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If (p(x)=2x^2-5x-3), what is (\frac{\alpha}{\beta}+\frac{\beta}{\alpha}), where (\alpha,\beta) are zeroes?यदि (p(x)=2x^2-5x-3), तो (\frac{\alpha}{\beta}+\frac{\beta}{\alpha}) क्या है, जहाँ (\alpha,\beta) शून्यक हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: -(\frac{37}{6}) / (-\frac{37}{6})-(\frac{37}{6}) / (-\frac{37}{6})
(\alpha+\beta=\frac{5}{2}) and (\alpha\beta=-\frac{3}{2}). (\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{(\alpha+\beta)^2-2\alpha\beta}{\alpha\beta}=-\frac{37}{6}).(\alpha+\beta=\frac{5}{2}) और (\alpha\beta=-\frac{3}{2}) हैं। (\frac{\alpha}{\beta}+\frac{\beta}{\alpha}=\frac{(\alpha+\beta)^2-2\alpha\beta}{\alpha\beta}=-\frac{37}{6})।
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