Question 1/4
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30
क्या (x=2) समीकरण \(x^2-4=0\) का मूल है?
Is (x=2) a root of \(x^2-4=0\)?
Explanation opens after your attempt
Correct Answer
A. हाँ/Yes
Step 1
Concept
Putting (x=2) gives \(2^2-4=0\). To check a root, substitute the value and see if the result is (0).
Step 2
Why this answer is correct
The correct answer is A. हाँ / Yes. Putting (x=2) gives \(2^2-4=0\). To check a root, substitute the value and see if the result is (0).
Step 3
Exam Tip
(x=2) रखने पर \(2^2-4=0\) मिलता है। मूल जांचने के लिए मान रखकर परिणाम (0) देखें।
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Question 2/4
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29
समीकरण \(x^2-8x+16=0\) में (x=4) रखने पर क्या मिलता है?
What do we get by putting (x=4) in \(x^2-8x+16=0\)?
Explanation opens after your attempt
Step 1
Concept
We get \(4^2-8\cdot4+16=0\). So (x=4) satisfies the equation.
Step 2
Why this answer is correct
The correct answer is A. (0=0). We get \(4^2-8\cdot4+16=0\). So (x=4) satisfies the equation.
Step 3
Exam Tip
\(4^2-8\cdot4+16=0\) मिलता है। इसलिए (x=4) समीकरण को संतुष्ट करता है।
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Question 3/4
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28
कौन सा मान \(x^2+x-6=0\) का हल है?
Which value is a solution of \(x^2+x-6=0\)?
Explanation opens after your attempt
Step 1
Concept
Since \(2^2+2-6=0\), (x=2) is a solution of the equation.
Step 2
Why this answer is correct
The correct answer is B. (2). Since \(2^2+2-6=0\), (x=2) is a solution of the equation.
Step 3
Exam Tip
\(2^2+2-6=0\) है। इसलिए (x=2) इस समीकरण का हल है।
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Question 4/4
Easy Mathematics
Quadratic Equations Introduction to Quadratic Equations Class 10 Level 28
यदि (x=2) है तो \(x^2-5x+6=0\) में बायां पक्ष कितना होगा?
If (x=2), what is the left side of \(x^2-5x+6=0\)?
Explanation opens after your attempt
Step 1
Concept
Substitution gives \(2^2-5\cdot2+6=0\). So (x=2) is a solution.
Step 2
Why this answer is correct
The correct answer is A. (0). Substitution gives \(2^2-5\cdot2+6=0\). So (x=2) is a solution.
Step 3
Exam Tip
रखने पर \(2^2-5\cdot2+6=0\) मिलता है। इसलिए (x=2) समीकरण का हल है।
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