Concept-wise Practice

parameter-values MCQ Questions for Class 10

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Practice Questions

4 questions tagged with parameter-values.

Question 1/4 Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि (x-2+(m-2)x+25=0) की जड़ें समान हैं, तो (m) के मान क्या हैं?

If (x-2+(m-2)x+25=0) has equal roots, what are the values of (m)?

Explanation opens after your attempt
Correct Answer

A. (12) और (-8)(12) and (-8)

Step 1

Concept

For equal roots, ((m-2)2-100=0). Thus \(m-2=\pm10\), so (m=12) or (m=-8).

Step 2

Why this answer is correct

The correct answer is A. (12) और (-8) / (12) and (-8). For equal roots, ((m-2)2-100=0). Thus \(m-2=\pm10\), so (m=12) or (m=-8).

Step 3

Exam Tip

समान जड़ों के लिए ((m-2)2-100=0) होगा। इसलिए \(m-2=\pm10\), अतः (m=12) या (m=-8)।

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Question 2/4 Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि (x-2+(m+1)x+16=0) की जड़ें समान हैं, तो (m) के मान क्या हैं?

If (x-2+(m+1)x+16=0) has equal roots, what are the values of (m)?

Explanation opens after your attempt
Correct Answer

A. (7) और (-9)(7) and (-9)

Step 1

Concept

For equal roots, ((m+1)2-64=0). Thus \(m+1=\pm8\), so (m=7) or (m=-9).

Step 2

Why this answer is correct

The correct answer is A. (7) और (-9) / (7) and (-9). For equal roots, ((m+1)2-64=0). Thus \(m+1=\pm8\), so (m=7) or (m=-9).

Step 3

Exam Tip

समान जड़ों के लिए ((m+1)2-64=0) होगा। इसलिए \(m+1=\pm8\), अतः (m=7) या (m=-9)।

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Question 3/4 Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि (x-2+(m-5)x+9=0) की जड़ें बराबर पर विपरीत चिह्न वाली नहीं हैं और समान हैं, तो (m) के मान क्या हैं?

If (x-2+(m-5)x+9=0) has equal roots that are not of opposite signs, what are the values of (m)?

Explanation opens after your attempt
Correct Answer

A. (11) और (-1)(11) and (-1)

Step 1

Concept

For equal roots, ((m-5)2-36=0). Thus \(m-5=\pm6\), so (m=11) or (m=-1).

Step 2

Why this answer is correct

The correct answer is A. (11) और (-1) / (11) and (-1). For equal roots, ((m-5)2-36=0). Thus \(m-5=\pm6\), so (m=11) or (m=-1).

Step 3

Exam Tip

समान जड़ों के लिए ((m-5)2-36=0) होगा। इसलिए \(m-5=\pm6\), अतः (m=11) या (m=-1)।

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Question 4/4 Hard Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

(x-2+2(k-1)x+k+5=0) की जड़ें समान हों, तो (k) के मान कौन-से हैं?

If (x-2+2(k-1)x+k+5=0) has equal roots, what are the values of (k)?

Explanation opens after your attempt
Correct Answer

A. (4) और (-1)(4) and (-1)

Step 1

Concept

For equal roots, put (D=0). This gives \(k^2-3k-4=0\), so (k=4) or (k=-1).

Step 2

Why this answer is correct

The correct answer is A. (4) और (-1) / (4) and (-1). For equal roots, put (D=0). This gives \(k^2-3k-4=0\), so (k=4) or (k=-1).

Step 3

Exam Tip

समान जड़ों के लिए (D=0) रखें। इससे \(k^2-3k-4=0\) मिलता है, इसलिए (k=4) या (k=-1)।

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