If \(x=2\), what is the value of the left-hand side of the equation \(x^2-5x+6=0\)?
Answer and explanation
Correct answer: 0
Substitute and evaluate: \(2^2-5\cdot2+6=4-10+6=0\). Hence the left-hand side equals 0 and \(x=2\) is a root of the quadratic. Option C (4) is incorrect — that would result from using only \(2^2\) and ignoring the other terms. Exam tip: compute powers and multiplications first, then perform additions/subtractions to avoid sign or order errors.
Frequently asked questions
What is the correct answer to this question?
0
Why is this the correct answer?
Substitute and evaluate: \(2^2-5\cdot2+6=4-10+6=0\). Hence the left-hand side equals 0 and \(x=2\) is a root of the quadratic. Option C (4) is incorrect — that would result from using only \(2^2\) and ignoring the other terms. Exam tip: compute powers and multiplications first, then perform additions/subtractions to avoid sign or order errors.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Introduction to Quadratic Equations.
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