If the roots of (3x^2+px+12=0) are in the ratio (1:4), what are the possible values of (p)?

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Answer and explanation

Correct answer: (15) or (-15)

Let the roots be (r) and (4r). Then (4r^2=4), so (r=\pm1); using (5r=-\frac{p}{3}), we get (p=\pm15).

What is the correct answer to this question?

(15) or (-15)

Why is this the correct answer?

Let the roots be (r) and (4r). Then (4r^2=4), so (r=\pm1); using (5r=-\frac{p}{3}), we get (p=\pm15).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Roots of a Quadratic Equation.

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