किस मान पर ((n-1)x+n+2) का शून्यक (1) होगा?
For which value will the zero of ((n-1)x+n+2) be (1)?
Explanation opens after your attempt
Correct Answer
A. \(n=-\frac{1}{2}\)
Concept
If the zero is (1), then (n-1+n+2=0). Thus (2n+1=0) and \(n=-\frac{1}{2}\).
Why this answer is correct
The correct answer is A. \(n=-\frac{1}{2}\). If the zero is (1), then (n-1+n+2=0). Thus (2n+1=0) and \(n=-\frac{1}{2}\).
Exam Tip
शून्यक (1) होने पर (n-1+n+2=0) होगा। इससे (2n+1=0) और \(n=-\frac{1}{2}\) मिलता है।
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