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What is the standard quadratic form of (\frac{x+3}{x-2}+\frac{x-2}{x+3}=\frac{13}{6})?
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Answer and explanation
Correct answer: (x^2+x-156=0)
After clearing denominators, (6{(x+3)^2+(x-2)^2}=13(x+3)(x-2)). Simplifying gives the correct form (x^2+x-156=0).
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What is the correct answer to this question?
(x^2+x-156=0)
Why is this the correct answer?
After clearing denominators, (6{(x+3)^2+(x-2)^2}=13(x+3)(x-2)). Simplifying gives the correct form (x^2+x-156=0).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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