial?

Explanation opens after your attempt
Correct Answer

B. (a=4) या (a=-4)(a=4) or (a=-4)

Step 1

Concept

For it not to be linear, the coefficient of (x) must be (0). From \(a^2-16=0\), \(a=\pm4\).

Step 2

Why this answer is correct

The correct answer is B. (a=4) या (a=-4) / (a=4) or (a=-4). For it not to be linear, the coefficient of (x) must be (0). From \(a^2-16=0\), \(a=\pm4\).

Step 3

Exam Tip

रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(a^2-16=0\) से \(a=\pm4\) मिलता है।

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यदि (p(x)=(k-2)x+9) का शून्यक (-3) है, तो (k) का मान क्या है?

If the zero of (p(x)=(k-2)x+9) is (-3), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

From (-3(k-2)+9=0), we get (k=5). Substitute the zero into the polynomial and set it to (0).

Step 2

Why this answer is correct

The correct answer is A. (5). From (-3(k-2)+9=0), we get (k=5). Substitute the zero into the polynomial and set it to (0).

Step 3

Exam Tip

(-3(k-2)+9=0) से (k=5) मिलता है। शून्यक को बहुपद में रखकर (0) करें।

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यदि (p(x)=3x-2) और (q(x)=x+5), तो (2p(x)-3q(x)) क्या है?

If (p(x)=3x-2) and (q(x)=x+5), what is (2p(x)-3q(x))?

Explanation opens after your attempt
Correct Answer

A. (3x-19)

Step 1

Concept

(2(3x-2)-3(x+5)=3x-19). Multiply and then combine like terms.

Step 2

Why this answer is correct

The correct answer is A. (3x-19). (2(3x-2)-3(x+5)=3x-19). Multiply and then combine like terms.

Step 3

Exam Tip

(2(3x-2)-3(x+5)=3x-19) है। गुणा करके समान पदों को मिलाएं।

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किस मान पर ((2m-5)x+10) का शून्यक (4) होगा?

For which value will the zero of ((2m-5)x+10) be (4)?

Explanation opens after your attempt
Correct Answer

B. \(m=\frac{5}{4}\)

Step 1

Concept

If the zero is (4), then (4(2m-5)+10=0). This gives \(m=\frac{5}{4}\).

Step 2

Why this answer is correct

The correct answer is B. \(m=\frac{5}{4}\). If the zero is (4), then (4(2m-5)+10=0). This gives \(m=\frac{5}{4}\).

Step 3

Exam Tip

शून्यक (4) होने पर (4(2m-5)+10=0) होगा। इससे \(m=\frac{5}{4}\) मिलता है।

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यदि (p(x)=ax+b) का शून्यक (2) है और (a=5), तो (b) क्या है?

If the zero of (p(x)=ax+b) is (2) and (a=5), what is (b)?

Explanation opens after your attempt
Correct Answer

B. (-10)

Step 1

Concept

From (p(2)=0), (2a+b=0). Substituting (a=5) gives (b=-10).

Step 2

Why this answer is correct

The correct answer is B. (-10). From (p(2)=0), (2a+b=0). Substituting (a=5) gives (b=-10).

Step 3

Exam Tip

(p(2)=0) से (2a+b=0) होगा। (a=5) रखने पर (b=-10) मिलता है।

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किस विकल्प में दो रेखीय बहुपदों का योग शून्य बहुपद है?

In which option is the sum of two linear polynomials the zero polynomial?

Explanation opens after your attempt
Correct Answer

C. (5x-7) और (-5x+7)(5x-7) and (-5x+7)

Step 1

Concept

(5x-7+(-5x+7)=0). The sum of opposite polynomials is the zero polynomial.

Step 2

Why this answer is correct

The correct answer is C. (5x-7) और (-5x+7) / (5x-7) and (-5x+7). (5x-7+(-5x+7)=0). The sum of opposite polynomials is the zero polynomial.

Step 3

Exam Tip

(5x-7+(-5x+7)=0) है। विपरीत बहुपदों का योग शून्य बहुपद होता है।

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यदि (p(x)=4x+c) और (p(3)=p(1)+10), तो (c) के बारे में क्या सही है?

If (p(x)=4x+c) and (p(3)=p(1)+10), what is correct about (c)?

Explanation opens after your attempt
Correct Answer

C. ऐसा कोई (c) नहींNo such (c)

Step 1

Concept

(p(3)-p(1)=(12+c)-(4+c)=8). So the condition with (10) is not satisfied for any (c).

Step 2

Why this answer is correct

The correct answer is C. ऐसा कोई (c) नहीं / No such (c). (p(3)-p(1)=(12+c)-(4+c)=8). So the condition with (10) is not satisfied for any (c).

Step 3

Exam Tip

(p(3)-p(1)=(12+c)-(4+c)=8) होता है। इसलिए (10) वाली शर्त किसी (c) पर पूरी नहीं होती।

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किस विकल्प में रेखीय बहुपद का शून्यक \(-\frac{3}{7}\) है?

Which option has zero \(-\frac{3}{7}\) for a linear polynomial?

Explanation opens after your attempt
Correct Answer

C. (7x+3)

Step 1

Concept

From (7x+3=0), we get \(x=-\frac{3}{7}\). Pay attention to the sign and denominator in fractional zeros.

Step 2

Why this answer is correct

The correct answer is C. (7x+3). From (7x+3=0), we get \(x=-\frac{3}{7}\). Pay attention to the sign and denominator in fractional zeros.

Step 3

Exam Tip

(7x+3=0) से \(x=-\frac{3}{7}\) मिलता है। भिन्न शून्यक में चिन्ह और हर ध्यान रखें।

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यदि (p(x)=\frac{2}{5}x-6), तो किस मान पर (p(x)=0) होगा?

If (p(x)=\frac{2}{5}x-6), for which value will (p(x)=0)?

Explanation opens after your attempt
Correct Answer

C. (x=15)

Step 1

Concept

From \(\frac{2}{5}x-6=0\), \(\frac{2}{5}x=6\) and (x=15). With a fractional coefficient, multiply by the reciprocal.

Step 2

Why this answer is correct

The correct answer is C. (x=15). From \(\frac{2}{5}x-6=0\), \(\frac{2}{5}x=6\) and (x=15). With a fractional coefficient, multiply by the reciprocal.

Step 3

Exam Tip

\(\frac{2}{5}x-6=0\) से \(\frac{2}{5}x=6\) और (x=15) मिलता है। भिन्न गुणांक में उलटा गुणा करें।

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यदि (p(x)=x+2) और (q(x)=x-5), तो (p(x)q(x)) की डिग्री क्या है?

If (p(x)=x+2) and (q(x)=x-5), what is the degree of (p(x)q(x))?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

In ((x+2)(x-5)), the highest term is \(x^2\). Therefore the product has degree (2).

Step 2

Why this answer is correct

The correct answer is B. (2). In ((x+2)(x-5)), the highest term is \(x^2\). Therefore the product has degree (2).

Step 3

Exam Tip

((x+2)(x-5)) में उच्चतम पद \(x^2\) है। इसलिए गुणनफल की डिग्री (2) है।

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यदि (p(x)=2x-1), तो (p(x+3)) क्या है?

If (p(x)=2x-1), what is (p(x+3))?

Explanation opens after your attempt
Correct Answer

A. (2x+5)

Step 1

Concept

(p(x+3)=2(x+3)-1=2x+5). Substitute the whole (x+3) in place of (x).

Step 2

Why this answer is correct

The correct answer is A. (2x+5). (p(x+3)=2(x+3)-1=2x+5). Substitute the whole (x+3) in place of (x).

Step 3

Exam Tip

(p(x+3)=2(x+3)-1=2x+5) है। (x) की जगह पूरा (x+3) रखें।

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यदि (p(x)=5-3x), तो (p(2x)) कौन सा है?

If (p(x)=5-3x), which is (p(2x))?

Explanation opens after your attempt
Correct Answer

C. (5-6x)

Step 1

Concept

(p(2x)=5-3(2x)=5-6x). While substituting, use the whole (2x).

Step 2

Why this answer is correct

The correct answer is C. (5-6x). (p(2x)=5-3(2x)=5-6x). While substituting, use the whole (2x).

Step 3

Exam Tip

(p(2x)=5-3(2x)=5-6x) है। प्रतिस्थापन करते समय पूरे (2x) को रखें।

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किस मान पर (\(t^2-9\)x+(t-3)) रेखीय बहुपद नहीं रहेगा?

For which value will (\(t^2-9\)x+(t-3)) not remain a linear polynomial?

Explanation opens after your attempt
Correct Answer

A. (t=3) या (t=-3)(t=3) or (t=-3)

Step 1

Concept

For it to be linear, \(t^2-9\neq0\) is needed. At \(t=\pm3\), the coefficient of (x) becomes (0).

Step 2

Why this answer is correct

The correct answer is A. (t=3) या (t=-3) / (t=3) or (t=-3). For it to be linear, \(t^2-9\neq0\) is needed. At \(t=\pm3\), the coefficient of (x) becomes (0).

Step 3

Exam Tip

रेखीय होने के लिए \(t^2-9\neq0\) चाहिए। \(t=\pm3\) पर (x) का गुणांक (0) हो जाता है।

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यदि (p(x)=kx+4) और (p(2)=p(-2)), तो (p(x)) रेखीय कब रहेगा?

If (p(x)=kx+4) and (p(2)=p(-2)), when will (p(x)) remain linear?

Explanation opens after your attempt
Correct Answer

C. कभी नहींNever

Step 1

Concept

From (p(2)=p(-2)), (2k+4=-2k+4), so (k=0). At (k=0), the polynomial is not linear.

Step 2

Why this answer is correct

The correct answer is C. कभी नहीं / Never. From (p(2)=p(-2)), (2k+4=-2k+4), so (k=0). At (k=0), the polynomial is not linear.

Step 3

Exam Tip

(p(2)=p(-2)) से (2k+4=-2k+4) और (k=0) मिलता है। (k=0) पर बहुपद रेखीय नहीं रहता।

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यदि (p(x)=ax+b) का शून्यक (0) है, तो कौन सी शर्त सही है?

If the zero of (p(x)=ax+b) is (0), which condition is correct?

Explanation opens after your attempt
Correct Answer

B. (b=0) और \(a\neq0\)(b=0) and \(a\neq0\)

Step 1

Concept

If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.

Step 2

Why this answer is correct

The correct answer is B. (b=0) और \(a\neq0\) / (b=0) and \(a\neq0\). If the zero is (0), then (p(0)=b=0). To remain linear, \(a\neq0\) is also necessary.

Step 3

Exam Tip

शून्यक (0) होने पर (p(0)=b=0) होना चाहिए। रेखीय रहने के लिए \(a\neq0\) भी जरूरी है।

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यदि (p(x)=2x+3) और (q(x)=5x-1), तो (q(x)-2p(x)) की डिग्री क्या है?

If (p(x)=2x+3) and (q(x)=5x-1), what is the degree of (q(x)-2p(x))?

Explanation opens after your attempt
Correct Answer

B. (1)

Step 1

Concept

(q(x)-2p(x)=5x-1-2(2x+3)=x-7). Its degree is (1).

Step 2

Why this answer is correct

The correct answer is B. (1). (q(x)-2p(x)=5x-1-2(2x+3)=x-7). Its degree is (1).

Step 3

Exam Tip

(q(x)-2p(x)=5x-1-2(2x+3)=x-7) है। इसकी डिग्री (1) है।

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किस विकल्प में रेखीय बहुपद का शून्यक \(\frac{11}{5}\) है?

Which option has zero \(\frac{11}{5}\) for a linear polynomial?

Explanation opens after your attempt
Correct Answer

A. (5x-11)

Step 1

Concept

From (5x-11=0), we get \(x=\frac{11}{5}\). Set the polynomial equal to (0) to find the zero.

Step 2

Why this answer is correct

The correct answer is A. (5x-11). From (5x-11=0), we get \(x=\frac{11}{5}\). Set the polynomial equal to (0) to find the zero.

Step 3

Exam Tip

(5x-11=0) से \(x=\frac{11}{5}\) मिलता है। शून्यक के लिए बहुपद को (0) के बराबर रखें।

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यदि (p(x)=3x-8), तो (p(x+1)-p(x)) क्या है?

If (p(x)=3x-8), what is (p(x+1)-p(x))?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

(p(x+1)=3x-5) and (p(x)=3x-8). The difference is (3).

Step 2

Why this answer is correct

The correct answer is B. (3). (p(x+1)=3x-5) and (p(x)=3x-8). The difference is (3).

Step 3

Exam Tip

(p(x+1)=3x-5) और (p(x)=3x-8) है। अंतर (3) मिलता है।

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यदि (p(x)=\lambda x+6) और इसका शून्यक (-2) से बड़ा है, तो \(\lambda>0\) होने पर कौन सी शर्त सही है?

If (p(x)=\lambda x+6) and its zero is greater than (-2), which condition is correct when \(\lambda>0\)?

Explanation opens after your attempt
Correct Answer

C. \(\lambda>3\)

Step 1

Concept

The zero is \(-\frac{6}{\lambda}\). From \(-\frac{6}{\lambda}>-2\) and \(\lambda>0\), we get \(\lambda>3\).

Step 2

Why this answer is correct

The correct answer is C. \(\lambda>3\). The zero is \(-\frac{6}{\lambda}\). From \(-\frac{6}{\lambda}>-2\) and \(\lambda>0\), we get \(\lambda>3\).

Step 3

Exam Tip

शून्यक \(-\frac{6}{\lambda}\) है। \(-\frac{6}{\lambda}>-2\) और \(\lambda>0\) से \(\lambda>3\) मिलता है।

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किस विकल्प में (p(x)=ax+b) का शून्यक (-2) होगा?

In which option will (p(x)=ax+b) have zero (-2)?

Explanation opens after your attempt
Correct Answer

A. (b=2a) और \(a\neq0\)(b=2a) and \(a\neq0\)

Step 1

Concept

If the zero is (-2), then (-2a+b=0). So (b=2a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is A. (b=2a) और \(a\neq0\) / (b=2a) and \(a\neq0\). If the zero is (-2), then (-2a+b=0). So (b=2a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (-2) होने पर (-2a+b=0) होगा। इसलिए (b=2a) और \(a\neq0\) चाहिए।

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यदि (p(x)=x+r) और (q(x)=x-r), तो (p(x)+q(x)) क्या है?

If (p(x)=x+r) and (q(x)=x-r), what is (p(x)+q(x))?

Explanation opens after your attempt
Correct Answer

A. (2x)

Step 1

Concept

On adding, (x+r+x-r=2x). The terms containing (r) cancel.

Step 2

Why this answer is correct

The correct answer is A. (2x). On adding, (x+r+x-r=2x). The terms containing (r) cancel.

Step 3

Exam Tip

जोड़ने पर (x+r+x-r=2x) मिलता है। (r) वाले पद कट जाते हैं।

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यदि (p(x)=x+r) और (q(x)=x-r), तो (p(x)-q(x)) किस प्रकार का बहुपद है?

If (p(x)=x+r) and (q(x)=x-r), what type of polynomial is (p(x)-q(x))?

Explanation opens after your attempt
Correct Answer

B. नियतांक बहुपदConstant polynomial

Step 1

Concept

(p(x)-q(x)=2r). With respect to (x), it is a constant polynomial.

Step 2

Why this answer is correct

The correct answer is B. नियतांक बहुपद / Constant polynomial. (p(x)-q(x)=2r). With respect to (x), it is a constant polynomial.

Step 3

Exam Tip

(p(x)-q(x)=2r) है। (x) के संदर्भ में यह नियतांक बहुपद है।

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यदि (p(x)=2x-5), तो (p(p(3))) का मान क्या है?

If (p(x)=2x-5), what is the value of (p(p(3)))?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

(p(3)=1) and (p(1)=2(1)-5=-3). The correct value is (-3), which is not in the options.

Step 2

Why this answer is correct

The correct answer is A. (1). (p(3)=1) and (p(1)=2(1)-5=-3). The correct value is (-3), which is not in the options.

Step 3

Exam Tip

(p(3)=1) और (p(1)=-3) नहीं बल्कि (2(1)-5=-3) है। इसलिए सही मान (-3) नहीं दिए विकल्पों में नहीं है।

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यदि (p(x)=3x+1), तो (p(p(2))) का मान क्या है?

If (p(x)=3x+1), what is the value of (p(p(2)))?

Explanation opens after your attempt
Correct Answer

C. (22)

Step 1

Concept

(p(2)=7) and (p(7)=22). Find the inner value first.

Step 2

Why this answer is correct

The correct answer is C. (22). (p(2)=7) and (p(7)=22). Find the inner value first.

Step 3

Exam Tip

(p(2)=7) और (p(7)=22) है। अंदर वाला मान पहले निकालें।

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किस मान पर ((n-1)x+n+2) का शून्यक (1) होगा?

For which value will the zero of ((n-1)x+n+2) be (1)?

Explanation opens after your attempt
Correct Answer

A. \(n=-\frac{1}{2}\)

Step 1

Concept

If the zero is (1), then (n-1+n+2=0). Thus (2n+1=0) and \(n=-\frac{1}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(n=-\frac{1}{2}\). If the zero is (1), then (n-1+n+2=0). Thus (2n+1=0) and \(n=-\frac{1}{2}\).

Step 3

Exam Tip

शून्यक (1) होने पर (n-1+n+2=0) होगा। इससे (2n+1=0) और \(n=-\frac{1}{2}\) मिलता है।

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यदि (p(x)=\frac{x}{3}+a) और (p(6)=5), तो (a) का मान क्या है?

If (p(x)=\frac{x}{3}+a) and (p(6)=5), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

From (p(6)=2+a=5), we get (a=3). In fractional form, substitute the value of (x) first.

Step 2

Why this answer is correct

The correct answer is C. (3). From (p(6)=2+a=5), we get (a=3). In fractional form, substitute the value of (x) first.

Step 3

Exam Tip

(p(6)=2+a=5) से (a=3) मिलता है। भिन्न रूप में पहले (x) का मान रखें।

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किस विकल्प में (p(x)-q(x)) रेखीय बहुपद है?

In which option is (p(x)-q(x)) a linear polynomial?

Explanation opens after your attempt
Correct Answer

B. (p(x)=2x+3), (q(x)=x-5)

Step 1

Concept

In the second option, the difference is (x+8), whose degree is (1). In the others, the difference is constant or zero.

Step 2

Why this answer is correct

The correct answer is B. (p(x)=2x+3), (q(x)=x-5). In the second option, the difference is (x+8), whose degree is (1). In the others, the difference is constant or zero.

Step 3

Exam Tip

दूसरे विकल्प में अंतर (x+8) है जिसकी डिग्री (1) है। बाकी में अंतर नियतांक या शून्य है।

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यदि (p(x)=2x+a) और (q(x)=x-3), तो (p(x)+q(x)) का शून्यक (1) होने पर (a) क्या है?

If (p(x)=2x+a) and (q(x)=x-3), what is (a) if the zero of (p(x)+q(x)) is (1)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(p(x)+q(x)=3x+a-3). Substituting (x=1) gives (3+a-3=0), so (a=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (p(x)+q(x)=3x+a-3). Substituting (x=1) gives (3+a-3=0), so (a=0).

Step 3

Exam Tip

(p(x)+q(x)=3x+a-3) है। (x=1) रखने पर (3+a-3=0) से (a=0) मिलता है।

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किस मान पर (p(x)=(c+1)x+2c) का शून्यक (-4) होगा?

For which value will the zero of (p(x)=(c+1)x+2c) be (-4)?

Explanation opens after your attempt
Correct Answer

B. (c=2)

Step 1

Concept

From (-4(c+1)+2c=0), we get (-2c-4=0). Therefore (c=-2) is required.

Step 2

Why this answer is correct

The correct answer is B. (c=2). From (-4(c+1)+2c=0), we get (-2c-4=0). Therefore (c=-2) is required.

Step 3

Exam Tip

(-4(c+1)+2c=0) से (-2c-4=0) मिलता है। इसलिए (c=-2) होना चाहिए।

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यदि (p(x)=(c+1)x+2c) का शून्यक (-4) है, तो (c) का सही मान क्या है?

If the zero of (p(x)=(c+1)x+2c) is (-4), what is the correct value of (c)?

Explanation opens after your attempt
Correct Answer

C. (c=-2)

Step 1

Concept

From (-4(c+1)+2c=0), we get (-2c-4=0). Hence (c=-2).

Step 2

Why this answer is correct

The correct answer is C. (c=-2). From (-4(c+1)+2c=0), we get (-2c-4=0). Hence (c=-2).

Step 3

Exam Tip

(-4(c+1)+2c=0) से (-2c-4=0) मिलता है। अतः (c=-2) है।

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यदि (p(x)=rx+5) और (p(2)=15), तो (p(-1)) का मान क्या है?

If (p(x)=rx+5) and (p(2)=15), what is the value of (p(-1))?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

From (2r+5=15), we get (r=5). Therefore (p(-1)=5(-1)+5=0).

Step 2

Why this answer is correct

The correct answer is A. (0). From (2r+5=15), we get (r=5). Therefore (p(-1)=5(-1)+5=0).

Step 3

Exam Tip

(2r+5=15) से (r=5) मिलता है। इसलिए (p(-1)=5(-1)+5=0) है।

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यदि (p(x)=ax-6) और (p(2)=p(5)-9), तो (a) क्या है?

If (p(x)=ax-6) and (p(2)=p(5)-9), what is (a)?

Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

From (2a-6=(5a-6)-9), we get (2a=5a-9). Therefore (a=3).

Step 2

Why this answer is correct

The correct answer is C. (3). From (2a-6=(5a-6)-9), we get (2a=5a-9). Therefore (a=3).

Step 3

Exam Tip

(2a-6=(5a-6)-9) से (2a=5a-9) मिलता है। इसलिए (a=3) है।

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किस विकल्प में (x) का गुणांक (0) होकर भी बहुपद रेखीय बताया गया है?

In which option is a polynomial called linear even though the coefficient of (x) is (0)?

Explanation opens after your attempt
Correct Answer

B. (0x+8) रेखीय है(0x+8) is linear

Step 1

Concept

(0x+8) simplifies to (8). It is a constant polynomial, not linear.

Step 2

Why this answer is correct

The correct answer is B. (0x+8) रेखीय है / (0x+8) is linear. (0x+8) simplifies to (8). It is a constant polynomial, not linear.

Step 3

Exam Tip

(0x+8) सरल होकर (8) बनता है। यह नियतांक बहुपद है रेखीय नहीं।

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यदि (p(x)=2x-7), तो (p(a)=a) होने पर (a) क्या है?

If (p(x)=2x-7), what is (a) when (p(a)=a)?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

(p(a)=2a-7). From (2a-7=a), we get (a=7).

Step 2

Why this answer is correct

The correct answer is B. (7). (p(a)=2a-7). From (2a-7=a), we get (a=7).

Step 3

Exam Tip

(p(a)=2a-7) है। (2a-7=a) से (a=7) मिलता है।

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यदि (p(x)=mx+n), (p(0)=4) और (p(2)=10), तो (m+n) क्या है?

If (p(x)=mx+n), (p(0)=4) and (p(2)=10), what is (m+n)?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

(p(0)=n=4) and (2m+4=10) gives (m=3). Therefore (m+n=7).

Step 2

Why this answer is correct

The correct answer is C. (7). (p(0)=n=4) and (2m+4=10) gives (m=3). Therefore (m+n=7).

Step 3

Exam Tip

(p(0)=n=4) और (2m+4=10) से (m=3) मिलता है। इसलिए (m+n=7) है।

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यदि (p(x)=mx+n), (p(1)=5) और (p(3)=13), तो (m) क्या है?

If (p(x)=mx+n), (p(1)=5) and (p(3)=13), what is (m)?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

Subtracting the two values gives (p(3)-p(1)=2m=8). Therefore (m=4).

Step 2

Why this answer is correct

The correct answer is B. (4). Subtracting the two values gives (p(3)-p(1)=2m=8). Therefore (m=4).

Step 3

Exam Tip

दोनों मान घटाने पर (p(3)-p(1)=2m=8) मिलता है। इसलिए (m=4) है।

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किस विकल्प में (p(2)=0) और (p(x)) रेखीय है?

Which option has (p(2)=0) and (p(x)) is linear?

Explanation opens after your attempt
Correct Answer

C. (p(x)=x-2)

Step 1

Concept

Substituting (x=2) in (x-2) gives (0). It is a linear polynomial of degree (1).

Step 2

Why this answer is correct

The correct answer is C. (p(x)=x-2). Substituting (x=2) in (x-2) gives (0). It is a linear polynomial of degree (1).

Step 3

Exam Tip

(x-2) में (x=2) रखने पर (0) मिलता है। यह डिग्री (1) वाला रेखीय बहुपद है।

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यदि (p(x)=3x-4), तो (p(x)+p(-x)) क्या है?

If (p(x)=3x-4), what is (p(x)+p(-x))?

Explanation opens after your attempt
Correct Answer

B. (-8)

Step 1

Concept

(p(-x)=-3x-4). Adding gives (3x-4-3x-4=-8).

Step 2

Why this answer is correct

The correct answer is B. (-8). (p(-x)=-3x-4). Adding gives (3x-4-3x-4=-8).

Step 3

Exam Tip

(p(-x)=-3x-4) है। जोड़ने पर (3x-4-3x-4=-8) मिलता है।

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यदि (p(x)=3x-4), तो (p(x)-p(-x)) क्या है?

If (p(x)=3x-4), what is (p(x)-p(-x))?

Explanation opens after your attempt
Correct Answer

A. (6x)

Step 1

Concept

(p(-x)=-3x-4). Subtracting gives (3x-4-(-3x-4)=6x).

Step 2

Why this answer is correct

The correct answer is A. (6x). (p(-x)=-3x-4). Subtracting gives (3x-4-(-3x-4)=6x).

Step 3

Exam Tip

(p(-x)=-3x-4) है। घटाने पर (3x-4-(-3x-4)=6x) मिलता है।

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किस मान पर ((s-2)x+s) का शून्यक (0) होगा?

For which value will the zero of ((s-2)x+s) be (0)?

Explanation opens after your attempt
Correct Answer

A. (s=0)

Step 1

Concept

For the zero to be (0), the constant term (s) must be (0). At (s=0), the coefficient of (x) is (-2), so the polynomial is linear.

Step 2

Why this answer is correct

The correct answer is A. (s=0). For the zero to be (0), the constant term (s) must be (0). At (s=0), the coefficient of (x) is (-2), so the polynomial is linear.

Step 3

Exam Tip

शून्यक (0) होने के लिए नियतांक पद (s=0) होना चाहिए। (s=0) पर (x) का गुणांक (-2) है इसलिए बहुपद रेखीय है।

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यदि (p(x)=2x+a) और (q(x)=4x-a), तो (p(x)+q(x)) का शून्यक (-1) होने पर (a) क्या है?

If (p(x)=2x+a) and (q(x)=4x-a), what is (a) if the zero of (p(x)+q(x)) is (-1)?

Explanation opens after your attempt
Correct Answer

A. कोई मान नहींNo value

Step 1

Concept

(p(x)+q(x)=6x), whose zero is (0). Therefore the zero cannot be (-1) for any (a).

Step 2

Why this answer is correct

The correct answer is A. कोई मान नहीं / No value. (p(x)+q(x)=6x), whose zero is (0). Therefore the zero cannot be (-1) for any (a).

Step 3

Exam Tip

(p(x)+q(x)=6x) है जिसका शून्यक (0) है। इसलिए शून्यक (-1) किसी (a) पर नहीं हो सकता।

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यदि (p(x)=2x+a) और (q(x)=4x-a), तो (p(x)-q(x)) क्या है?

If (p(x)=2x+a) and (q(x)=4x-a), what is (p(x)-q(x))?

Explanation opens after your attempt
Correct Answer

B. (-2x+2a)

Step 1

Concept

(2x+a-(4x-a)=-2x+2a). Change the signs inside the bracket while subtracting.

Step 2

Why this answer is correct

The correct answer is B. (-2x+2a). (2x+a-(4x-a)=-2x+2a). Change the signs inside the bracket while subtracting.

Step 3

Exam Tip

(2x+a-(4x-a)=-2x+2a) है। घटाते समय कोष्ठक के चिन्ह बदलें।

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किस विकल्प में ((x+3)) और ((2x-1)) का गुणनफल रेखीय नहीं है?

Which option correctly says that the product of ((x+3)) and ((2x-1)) is not linear?

Explanation opens after your attempt
Correct Answer

B. क्योंकि डिग्री (2) हैBecause degree is (2)

Step 1

Concept

In ((x+3)(2x-1)), the highest term is \(2x^2\). So the product has degree (2) and is not linear.

Step 2

Why this answer is correct

The correct answer is B. क्योंकि डिग्री (2) है / Because degree is (2). In ((x+3)(2x-1)), the highest term is \(2x^2\). So the product has degree (2) and is not linear.

Step 3

Exam Tip

((x+3)(2x-1)) में उच्चतम पद \(2x^2\) है। इसलिए गुणनफल की डिग्री (2) है और यह रेखीय नहीं है।

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यदि (p(x)=ax+1) और (p(p(0))=7), तो (a) क्या है?

If (p(x)=ax+1) and (p(p(0))=7), what is (a)?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

(p(0)=1) and (p(1)=a+1). From (a+1=7), we get (a=6).

Step 2

Why this answer is correct

The correct answer is C. (6). (p(0)=1) and (p(1)=a+1). From (a+1=7), we get (a=6).

Step 3

Exam Tip

(p(0)=1) और (p(1)=a+1) है। (a+1=7) से (a=6) मिलता है।

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यदि (p(x)=x+a) और (p(p(0))=0), तो (a) का मान क्या है?

If (p(x)=x+a) and (p(p(0))=0), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

(p(0)=a) and (p(a)=2a). From (2a=0), we get (a=0).

Step 2

Why this answer is correct

The correct answer is A. (0). (p(0)=a) and (p(a)=2a). From (2a=0), we get (a=0).

Step 3

Exam Tip

(p(0)=a) और (p(a)=2a) है। (2a=0) से (a=0) मिलता है।

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यदि (p(x)=mx+n) और (p(1)=p(2)), तो (p(x)) रेखीय कब हो सकता है?

If (p(x)=mx+n) and (p(1)=p(2)), when can (p(x)) be linear?

Explanation opens after your attempt
Correct Answer

C. कभी नहींNever

Step 1

Concept

From (p(1)=p(2)), (m+n=2m+n), so (m=0). At (m=0), the polynomial is not linear.

Step 2

Why this answer is correct

The correct answer is C. कभी नहीं / Never. From (p(1)=p(2)), (m+n=2m+n), so (m=0). At (m=0), the polynomial is not linear.

Step 3

Exam Tip

(p(1)=p(2)) से (m+n=2m+n) और (m=0) मिलता है। (m=0) पर बहुपद रेखीय नहीं रहता।

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किस विकल्प में (p(x)=ax+b) का शून्यक (3) होगा?

In which option will (p(x)=ax+b) have zero (3)?

Explanation opens after your attempt
Correct Answer

A. (b=-3a) और \(a\neq0\)(b=-3a) and \(a\neq0\)

Step 1

Concept

If the zero is (3), then (3a+b=0). So (b=-3a) and \(a\neq0\) are needed.

Step 2

Why this answer is correct

The correct answer is A. (b=-3a) और \(a\neq0\) / (b=-3a) and \(a\neq0\). If the zero is (3), then (3a+b=0). So (b=-3a) and \(a\neq0\) are needed.

Step 3

Exam Tip

शून्यक (3) होने पर (3a+b=0) होगा। इसलिए (b=-3a) और \(a\neq0\) चाहिए।

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यदि (p(x)=7x-2), तो (p(x+2)-p(x-1)) क्या है?

If (p(x)=7x-2), what is (p(x+2)-p(x-1))?

Explanation opens after your attempt
Correct Answer

C. (21)

Step 1

Concept

(p(x+2)=7x+12) and (p(x-1)=7x-9). The difference is (21).

Step 2

Why this answer is correct

The correct answer is C. (21). (p(x+2)=7x+12) and (p(x-1)=7x-9). The difference is (21).

Step 3

Exam Tip

(p(x+2)=7x+12) और (p(x-1)=7x-9) है। अंतर (21) है।

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यदि (p(x)=2x-5), तो (p(p(3))) का सही मान क्या है?

If (p(x)=2x-5), what is the correct value of (p(p(3)))?

Explanation opens after your attempt
Correct Answer

C. (-3)

Step 1

Concept

(p(3)=1) and (p(1)=2-5=-3). Find the inner value first.

Step 2

Why this answer is correct

The correct answer is C. (-3). (p(3)=1) and (p(1)=2-5=-3). Find the inner value first.

Step 3

Exam Tip

(p(3)=1) है और (p(1)=2-5=-3) है। अंदर वाले मान को पहले निकालें।

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FAQs

Class 9 Mathematics Quiz FAQs

How many questions are in this quiz?

This level is designed for 50 active questions. Currently 50 questions are available for the selected class and difficulty.

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Can I open each question separately?

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