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5 results found for "ratio-expression" in Class 10.

Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 33

यदि \(x^2-13x+36=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) का मान क्या है?

If \(\alpha,\beta\) are the roots of \(x^2-13x+36=0\), what is \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{97}{36}\)

Step 1

Concept

We use \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\). Here \(\alpha^2+\beta^2=169-72=97\) and \(\alpha\beta=36\), so the value is \(\frac{97}{36}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{97}{36}\). We use \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\). Here \(\alpha^2+\beta^2=169-72=97\) and \(\alpha\beta=36\), so the value is \(\frac{97}{36}\).

Step 3

Exam Tip

\(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\) है। यहाँ \(\alpha^2+\beta^2=169-72=97\) और \(\alpha\beta=36\), इसलिए मान \(\frac{97}{36}\) है।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

यदि \(x^2-11x+24=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) का मान क्या है?

If \(\alpha,\beta\) are the roots of \(x^2-11x+24=0\), what is \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\)?

Explanation opens after your attempt
Correct Answer

C. \(\frac{73}{24}\)

Step 1

Concept

We use \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\). Here \(\alpha^2+\beta^2=73\) and \(\alpha\beta=24\), so the value is \(\frac{73}{24}\).

Step 2

Why this answer is correct

The correct answer is C. \(\frac{73}{24}\). We use \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\). Here \(\alpha^2+\beta^2=73\) and \(\alpha\beta=24\), so the value is \(\frac{73}{24}\).

Step 3

Exam Tip

\(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\) है। यहाँ \(\alpha^2+\beta^2=73\) और \(\alpha\beta=24\), इसलिए मान \(\frac{73}{24}\) है।

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Question Expert Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

यदि \(x^2-9x+18=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) का मान क्या है?

If \(\alpha,\beta\) are the roots of \(x^2-9x+18=0\), what is \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{5}{2}\)

Step 1

Concept

We use \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\). Here \(\alpha^2+\beta^2=45\) and \(\alpha\beta=18\), so the value is \(\frac{5}{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{5}{2}\). We use \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\). Here \(\alpha^2+\beta^2=45\) and \(\alpha\beta=18\), so the value is \(\frac{5}{2}\).

Step 3

Exam Tip

\(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\) है। यहाँ \(\alpha^2+\beta^2=45\) और \(\alpha\beta=18\), इसलिए मान \(\frac{5}{2}\) है।

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Question Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 30

यदि \(3x^2-11x+6=0\) के मूल \(\alpha,\beta\) हैं, तो \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(3x^2-11x+6=0\), what is the value of \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\)?

Explanation opens after your attempt
Correct Answer

A. \( \frac{85}{18} \)

Step 1

Concept

We use \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\). Here \(\alpha+\beta=\frac{11}{3}\) and \(\alpha\beta=2\), so the value is \(\frac{85}{18}\).

Step 2

Why this answer is correct

The correct answer is A. \( \frac{85}{18} \). We use \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\). Here \(\alpha+\beta=\frac{11}{3}\) and \(\alpha\beta=2\), so the value is \(\frac{85}{18}\).

Step 3

Exam Tip

\(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\) होता है। यहाँ \(\alpha+\beta=\frac{11}{3}\) और \(\alpha\beta=2\), इसलिए मान \(\frac{85}{18}\) है।

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Question Expert Mathematics Quadratic Equations Introduction to Quadratic Equations Class 10 Level 29

यदि \(2x^2-7x+3=0\) के मूल \(\alpha,\beta\) हैं, तो \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\) का मान क्या है?

If \(\alpha,\beta\) are roots of \(2x^2-7x+3=0\), what is the value of \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}\)?

Explanation opens after your attempt
Correct Answer

A. \( \frac{37}{6} \)

Step 1

Concept

We use \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\). Here \(\alpha+\beta=\frac{7}{2}\) and \(\alpha\beta=\frac{3}{2}\), so the value is \(\frac{37}{6}\).

Step 2

Why this answer is correct

The correct answer is A. \( \frac{37}{6} \). We use \(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\). Here \(\alpha+\beta=\frac{7}{2}\) and \(\alpha\beta=\frac{3}{2}\), so the value is \(\frac{37}{6}\).

Step 3

Exam Tip

\(\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{\alpha^2+\beta^2}{\alpha\beta}\) होता है। यहाँ \(\alpha+\beta=\frac{7}{2}\) और \(\alpha\beta=\frac{3}{2}\), इसलिए मान \(\frac{37}{6}\) है।

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