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fraction-equation MCQ Questions for Class 10

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4 questions tagged with fraction-equation.

Question 1/4 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

यदि \(\frac{x}{3}+\frac{y}{2}=7\) और (x-y=3), तो (y) का मान क्या है?

If \(\frac{x}{3}+\frac{y}{2}=7\) and (x-y=3), what is the value of (y)?

Explanation opens after your attempt
Correct Answer

C. \(y=\frac{36}{5}\)

Step 1

Concept

Multiplying the first equation by (6) gives (2x+3y=42). Using (x=y+3) gives (5y=36), so \(y=\frac{36}{5}\).

Step 2

Why this answer is correct

The correct answer is C. \(y=\frac{36}{5}\). Multiplying the first equation by (6) gives (2x+3y=42). Using (x=y+3) gives (5y=36), so \(y=\frac{36}{5}\).

Step 3

Exam Tip

पहले समीकरण को (6) से गुणा करने पर (2x+3y=42) मिलता है। (x=y+3) रखने पर (5y=36), इसलिए \(y=\frac{36}{5}\)।

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Question 2/4 Medium Mathematics Pair of Linear Equations in Two Variables Algebraic methods: Substitution method and Elimination method. Class 10 Level 57

समीकरणों \(\frac{x}{2}+\frac{y}{3}=5\) और (x-y=3) का हल क्या है?

What is the solution of \(\frac{x}{2}+\frac{y}{3}=5\) and (x-y=3)?

Explanation opens after your attempt
Correct Answer

A. \(x=\frac{36}{5},\ y=\frac{21}{5}\)

Step 1

Concept

Multiplying the first equation by (6) gives (3x+2y=30). Using (x=y+3) gives \(y=\frac{21}{5}\) and \(x=\frac{36}{5}\).

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{36}{5},\ y=\frac{21}{5}\). Multiplying the first equation by (6) gives (3x+2y=30). Using (x=y+3) gives \(y=\frac{21}{5}\) and \(x=\frac{36}{5}\).

Step 3

Exam Tip

पहले समीकरण को (6) से गुणा करने पर (3x+2y=30) मिलता है। (x=y+3) रखने पर \(y=\frac{21}{5}\) और \(x=\frac{36}{5}\)।

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Question 3/4 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

समीकरण \(\frac{x+3}{x-2}+\frac{x-2}{x+3}=\frac{13}{6}\) का मानक द्विघात रूप कौन-सा है?

What is the standard quadratic form of \(\frac{x+3}{x-2}+\frac{x-2}{x+3}=\frac{13}{6}\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+x-156=0\)

Step 1

Concept

After clearing denominators, (6{(x+3)2+(x-2)2}=13(x+3)(x-2)). Simplifying gives the correct form \(x^2+x-156=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2+x-156=0\). After clearing denominators, (6{(x+3)2+(x-2)2}=13(x+3)(x-2)). Simplifying gives the correct form \(x^2+x-156=0\).

Step 3

Exam Tip

हर हटाने पर (6{(x+3)2+(x-2)2}=13(x+3)(x-2)) मिलता है। सरल करने पर \(x^2+x-156=0\) सही रूप है।

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Question 4/4 Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

समीकरण \(\frac{x+2}{x-1}+\frac{x-1}{x+2}=\frac{5}{2}\) का मानक द्विघात रूप कौन-सा है?

What is the standard quadratic form of \(\frac{x+2}{x-1}+\frac{x-1}{x+2}=\frac{5}{2}\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2+x-20=0\)

Step 1

Concept

After clearing denominators, (2(x+2)2+2(x-1)2=5(x-1)(x+2)). Simplifying gives the correct form \(x^2+x-20=0\).

Step 2

Why this answer is correct

The correct answer is A. \(x^2+x-20=0\). After clearing denominators, (2(x+2)2+2(x-1)2=5(x-1)(x+2)). Simplifying gives the correct form \(x^2+x-20=0\).

Step 3

Exam Tip

हर हटाने पर (2(x+2)2+2(x-1)2=5(x-1)(x+2)) मिलता है। सरल करने पर \(x^2+x-20=0\) सही रूप है।

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