Concept-wise Practice

infinite solutions MCQ Questions for Class 10

infinite solutions se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

61 questions tagged with infinite solutions.

Question 1/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि (7x+3y=42) और (21x+9y=k) की रेखाएं संपाती हों, तो (k) का मान क्या होगा?

If the lines (7x+3y=42) and (21x+9y=k) are coincident, what will be the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (126)

Step 1

Concept

The second equation must be (3) times the first, so (k=126). In coincident lines, the constant term also changes in the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (126). The second equation must be (3) times the first, so (k=126). In coincident lines, the constant term also changes in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना होना चाहिए, इसलिए (k=126)। संपाती रेखाओं में स्थिर पद भी उसी अनुपात में बदलता है।

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Question 2/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (15x+20y=60) और (3x+4y=12) किस प्रकार की हैं?

What type of lines are (15x+20y=60) and (3x+4y=12)?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

The first equation is (5) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. The first equation is (5) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 3

Exam Tip

पहला समीकरण दूसरे का (5) गुना है। इसलिए दोनों रेखाएं संपाती हैं और अनंत समाधान देती हैं।

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Question 3/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि (3x+ky=21) और (12x+20y=84) अनंत समाधान देते हैं, तो (k) का मान क्या है?

If (3x+ky=21) and (12x+20y=84) give infinitely many solutions, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The second equation is (4) times the first, so (4k=20) and (k=5). For infinite solutions, the lines must be coincident.

Step 2

Why this answer is correct

The correct answer is C. (5). The second equation is (4) times the first, so (4k=20) and (k=5). For infinite solutions, the lines must be coincident.

Step 3

Exam Tip

दूसरा समीकरण पहले का (4) गुना है, इसलिए (4k=20) और (k=5)। अनंत समाधान के लिए रेखाएं संपाती होनी चाहिए।

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Question 4/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि (ax+12y=48) और (5x+3y=12) संपाती रेखाएं हैं, तो (a) का मान क्या है?

If (ax+12y=48) and (5x+3y=12) are coincident lines, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (20)

Step 1

Concept

The first equation must be (4) times the second, so (a=20). In coincident lines, all terms change by the same multiplier.

Step 2

Why this answer is correct

The correct answer is C. (20). The first equation must be (4) times the second, so (a=20). In coincident lines, all terms change by the same multiplier.

Step 3

Exam Tip

पहला समीकरण दूसरे का (4) गुना होना चाहिए, इसलिए (a=20)। संपाती रेखाओं में सभी पद समान गुणक से बदलते हैं।

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Question 5/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि (5x+4y=p) और (15x+12y=96) की रेखाएं अनंत समाधान देती हैं, तो (p) क्या है?

If (5x+4y=p) and (15x+12y=96) give infinitely many solutions, what is (p)?

Explanation opens after your attempt
Correct Answer

C. (32)

Step 1

Concept

For infinitely many solutions, the second equation must be (3) times the first. Therefore (3p=96) and (p=32).

Step 2

Why this answer is correct

The correct answer is C. (32). For infinitely many solutions, the second equation must be (3) times the first. Therefore (3p=96) and (p=32).

Step 3

Exam Tip

अनंत समाधान के लिए दूसरा समीकरण पहले का (3) गुना होना चाहिए। इसलिए (3p=96) और (p=32)।

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Question 6/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), तो ग्राफ में रेखाओं की स्थिति क्या होगी?

If \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), what will be the position of the lines on a graph?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

If all three ratios are equal, both equations represent the same line. Hence the lines are coincident and give infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. If all three ratios are equal, both equations represent the same line. Hence the lines are coincident and give infinitely many solutions.

Step 3

Exam Tip

तीनों अनुपात बराबर हों तो दोनों समीकरण एक ही रेखा बताते हैं। इसलिए रेखाएं संपाती होती हैं और अनंत समाधान देती हैं।

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Question 7/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (11x-6y=33) और (22x-12y=66) ग्राफ पर क्या दर्शाती हैं?

What do the lines (11x-6y=33) and (22x-12y=66) represent on a graph?

Explanation opens after your attempt
Correct Answer

C. अनंत समाधानInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत समाधान / Infinitely many solutions. The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों रेखाएं एक ही हैं। एक ही रेखा के सभी बिंदु समाधान होते हैं।

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Question 8/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

यदि (6x+ky=30) और (18x+15y=90) संपाती रेखाएं हों, तो (k) का मान क्या है?

If (6x+ky=30) and (18x+15y=90) are coincident lines, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (5)

Step 1

Concept

The second equation is (3) times the first, so (3k=15) and (k=5). In coincident lines, all terms are in the same ratio.

Step 2

Why this answer is correct

The correct answer is C. (5). The second equation is (3) times the first, so (3k=15) and (k=5). In coincident lines, all terms are in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3k=15) और (k=5)। संपाती रेखाओं में सभी पद समान अनुपात में होते हैं।

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Question 9/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

रेखाएं (12x+15y=30) और (4x+5y=10) किस प्रकार की हैं?

What type of lines are (12x+15y=30) and (4x+5y=10)?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

The first equation is (3) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. The first equation is (3) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 3

Exam Tip

पहला समीकरण दूसरे का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं और अनंत समाधान देती हैं।

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Question 10/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

यदि (2x+ky=18) और (6x+12y=54) अनंत समाधान देते हैं, तो (k) का मान क्या है?

If (2x+ky=18) and (6x+12y=54) give infinitely many solutions, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The second equation is (3) times the first, so (3k=12) and (k=4). For infinite solutions, the lines must be coincident.

Step 2

Why this answer is correct

The correct answer is C. (4). The second equation is (3) times the first, so (3k=12) and (k=4). For infinite solutions, the lines must be coincident.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3k=12) और (k=4)। अनंत समाधान के लिए रेखाएं संपाती होनी चाहिए।

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Question 11/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

यदि (ax+9y=27) और (4x+3y=9) संपाती रेखाएं हैं, तो (a) का मान क्या है?

If (ax+9y=27) and (4x+3y=9) are coincident lines, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (12)

Step 1

Concept

The first equation must be (3) times the second, so (a=12). In coincident lines, all terms change by the same multiplier.

Step 2

Why this answer is correct

The correct answer is C. (12). The first equation must be (3) times the second, so (a=12). In coincident lines, all terms change by the same multiplier.

Step 3

Exam Tip

पहला समीकरण दूसरे का (3) गुना होना चाहिए, इसलिए (a=12)। संपाती रेखाओं में सभी पद समान गुणक से बदलते हैं।

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Question 12/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

यदि (4x+3y=p) और (8x+6y=42) की रेखाएं अनंत समाधान देती हैं, तो (p) क्या है?

If (4x+3y=p) and (8x+6y=42) give infinitely many solutions, what is (p)?

Explanation opens after your attempt
Correct Answer

C. (21)

Step 1

Concept

For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=42) and (p=21).

Step 2

Why this answer is correct

The correct answer is C. (21). For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=42) and (p=21).

Step 3

Exam Tip

अनंत समाधान के लिए दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (2p=42) और (p=21)।

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Question 13/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

रेखाएं (8x-5y=24) और (16x-10y=48) ग्राफ पर क्या दर्शाती हैं?

What do the lines (8x-5y=24) and (16x-10y=48) represent on a graph?

Explanation opens after your attempt
Correct Answer

C. अनंत समाधानInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत समाधान / Infinitely many solutions. The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों रेखाएं एक ही हैं। एक ही रेखा के सभी बिंदु समाधान होते हैं।

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Question 14/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

यदि (5x+ky=20) और (15x+6y=60) संपाती रेखाएं हों, तो (k) का मान क्या है?

If (5x+ky=20) and (15x+6y=60) are coincident lines, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

The second equation is (3) times the first, so (3k=6) and (k=2). In coincident lines, all terms are in the same ratio.

Step 2

Why this answer is correct

The correct answer is B. (2). The second equation is (3) times the first, so (3k=6) and (k=2). In coincident lines, all terms are in the same ratio.

Step 3

Exam Tip

दूसरा समीकरण पहले का (3) गुना है, इसलिए (3k=6) और (k=2)। संपाती रेखाओं में सभी पद समान अनुपात में होते हैं।

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Question 15/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

रेखाएं (9x-6y=21) और (3x-2y=7) किस प्रकार की हैं?

What type of lines are (9x-6y=21) and (3x-2y=7)?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

The first equation is (3) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. The first equation is (3) times the second. Therefore the lines are coincident and give infinitely many solutions.

Step 3

Exam Tip

पहला समीकरण दूसरे का (3) गुना है। इसलिए दोनों रेखाएं संपाती हैं और अनंत समाधान देती हैं।

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Question 16/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

यदि (x+ky=8) और (2x+6y=16) अनंत समाधान देते हैं, तो (k) का मान क्या है?

If (x+ky=8) and (2x+6y=16) give infinitely many solutions, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

The second equation is (2) times the first, so (2k=6) and (k=3). For infinite solutions, the lines must be coincident.

Step 2

Why this answer is correct

The correct answer is B. (3). The second equation is (2) times the first, so (2k=6) and (k=3). For infinite solutions, the lines must be coincident.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए (2k=6) और (k=3)। अनंत समाधान के लिए रेखाएं संपाती होनी चाहिए।

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Question 17/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

यदि (ax+6y=18) और (2x+3y=9) संपाती रेखाएं हैं, तो (a) का मान क्या है?

If (ax+6y=18) and (2x+3y=9) are coincident lines, what is the value of (a)?

Explanation opens after your attempt
Correct Answer

C. (4)

Step 1

Concept

The first equation must be (2) times the second, so (a=4). In coincident lines, all terms change by the same multiplier.

Step 2

Why this answer is correct

The correct answer is C. (4). The first equation must be (2) times the second, so (a=4). In coincident lines, all terms change by the same multiplier.

Step 3

Exam Tip

पहला समीकरण दूसरे का (2) गुना होना चाहिए, इसलिए (a=4)। संपाती रेखाओं में सभी पद समान गुणक से बदलते हैं।

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Question 18/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

यदि (3x+2y=p) और (6x+4y=20) की रेखाएं अनंत समाधान देती हैं, तो (p) क्या है?

If (3x+2y=p) and (6x+4y=20) give infinitely many solutions, what is (p)?

Explanation opens after your attempt
Correct Answer

B. (10)

Step 1

Concept

For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=20) and (p=10).

Step 2

Why this answer is correct

The correct answer is B. (10). For infinitely many solutions, the second equation must be (2) times the first. Therefore (2p=20) and (p=10).

Step 3

Exam Tip

अनंत समाधान के लिए दूसरा समीकरण पहले का (2) गुना होना चाहिए। इसलिए (2p=20) और (p=10)।

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Question 19/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

किस युग्म का ग्राफ संगत और आश्रित युग्म दिखाता है?

Which pair shows a consistent and dependent pair on the graph?

Explanation opens after your attempt
Correct Answer

A. (2x-y=7), (4x-2y=14)

Step 1

Concept

The second equation is (2) times the first, so the lines are coincident. Coincident lines give a consistent and dependent pair.

Step 2

Why this answer is correct

The correct answer is A. (2x-y=7), (4x-2y=14). The second equation is (2) times the first, so the lines are coincident. Coincident lines give a consistent and dependent pair.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए रेखाएं संपाती हैं। संपाती रेखाएं संगत और आश्रित युग्म देती हैं।

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Question 20/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

रेखाएं (7x+2y=18) और (14x+4y=36) ग्राफ पर क्या दर्शाती हैं?

What do the lines (7x+2y=18) and (14x+4y=36) represent on a graph?

Explanation opens after your attempt
Correct Answer

C. अनंत समाधानInfinitely many solutions

Step 1

Concept

The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 2

Why this answer is correct

The correct answer is C. अनंत समाधान / Infinitely many solutions. The second equation is (2) times the first, so both lines are the same. All points on the same line are solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों रेखाएं एक ही हैं। एक ही रेखा के सभी बिंदु समाधान होते हैं।

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Question 21/61 Expert Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

यदि (kx+4y=12) और (6x+8y=24) की रेखाएं संपाती हैं, तो (k) का मान क्या होगा?

If the lines (kx+4y=12) and (6x+8y=24) are coincident, what is the value of (k)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

For coincident lines, \(\frac{k}{6}=\frac{4}{8}=\frac{12}{24}\), so (k=3). In coincidence, the whole equation stays in the same ratio.

Step 2

Why this answer is correct

The correct answer is B. (3). For coincident lines, \(\frac{k}{6}=\frac{4}{8}=\frac{12}{24}\), so (k=3). In coincidence, the whole equation stays in the same ratio.

Step 3

Exam Tip

संपाती रेखाओं के लिए \(\frac{k}{6}=\frac{4}{8}=\frac{12}{24}\), इसलिए (k=3)। संपाती स्थिति में पूरा समीकरण समान अनुपात में होता है।

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Question 22/61 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (2x+3y=13) और (4x+6y=26) को ग्राफ करने पर क्या मिलेगा?

What will be obtained by graphing (2x+3y=13) and (4x+6y=26)?

Explanation opens after your attempt
Correct Answer

C. अनंत समाधानInfinitely many solutions

Step 1

Concept

The second line is (2) times the first, so both are the same line. A same line has infinitely many solution points.

Step 2

Why this answer is correct

The correct answer is C. अनंत समाधान / Infinitely many solutions. The second line is (2) times the first, so both are the same line. A same line has infinitely many solution points.

Step 3

Exam Tip

दूसरी रेखा पहली की (2) गुनी है, इसलिए दोनों एक ही रेखा हैं। एक ही रेखा के अनंत बिंदु समाधान होते हैं।

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Question 23/61 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

किस स्थिति में दो रेखाओं का ग्राफ अनंत समाधान दिखाता है?

In which condition does the graph of two lines show infinitely many solutions?

Explanation opens after your attempt
Correct Answer

C. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\)

Step 1

Concept

Infinite solutions occur when both lines are the same line. For this, all three ratios are equal.

Step 2

Why this answer is correct

The correct answer is C. \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\). Infinite solutions occur when both lines are the same line. For this, all three ratios are equal.

Step 3

Exam Tip

अनंत समाधान तब होते हैं जब दोनों रेखाएं एक ही रेखा हों। इसके लिए तीनों अनुपात बराबर होते हैं।

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Question 24/61 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (2x-y=1) और (4x-2y=2) के ग्राफ से कितने समाधान मिलेंगे?

How many solutions will be obtained from the graphs of (2x-y=1) and (4x-2y=2)?

Explanation opens after your attempt
Correct Answer

D. अनंतInfinite

Step 1

Concept

The second equation is (2) times the first, so the lines are coincident. In coincident lines, every point is a solution.

Step 2

Why this answer is correct

The correct answer is D. अनंत / Infinite. The second equation is (2) times the first, so the lines are coincident. In coincident lines, every point is a solution.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए रेखाएं संपाती हैं। संपाती रेखाओं में हर बिंदु समाधान होता है।

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Question 25/61 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 54

रेखाएं (3x-2y=6) और (6x-4y=12) ग्राफ पर कैसी दिखेंगी?

How will the lines (3x-2y=6) and (6x-4y=12) appear on a graph?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

The second equation is (2) times the first, so both lines are the same. If one line overlaps the other, there are infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. The second equation is (2) times the first, so both lines are the same. If one line overlaps the other, there are infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए दोनों रेखाएं एक ही हैं। ग्राफ में एक ही रेखा दिखे तो अनंत समाधान होते हैं।

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Question 26/61 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

यदि \(a_1=7,\ b_1=14,\ c_1=21\) और \(a_2=1,\ b_2=2,\ c_2=3\), तो रेखाएँ कैसी होंगी?

If \(a_1=7,\ b_1=14,\ c_1=21\) and \(a_2=1,\ b_2=2,\ c_2=3\), how will the lines be?

Explanation opens after your attempt
Correct Answer

B. संपातीCoincident

Step 1

Concept

Here \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=7\). Therefore both lines will be coincident.

Step 2

Why this answer is correct

The correct answer is B. संपाती / Coincident. Here \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=7\). Therefore both lines will be coincident.

Step 3

Exam Tip

यहाँ \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=7\)। इसलिए दोनों रेखाएँ संपाती होंगी।

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Question 27/61 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 53

समीकरण (8x-12y=20) और (2x-3y=5) के ग्राफ कैसे होंगे?

How will the graphs of (8x-12y=20) and (2x-3y=5) be?

Explanation opens after your attempt
Correct Answer

C. संपातीCoincident

Step 1

Concept

Dividing the first equation by (4) gives (2x-3y=5). Therefore both are the same line and have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is C. संपाती / Coincident. Dividing the first equation by (4) gives (2x-3y=5). Therefore both are the same line and have infinitely many solutions.

Step 3

Exam Tip

पहला समीकरण (4) से भाग देने पर (2x-3y=5) बनता है। इसलिए दोनों एक ही रेखा हैं और अनंत हल हैं।

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Question 28/61 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

यदि \(a_1=5,\ b_1=10,\ c_1=15\) और \(a_2=1,\ b_2=2,\ c_2=3\), तो रेखाएँ कैसी होंगी?

If \(a_1=5,\ b_1=10,\ c_1=15\) and \(a_2=1,\ b_2=2,\ c_2=3\), how will the lines be?

Explanation opens after your attempt
Correct Answer

B. संपातीCoincident

Step 1

Concept

Here \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=5\). Therefore both lines will be coincident.

Step 2

Why this answer is correct

The correct answer is B. संपाती / Coincident. Here \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=5\). Therefore both lines will be coincident.

Step 3

Exam Tip

यहाँ \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}=5\)। इसलिए दोनों रेखाएँ संपाती होंगी।

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Question 29/61 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

एक विद्यार्थी (2x+3y=12) और (4x+6y=24) के लिए केवल एक हल लिखता है। गलती क्या है?

A student writes only one solution for (2x+3y=12) and (4x+6y=24). What is the mistake?

Explanation opens after your attempt
Correct Answer

B. संपाती रेखाओं को एक हल वाला माननाTreating coincident lines as having one solution

Step 1

Concept

The second equation is (2) times the first, so the lines are coincident. Coincident lines have infinitely many solutions.

Step 2

Why this answer is correct

The correct answer is B. संपाती रेखाओं को एक हल वाला मानना / Treating coincident lines as having one solution. The second equation is (2) times the first, so the lines are coincident. Coincident lines have infinitely many solutions.

Step 3

Exam Tip

दूसरा समीकरण पहले का (2) गुना है, इसलिए रेखाएँ संपाती हैं। संपाती रेखाओं के अनंत हल होते हैं।

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Question 30/61 Hard Mathematics Pair of Linear Equations in Two Variables Graphical method of finding solutions. Class 10 Level 52

यदि दो रेखाओं के लिए \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), तो कौन-सा निष्कर्ष सही है?

If for two lines \(\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\), which conclusion is correct?

Explanation opens after your attempt
Correct Answer

C. रेखाएँ संपाती हैंLines are coincident

Step 1

Concept

When all three ratios are equal, both equations represent the same line. Therefore there are infinitely many common points.

Step 2

Why this answer is correct

The correct answer is C. रेखाएँ संपाती हैं / Lines are coincident. When all three ratios are equal, both equations represent the same line. Therefore there are infinitely many common points.

Step 3

Exam Tip

तीनों अनुपात समान होने पर दोनों समीकरण एक ही रेखा दर्शाते हैं। इसलिए अनंत सामान्य बिंदु होते हैं।

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