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What is the standard form of the equation \(x^2 = 4x + 12\)?

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Answer and explanation

Correct answer: \(x^2 - 4x - 12 = 0\)

The standard form places all terms on one side and zero on the other. Moving the terms from the right to the left changes their signs, giving \(x^2 - 4x - 12 = 0\). The other options fail because their signs are not changed correctly — e.g. option C has the constant sign wrong, options B and D have the linear term sign wrong. Exam tip: Bring all terms to one side and arrange in descending powers of \(x\) (\(x^2\), then \(x\), then constant) before finalizing the answer.

Related tags

Quadratic EquationsStandard FormSignsEquation Rearrangement

Frequently asked questions

What is the correct answer to this question?

\(x^2 - 4x - 12 = 0\)

Why is this the correct answer?

The standard form places all terms on one side and zero on the other. Moving the terms from the right to the left changes their signs, giving \(x^2 - 4x - 12 = 0\). The other options fail because their signs are not changed correctly — e.g. option C has the constant sign wrong, options B and D have the linear term sign wrong. Exam tip: Bring all terms to one side and arrange in descending powers of \(x\) (\(x^2\), then \(x\), then constant) before finalizing the answer.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.

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